Chuyển Phân số thành hỗn số
29/2 ; 15/4; 31/2; 29/3; 125/8; 36/27; 124/15; 96/3; 129/24; 78/13; 91/4; 115/8 giúp mình với!!
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\(A=\dfrac{1}{2\cdot6}+\dfrac{1}{3\cdot8}+...+\dfrac{1}{2023\cdot4048}\)
\(=\dfrac{2}{4\cdot6}+\dfrac{2}{6\cdot8}+...+\dfrac{2}{4046\cdot4048}\)
\(=\dfrac{1}{4}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{8}+...+\dfrac{1}{4046}-\dfrac{1}{4048}\)
\(=\dfrac{1}{4}-\dfrac{1}{4048}=\dfrac{1012-1}{4048}=\dfrac{1011}{4048}\)
\(A=\dfrac{1}{2\cdot6}+\dfrac{1}{3\cdot8}+\dfrac{1}{4\cdot10}+...+\dfrac{1}{2023\cdot4048}\)
\(=\dfrac{1}{2}\cdot\left(\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+...+\dfrac{1}{2023\cdot2024}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2023}-\dfrac{1}{2024}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{2024}\right)\)
\(=\dfrac{1}{2}\cdot\dfrac{1012-1}{2024}\)
\(=\dfrac{1011}{4048}\)
\(\left\{47-\left[736:\left(5-3\right)^4\right]\right\}.2021\)
\(=\left\{47-\left[736:2^4\right]\right\}.2021\)
\(=\left\{47-\left[736:16\right]\right\}.2021\)
\(=\left\{47-46\right\}.2021\)
\(=1.2021\)
\(=2021\)
\(\left\{47-\left[736:\left(5-3\right)^4\right]\right\}\cdot2021\)
\(=\left\{47-736:16\right\}\cdot2021\)
\(=\left(47-46\right)\cdot2021=2021\)
2(x-1)+3(x-2)=x-4
=> 2x-2+3x-6=x-4
=> 5x-8=x-4
=> 5x-x=8-4
=> 4x=4
=> x=4:4
=> x=1
Vậy: x=1
\(2\left(x-1\right)+3\left(x-2\right)=x-4\)
\(2x-2+3x-6=x-4\)
\(\left(2x+3x\right)-\left(2+6\right)=x-4\)
\(5x-8=x-4\)
\(5x-x=-4+8\)
\(4x=4\)
\(x=1\)
\(\left(7+x\right)-\left(21-13\right)=32\)
\(\left(7+x\right)-8=32\)
\(7+x=32+8\)
\(7+x=40\)
\(x=40-7\)
\(x=33\)
Vậy \(x=33\)
\(\left(7+x\right)-\left(21-13\right)=32\)
\(7+x-21+13=32\)
\(x+\left(7+13-21\right)=32\)
\(x-1=32\)
\(x=33\)
\(-11-\left(19-x\right)=50\)
\(-11-19+x=50\)
\(x-\left(11+19\right)=50\)
\(x-30=50\)
\(x=50+30\)
\(x=80\)
\(-11-\left(19-x\right)=50\Leftrightarrow19-x=-11-50=-61\Leftrightarrow x=19+61=80\)
\(\dfrac{29}{2}=\dfrac{28+1}{2}=14+\dfrac{1}{2}=14\dfrac{1}{2}\)
\(\dfrac{15}{4}=\dfrac{12+3}{4}=3+\dfrac{3}{4}=3\dfrac{3}{4}\)
\(\dfrac{31}{2}=\dfrac{30+1}{2}=15\dfrac{1}{2}\)
\(\dfrac{29}{3}=\dfrac{27+2}{3}=9\dfrac{2}{3}\)
\(\dfrac{125}{8}=\dfrac{120+5}{8}=15+\dfrac{5}{8}=15\dfrac{5}{8}\)
\(\dfrac{36}{27}=\dfrac{27+9}{27}=1+\dfrac{9}{27}=1\dfrac{9}{27}\)
\(\dfrac{124}{15}=\dfrac{120+4}{15}=8+\dfrac{4}{15}=8\dfrac{4}{15}\)
\(\dfrac{96}{3}=\dfrac{93+3}{3}=31\dfrac{3}{3}\)
\(\dfrac{129}{24}=\dfrac{120+9}{24}=5+\dfrac{9}{24}=5\dfrac{9}{24}\)
\(\dfrac{78}{13}=\dfrac{65+13}{13}=5+\dfrac{13}{13}=5\dfrac{13}{13}\)
\(\dfrac{91}{4}=\dfrac{88+3}{4}=22+\dfrac{3}{4}=22\dfrac{3}{4}\)
\(\dfrac{115}{8}=\dfrac{112+3}{8}=14+\dfrac{3}{8}=14\dfrac{3}{8}\)