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Giới thiệu về bản thân
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I/hope/I/visit/ Ho Chi Minh/ City / one day/./
`= >` I hope I will Ho Chi Minh City in one day.
Bài 2 :
\(a,\left(x-2021\right).958=0\)
\(x-2021=0:958\)
\(x-2021=0\)
\(x=0+2021\)
\(x=2021\)
Vậy...
\(b,959.\left(x-7\right)=0\)
\(x-7=0:959\)
\(x-7=0\)
\(x=0+7\)
\(x=7\)
Vậy....
\(e,45.\left(91-x\right)=90\)
\(91-x=90:45\)
\(91-x=2\)
\(x=91-2\)
\(x=89\)
Vậy...
\(g,5x+73.21=73.26\)
\(5x+1533=1898\)
\(5x=1898-1533\)
\(5x=365\)
\(x=365:5\)
\(x=73\)
Vậy...
\(h,\left(x-12\right).105=525\)
\(x-12=525:105\)
\(x-12=5\)
\(x=5+12\)
\(x=17\)
Vậy...
\(i,47.\left(27-x\right)=47\)
\(27-x=47:47\)
\(27-x=1\)
\(x=27-1\)
\(x=26\)
Vậy ...
\(j,2x+69.2=69.4\)
\(2x+138=276\)
\(2x=276-138\)
\(2x=138\)
\(x=138:2\)
\(x=69\)
Vậy ...
\(l,\left(x-40\right).15=15.3\)
\(\left(x-40\right).15=45\)
\(x-40=45:15\)
\(x-40=3\)
\(x=3+40\)
\(x=43\)
Vậy...
Bài 1 :
\(i,25.\left(x-4\right)=0\)
\(x-4=0:25\)
\(x-4=0\)
\(x=0+4\)
\(x=4\)
Vậy .....
\(m,34.\left(2x-6\right)=0\)
\(2x-6=0:34\)
\(2x-6=0\)
\(2x=0+6\)
\(2x=6\)
\(x=6:2\)
\(x=3\)
Vậy ....
\(n,2023.\left(3x-12\right)=0\)
\(3x-12=0:2023\)
\(3x-12=0\)
\(3x=0+12\)
\(3x=12\)
\(x=12:3\)
\(x=4\)
Vậy...
\(o,47.\left(5x-15\right)=0\)
\(5x-15=0:47\)
\(5x-15=0\)
\(5x=0+15\)
\(5x=15\)
\(x=15:5\)
\(x=3\)
Vậy....
\(p,13.\left(4x-24\right)=0\)
\(4x-24=0:13\)
\(4x-24=0\)
\(4x=0+24\)
\(4x=24\)
\(x=24:4\)
\(x=6\)
Vậy...
\(s,2.\left(x-5\right)-17=25\)
\(2.\left(x-5\right)=25+17\)
\(2.\left(x-5\right)=42\)
\(x-5=42:2\)
\(x-5=21\)
\(x=21+5\)
\(x=26\)
Vậy...
\(t,3.\left(x+7\right)-15=27\)
\(3.\left(x+7\right)=27+15\)
\(3.\left(x+7\right)=42\)
\(x+7=42:3\)
\(x+7=14\)
\(x=14-7\)
\(x=7\)
Vậy...
\(u,15+4.\left(x-2\right)=95\)
\(4.\left(x-2\right)=95-15\)
\(4.\left(x-2\right)=80\)
\(x-2=80:4\)
\(x-2=20\)
\(x=20+2\)
\(x=22\)
Vậy...
\(w,24+3.\left(5-x\right)=27\)
\(3.\left(5-x\right)=27-24\)
\(3.\left(x-5\right)=3\)
\(x-5=3:3\)
\(x-5=1\)
\(x=1+5\)
\(x=6\)
Vậy...
\(5^{x+3}-247=36^7:6^{11}+162\)
\(5^{x+3}-247=\left(6^2\right)^7:6^{11}+162\)
\(5^{x+3}-247=6^{14}:6^{11}+162\)
\(5^{x+3}-247=216+162\)
\(5^{x+3}-247=378\)
\(5^{x+3}=378+247\)
\(5^{x+3}=625\)
\(5^{x+3}=5^4\)
\(=>x+3=4\)
\(x\) \(=4-3\)
\(x\) \(=1\)
Vậy \(x=1\)
\(x+x\times\dfrac{1}{4}:\dfrac{2}{7}+x:\dfrac{2}{9}=255\)
\(x\times1+x\times\dfrac{1}{4}\times\dfrac{7}{2}+x\times\dfrac{9}{2}=255\)
\(x\times1+x\times\dfrac{7}{8}+x\times\dfrac{9}{2}=255\)
\(x\times\left(1+\dfrac{7}{8}+\dfrac{9}{2}\right)=255\)
\(x\times\dfrac{51}{8}=255\)
\(x=255:\dfrac{51}{8}\)
\(x=40\)
nose
\(2023+10-\left(2020+2022\right)-10\)
\(=\left(2023-2022\right)+\left(10-10\right)-2020\)
\(=1+0-2020\)
\(=-2019\)
tớ lộn
bán rồi thì phải bt bài này là lớp mấy chứ!
bán rồi thì bạn phải nhớ cách làm chứ!