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2023-09-15 20:54:12
n là số lẻ nên n=2k+1 ,k là số tự nhiên
n3=\(\left(2k+1\right)^3\)=8k3+12k2+6k+1=2(4k3+6k2+3k)+1
Do k là số tự nhiên nên 2(4k3+6k2+3k) là số chẵn, vậy 2(4k3+6k2+3k)+1 là số lẻ
Hay n3 là số lẻ
2022-09-06 21:35:08
50
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