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Nguyễn Duy Thái
Giới thiệu về bản thân
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12.[43-(6-x)]=384
6-x=43-384:12
6-x=11
x=6-11
x=-5
Vậy: x=-5
Ta có:\(\dfrac{201201}{202202}\)=\(\dfrac{201}{202}\);\(\dfrac{201201201}{202202202}\)=\(\dfrac{201}{202}\)
=>\(\dfrac{201}{202}\)=\(\dfrac{201}{202}\)
=> \(\dfrac{201201}{202202}\)=\(\dfrac{201201201}{202202202}\)
Vậy: \(\dfrac{201201}{202202}\)=\(\dfrac{201201201}{202202202}\)
(quá dễ)
b) \(\dfrac{3}{5}\)x - \(\dfrac{1}{3}\) = \(\dfrac{4}{3}\)
x = \(\dfrac{3}{5}\) : (\(\dfrac{4}{3}\) + \(\dfrac{1}{3}\))
x = \(\dfrac{9}{25}\)
Vậy: x = \(\dfrac{9}{25}\)
a) \(\dfrac{5}{8}\) + \(\dfrac{3}{8}\) :\(\dfrac{2}{3}\) = \(\dfrac{5}{8}\) + \(\dfrac{3}{8}\) .\(\dfrac{3}{2}\) = \(\dfrac{5}{8}\) + \(\dfrac{9}{16}\) = \(\dfrac{10}{16}\) + \(\dfrac{9}{16}\) = \(\dfrac{19}{16}\)
b) \(\dfrac{1}{72}\) .\(\dfrac{144}{23}\) + \(\dfrac{1}{46}\) = \(\dfrac{2}{23}\) + \(\dfrac{1}{46}\) = \(\dfrac{4}{46}\) + \(\dfrac{1}{46}\) = \(\dfrac{5}{46}\)