\(\left(-0,25^{ }\right)^5\) : x = \(\left(-0,25^{ }\right)^3\)
                  x = \(\left(-0,25^{ }\right)^5\): \(\left(-0,25^{ }\right)^3\)
                  x = \(\left(-0,25^{ }\right)^{5-3}\)
                  x = \(\left(-0,25^{ }\right)^2\)
                  x = 0,0625

a) $\genfrac{}{}{0ex}{}{3}{4}+\genfrac{}{}{0ex}{}{9}{5}{\left(\genfrac{}{}{0ex}{}{3}{2}-\genfrac{}{}{0ex}{}{2}{3}\right)}^2=\genfrac{}{}{0ex}{}{3}{4}+\genfrac{}{}{0ex}{}{9}{5}{\left(\genfrac{}{}{0ex}{}{5}{6}\right)}^2=\genfrac{}{}{0ex}{}{3}{4}+\genfrac{}{}{0ex}{}{9}{5}\cdot \genfrac{}{}{0ex}{}{25}{36}=\genfrac{}{}{0ex}{}{3}{4}+\genfrac{}{}{0ex}{}{5}{4}=2$

b) $\genfrac{}{}{0ex}{}{-22}{25}+\left(\genfrac{}{}{0ex}{}{22}{7}-0,12\right)=\genfrac{}{}{0ex}{}{-22}{25}+\left(\genfrac{}{}{0ex}{}{22}{7}-\genfrac{}{}{0ex}{}{12}{100}\right)=\genfrac{}{}{0ex}{}{-88}{100}+\genfrac{}{}{0ex}{}{22}{7}+\genfrac{}{}{0ex}{}{-12}{100}=\left(\genfrac{}{}{0ex}{}{-88}{100}+\genfrac{}{}{0ex}{}{-12}{100}\right)+\genfrac{}{}{0ex}{}{22}{7}=-1+\genfrac{}{}{0ex}{}{22}{7}=\genfrac{}{}{0ex}{}{15}{7}$