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mong bạn chấp hành ko đăng lung tung lên diễn đàn
cái này mà toán lớp 10 tôi cũng lạy
nguyen vy oanh hình như cậu tính sai rồi
bài 2 :
a) 29 + 132 + 237 + 868 + 3
= 29 +(132 + 868)+(237 + 3)
= 29 + 1000 + 240
=1269
b) 35 . 34 + 35 . 86 + 65 . 75 + 65 . 5
= 35 .(34 + 86)+ 65 .(75 + 5)
= 35 . 120 + 65 . 80
= 4200 + 5200
= 9400
c) 3 . 25 . 8 + 4 . 37 . 6 + 2 . 38 .12
khum bít làm hehe
d) 12 . 53 + 53 . 172 - 53 . 84
= 53 . (12 + 172 - 84)
= 53 . 100
= 5300
Bài 3:
a) 4 . 52 - 18 : 32 hình như câu này sai đề
b) 32 . 22 - 32 . 19
= 32 . (22 - 19)
= 32 . 3
= 96
c) 24 . 5 - [131- (13 - 4)^2] = 24 . 5 - [131 - 9^2] = 24. 5 - [131 - 81] = 24 . 5 - 50 = 120 - 50 = 70 d) 5871: [928 – ( 247 - 82) . 5] + 21750 = 5871 : [928 - 165 . 5] + 21750 = 5871 : [928 - 825] + 21750 = 5871 : 103 + 21750 = 57 + 21750 = 21807a: Trên tia Ox, ta có: OA<OB
nên A nằm giữa O và B
=>OA+AB=OB
=>AB+2=6
=>AB=4(cm)
b: Vì OA<AB
nên A không là trung điểm của OB
c: I là trung điểm của AB
=>
Vì AO và AI là hai tia đối nhau
nên A nằm giữa I và O
=>OI=OA+IA=2+2=4(cm)
=>OI=AB(=4cm)
d: Đỉnh: O
Cạnh: OI;OK
câu D