Bạn ghi lại đề cho rõ ràng nha

Đề yêu cầu rút gọn à bạn?

\(\dfrac{xyz+2y^2y}{y^2+1}=\dfrac{y.xz+2y^2.y}{y^2+1}=\dfrac{y\left(xz+2y^2\right)}{y^2+1}\)

Do tử và mẫu không có nhân tử chung nên phân thức đã tối giảm.

`2+1/[2+1/[2+1/[2+1/2]]]`

`=2+1/[2+1/[2+1/[4/2+1/2]]]`

`=2+1/[2+1/[2+1/[5/2]]]`

`=2+1/[2+1/[2+2/5]]`

`=2+1/[2+1/[10/5+2/5]]`

`=2+1/[2+1/[12/5]]`

`=2+1/[2+5/12]`

`=2+1/[24/12+5/12]`

`=2+1/[29/12]`

`=2+12/29`

`=58/29+12/29=70/29`

\(2+\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{2}}}}=2+\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{\dfrac{5}{2}}}}=2+\dfrac{1}{2+\dfrac{1}{2+\dfrac{2}{5}}}=2+\dfrac{1}{2+\dfrac{1}{\dfrac{12}{5}}}=2+\dfrac{1}{2+\dfrac{5}{12}}=2+\dfrac{1}{\dfrac{29}{12}}=2+\dfrac{12}{29}=\dfrac{70}{29}\)

\(\dfrac{2}{8.9}+\dfrac{2}{9.10}+...+\dfrac{2}{63.64}\)

\(=2.\left(\dfrac{1}{8.9}+\dfrac{1}{9.10}+...+\dfrac{1}{63.64}\right)\)

\(=2.\left(\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-....-\dfrac{1}{63}+\dfrac{1}{63}-\dfrac{1}{64}\right)\)

\(=2.\left(\dfrac{1}{8}-\dfrac{1}{64}\right)\)

\(=\dfrac{7}{32}\)

hông biết☹☹

\(-\left(x+11\right)=\left(3x+22\right)-\left(6+x\right)\)

\(\Rightarrow-x-11=3x+22-6-x\)

\(\Rightarrow-x-11=2x+16\)

\(\Rightarrow-x-2x=11+16\)

\(\Rightarrow-3x=27\)

\(\Rightarrow x=-9\)

\(-\left(-x+11-134\right)=199-\left(x-24\right)\)

\(\Rightarrow x-111+134=199-x+24\)

\(\Rightarrow x+23=233-x\)

\(\Rightarrow2x=200\)

\(\Rightarrow x=100\)

\(\left(x+3\right).2+x=\left(200-9x\right)-350\)

\(\Rightarrow2x+6+x=200-9x-350\)

\(\Rightarrow12x=-156\)

\(\Rightarrow x=-13\)

bnbbvvf cb'/

???

CÂU HỎI LÀ J Z

ko biết

`B = ( 1-3/4) xx ( 1-3/7) xx ( 1-3/10) xx (1- 3/13) xx (1-3/16) xx ( 1 - 3/18)`

`B = 1/4 xx 4/7 xx 7/10 xx 10/13 xx 13/16 xx 15/18`

`B = 1/4 xx 4/7 xx 7/10 xx 10/13 xx 13/16 xx 5/6`

`B = ( 1 xx 4 xx 7 xx10xx13xx5)/(4xx7xx10xx13xx16xx6)`

`B = (1xx5)/(16xx6)`

`B=  5/96`

Làm rõ đề được ko bạn ?

nói là chia mà

`x - 2275 : 35 = 2023 - 1732`

`x - 2275 : 35 = 291`

`x - 65 = 291`

`x = 291 + 65`

`x= 356`