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Vice Biche Amellian
Giới thiệu về bản thân
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=1 - (3 - 103) + (5 - 105) - (7 - 107)+...
=1 + 100 - 100 +100 - ...
=1
a) \(\dfrac{x}{3}=\dfrac{3}{2}\cdot\dfrac{1}{4}\)
\(\dfrac{x}{3}=\dfrac{3}{8}\)
\(x=\dfrac{3\cdot3}{8}\)
\(x=\dfrac{9}{8}\)
b) \(\dfrac{x}{5}=\dfrac{-1}{3}:\dfrac{7}{2}\)
\(\dfrac{x}{5}=\dfrac{-1}{3}\cdot\dfrac{2}{7}\)
\(\dfrac{x}{5}=\dfrac{-2}{21}\)
\(x=\dfrac{-2\cdot5}{21}\)
\(x=-\dfrac{10}{21}\)
c) \(x+\dfrac{2}{3}=\dfrac{4}{3}-\dfrac{1}{6}\)
\(\dfrac{6x}{6}+\dfrac{2\cdot2}{3\cdot2}=\dfrac{4\cdot2}{3\cdot2}-\dfrac{1}{6}\)
\(\dfrac{6x}{6}+\dfrac{4}{6}=\dfrac{8}{6}-\dfrac{1}{6}\)
\(\dfrac{6x+4}{6}=\dfrac{7}{6}\)
\(\dfrac{6x+4}{6}-\dfrac{7}{6}=0\)
\(\dfrac{6x+4-7}{6}=0\)
\(\dfrac{6x-3}{6}=0\)
\(6x-3=0\)
\(6x=3\)
\(x=\dfrac{3}{6}=\dfrac{1}{2}\)