a)$\left(\genfrac{}{}{0ex}{}{1}{2}+1,5\right)\cdot x=\genfrac{}{}{0ex}{}{1}{5}$

$2\cdot x=\genfrac{}{}{0ex}{}{1}{5}$

$x=\genfrac{}{}{0ex}{}{1}{5}:2$

$x=\genfrac{}{}{0ex}{}{1}{10}$
b) $\left(-1\genfrac{}{}{0ex}{}{3}{5}+x\right):\genfrac{}{}{0ex}{}{12}{13}=2\genfrac{}{}{0ex}{}{1}{6}$

$-1\genfrac{}{}{0ex}{}{3}{5}+x=\genfrac{}{}{0ex}{}{13}{6}\cdot \genfrac{}{}{0ex}{}{12}{13}$
$x=2+1\genfrac{}{}{0ex}{}{3}{5}$

$x=3\genfrac{}{}{0ex}{}{3}{5}$
c) $\left(x:2\genfrac{}{}{0ex}{}{1}{3}\right)\cdot \genfrac{}{}{0ex}{}{1}{7}=\genfrac{}{}{0ex}{}{-3}{8}$

$x\cdot \genfrac{}{}{0ex}{}{3}{7}\cdot \genfrac{}{}{0ex}{}{1}{7}=\genfrac{}{}{0ex}{}{-3}{8}$

$x=\genfrac{}{}{0ex}{}{-3}{8}:\genfrac{}{}{0ex}{}{3}{49}$
$x=\genfrac{}{}{0ex}{}{-49}{8}=-6\genfrac{}{}{0ex}{}{1}{8}$
d) $\genfrac{}{}{0ex}{}{-4}{7}\cdot x+\genfrac{}{}{0ex}{}{7}{5}=\genfrac{}{}{0ex}{}{1}{8}:\left(-1\genfrac{}{}{0ex}{}{2}{3}\right)$

$\genfrac{}{}{0ex}{}{-4}{7}x+\genfrac{}{}{0ex}{}{7}{5}=\genfrac{}{}{0ex}{}{1}{8}\cdot \genfrac{}{}{0ex}{}{-3}{5}$
$-\genfrac{}{}{0ex}{}{4}{7}x=\genfrac{}{}{0ex}{}{-3}{40}-\genfrac{}{}{0ex}{}{7}{5}x=\genfrac{}{}{0ex}{}{-59}{40}:\genfrac{}{}{0ex}{}{-4}{7}=\genfrac{}{}{0ex}{}{413}{160}=2\genfrac{}{}{0ex}{}{93}{160}$
 

a) $x+\genfrac{}{}{0ex}{}{1}{3}=\genfrac{}{}{0ex}{}{1}{2}-\genfrac{}{}{0ex}{}{5}{6}$

$x=-\genfrac{}{}{0ex}{}{1}{3}-\genfrac{}{}{0ex}{}{1}{3}$

$x=-\genfrac{}{}{0ex}{}{2}{3}$;
b) $\genfrac{}{}{0ex}{}{3}{8}+\genfrac{}{}{0ex}{}{5}{8}-\genfrac{}{}{0ex}{}{1}{5}-x=\genfrac{}{}{0ex}{}{1}{5}$

$x=1-\genfrac{}{}{0ex}{}{1}{5}-\genfrac{}{}{0ex}{}{1}{5}$

$x=\genfrac{}{}{0ex}{}{3}{5}$.

a) $x=7-\genfrac{}{}{0ex}{}{2}{5}+1,62=8,22$
b) $x=4\genfrac{}{}{0ex}{}{3}{5}+\genfrac{}{}{0ex}{}{1}{5}-\genfrac{}{}{0ex}{}{1}{2}=4\genfrac{}{}{0ex}{}{3}{10}$
c) $2x-x=\genfrac{}{}{0ex}{}{3}{5}+\genfrac{}{}{0ex}{}{4}{7}$
$x=\genfrac{}{}{0ex}{}{41}{35}$
d) $x=3\genfrac{}{}{0ex}{}{1}{2}-\genfrac{}{}{0ex}{}{5}{7}+\genfrac{}{}{0ex}{}{1}{13}-0.25$
$x=2\genfrac{}{}{0ex}{}{223}{364}$

 

a) $A=\left(\genfrac{}{}{0ex}{}{1}{3}+\genfrac{}{}{0ex}{}{2}{3}\right)-\left(\genfrac{}{}{0ex}{}{8}{15}+\genfrac{}{}{0ex}{}{7}{15}\right)+\left(\genfrac{}{}{0ex}{}{-1}{7}+1\genfrac{}{}{0ex}{}{1}{7}\right)=1-1+1=1$;
b) $\mathrm{B}=\left(0.25-1\genfrac{}{}{0ex}{}{1}{4}\right)+\left(\genfrac{}{}{0ex}{}{3}{5}+\genfrac{}{}{0ex}{}{2}{5}\right)-\genfrac{}{}{0ex}{}{1}{8}$
$=\left(\genfrac{}{}{0ex}{}{1}{4}-1-\genfrac{}{}{0ex}{}{1}{4}\right)+1-\genfrac{}{}{0ex}{}{1}{8}=\genfrac{}{}{0ex}{}{-1}{8}$.

a) $\mathrm{A}=\left[\genfrac{}{}{0ex}{}{2}{7}\left(\genfrac{}{}{0ex}{}{1}{4}-\genfrac{}{}{0ex}{}{1}{3}\right)\right]:\left[\genfrac{}{}{0ex}{}{2}{7}\left(\genfrac{}{}{0ex}{}{1}{3}-\genfrac{}{}{0ex}{}{2}{5}\right)\right]=\left(\genfrac{}{}{0ex}{}{1}{4}-\genfrac{}{}{0ex}{}{1}{3}\right):\left(\genfrac{}{}{0ex}{}{1}{3}-\genfrac{}{}{0ex}{}{2}{5}\right)=1\genfrac{}{}{0ex}{}{1}{4}$.
b) $\mathrm{B}=\genfrac{}{}{0ex}{}{\genfrac{}{}{0ex}{}{3}{4}\left(\genfrac{}{}{0ex}{}{1}{5}-\genfrac{}{}{0ex}{}{2}{7}-\genfrac{}{}{0ex}{}{1}{3}+\genfrac{}{}{0ex}{}{2}{7}\right)}{\genfrac{}{}{0ex}{}{1}{5}\left(\genfrac{}{}{0ex}{}{2}{7}+\genfrac{}{}{0ex}{}{1}{3}\right)-\genfrac{}{}{0ex}{}{1}{3}\left(\genfrac{}{}{0ex}{}{2}{7}+\genfrac{}{}{0ex}{}{1}{3}\right)}=\genfrac{}{}{0ex}{}{\genfrac{}{}{0ex}{}{3}{4}\left(\genfrac{}{}{0ex}{}{1}{5}-\genfrac{}{}{0ex}{}{1}{3}\right)}{\left(\genfrac{}{}{0ex}{}{1}{5}-\genfrac{}{}{0ex}{}{1}{3}\right)\left(\genfrac{}{}{0ex}{}{2}{7}+\genfrac{}{}{0ex}{}{1}{3}\right)}=1\genfrac{}{}{0ex}{}{11}{52}$

a) $\mathrm{A}=\genfrac{}{}{0ex}{}{3}{5}.\genfrac{}{}{0ex}{}{6}{7}+\genfrac{}{}{0ex}{}{3}{7}.\genfrac{}{}{0ex}{}{3}{5}-\genfrac{}{}{0ex}{}{2}{7}.\genfrac{}{}{0ex}{}{3}{5}$

b) $\mathrm{B}=\left(-13\cdot \genfrac{}{}{0ex}{}{2}{5}+\genfrac{}{}{0ex}{}{-2}{9}\cdot \genfrac{}{}{0ex}{}{2}{5}+\genfrac{}{}{0ex}{}{2}{5}\cdot \genfrac{}{}{0ex}{}{11}{9}\right)\cdot \genfrac{}{}{0ex}{}{5}{2}$
$=\left(-13-\genfrac{}{}{0ex}{}{2}{9}+\genfrac{}{}{0ex}{}{11}{9}\right)\cdot \genfrac{}{}{0ex}{}{2}{5}\cdot \genfrac{}{}{0ex}{}{5}{2}=-13+\left(\genfrac{}{}{0ex}{}{11}{9}-\genfrac{}{}{0ex}{}{2}{9}\right)=-12.$
c) $\mathrm{C}=\left(\genfrac{}{}{0ex}{}{-4}{5}+\genfrac{}{}{0ex}{}{5}{7}\right)\cdot \genfrac{}{}{0ex}{}{3}{2}+\left(\genfrac{}{}{0ex}{}{-1}{5}+\genfrac{}{}{0ex}{}{2}{7}\right)\cdot \genfrac{}{}{0ex}{}{3}{2}=\left(\genfrac{}{}{0ex}{}{-4}{5}+\genfrac{}{}{0ex}{}{5}{7}+\genfrac{}{}{0ex}{}{-1}{5}+\genfrac{}{}{0ex}{}{2}{7}\right)\cdot \genfrac{}{}{0ex}{}{3}{2}=\left(\left(\genfrac{}{}{0ex}{}{-4}{5}+\genfrac{}{}{0ex}{}{-1}{5}\right)+\left(\genfrac{}{}{0ex}{}{5}{7}+\genfrac{}{}{0ex}{}{2}{7}\right)\right)\cdot \genfrac{}{}{0ex}{}{3}{2}=0.$
d) $\mathrm{D}=\genfrac{}{}{0ex}{}{4}{9}:\left(\genfrac{}{}{0ex}{}{1}{15}-\genfrac{}{}{0ex}{}{10}{15}\right)+\genfrac{}{}{0ex}{}{4}{9}:\left(\genfrac{}{}{0ex}{}{2}{22}-\genfrac{}{}{0ex}{}{5}{22}\right)$

$\mathrm{a)\; P}=\frac{2}{3}+\frac{1}{4}+\frac{3}{5}-\frac{7}{45}+\frac{5}{9}+\frac{1}{12}+\frac{1}{35}$ 

    P $=\left(\frac{2}{3}+\frac{1}{4}+\frac{1}{12}\right)+\left(\frac{5}{9}-\frac{7}{45}\right)+\frac{3}{5}+\frac{1}{35}$

P =$1+\frac{4}{5}+\frac{3}{5}+\frac{1}{35}=2\frac{1}{35}$.

b)

$Q\; =\left(5-\frac{3}{4}+\frac{1}{5}\right)-\left(6+\frac{7}{4}-\frac{8}{5}\right)-\left(2-\frac{5}{4}+\frac{16}{5}\right)$

$Q=(5-6-2)+\left(-\frac{3}{4}-\frac{7}{4}+\frac{5}{4}\right)+(\frac{1}{5}-\frac{8}{5}-\frac{16}{5}$)

$Q\; =\; -\left(3+\frac{5}{4}+\frac{23}{5}\right)$ $=-(3+1\frac{1}{4}+4\frac{3}{5}$

$Q\; =-8\frac{17}{20}$.

a) $A=\left(\genfrac{}{}{0ex}{}{1}{3}-\genfrac{}{}{0ex}{}{8}{15}-\genfrac{}{}{0ex}{}{1}{7}\right)+\left(\genfrac{}{}{0ex}{}{2}{3}+\genfrac{}{}{0ex}{}{-7}{15}+1\genfrac{}{}{0ex}{}{1}{7}\right)$

$A=\genfrac{}{}{0ex}{}{1}{3}-\genfrac{}{}{0ex}{}{8}{15}-\genfrac{}{}{0ex}{}{1}{7}+\genfrac{}{}{0ex}{}{2}{3}+\genfrac{}{}{0ex}{}{-7}{15}+1+\genfrac{}{}{0ex}{}{1}{7}$

$A=\left(\genfrac{}{}{0ex}{}{1}{3}+\genfrac{}{}{0ex}{}{2}{3}\right)+\left(\genfrac{}{}{0ex}{}{-8}{15}+\genfrac{}{}{0ex}{}{-7}{15}\right)+\left(\genfrac{}{}{0ex}{}{-1}{7}+\genfrac{}{}{0ex}{}{1}{7}\right)+1$

$A=1+\left(-1\right)+0+1=\left(1-1\right)+1$

$A=1$

b) $B=0,25+\genfrac{}{}{0ex}{}{3}{5}-\left(\genfrac{}{}{0ex}{}{1}{8}-\genfrac{}{}{0ex}{}{2}{5}+1\genfrac{}{}{0ex}{}{1}{4}\right)$

$B=\genfrac{}{}{0ex}{}{1}{4}+\genfrac{}{}{0ex}{}{3}{5}-\genfrac{}{}{0ex}{}{1}{8}+\genfrac{}{}{0ex}{}{2}{5}-1-\genfrac{}{}{0ex}{}{1}{4}$

$B=\left(\genfrac{}{}{0ex}{}{1}{4}-\genfrac{}{}{0ex}{}{1}{4}\right)+\left(\genfrac{}{}{0ex}{}{3}{5}+\genfrac{}{}{0ex}{}{2}{5}\right)-1-\genfrac{}{}{0ex}{}{1}{8}$

$B=0+1-1-\genfrac{}{}{0ex}{}{1}{8}$

$B=-\genfrac{}{}{0ex}{}{1}{8}$