![](https://rs.olm.vn/images/background/bg637535282119.jpg?v=2?1640073246)
![](https://rs.olm.vn/images/avt/3.png?131640073246)
Nguyễn Huy Tú
Giới thiệu về bản thân
Chào mừng bạn đến với trang cá nhân của Nguyễn Huy Tú
![](https://rs.olm.vn/images/medal_mam_non.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_win_1.png)
0
![](https://rs.olm.vn/images/medal_tan_binh.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_win_1.png)
0
![](https://rs.olm.vn/images/medal_chuyen_can.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_win_1.png)
0
![](https://rs.olm.vn/images/medal_cao_thu.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_win_1.png)
0
![](https://rs.olm.vn/images/medal_thong_thai.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_win_1.png)
0
![](https://rs.olm.vn/images/medal_kien_tuong.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_win_1.png)
0
![](https://rs.olm.vn/images/medal_dai_kien_tuong.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_ngoi_sao.png)
![](https://rs.olm.vn/images/medal_win_1.png)
0
2022-08-24 15:11:59
.
2022-08-24 10:40:07
Ta có \(\left(x+1,5\right)^2+\left(2,7-x\right)^{10}\ge0\)
mà \(\left(x+1,5\right)^8+\left(2,7-y\right)^{10}=0\)
Dấu ''='' xảy ra khi x = 1,5 ; y = 2,7
2022-08-24 10:36:14
\(=3x^5-2x^4+x^3+6x^3-4x^2+2x+9x^2-6x+3-3x^4-6x^2-4x^3+4x=3x^5-5x^4+3x^3-x^2+3\)
Vậy bth phụ thuộc vào biến x
2022-08-24 10:33:32
\(\dfrac{x^4-3x^3-3x^2+8x-5}{x-1}=\dfrac{x^3\left(x-1\right)-3x^2+3x+5x-5}{x-1}=\dfrac{x^3\left(x-1\right)-3x\left(x-1\right)+5\left(x-1\right)}{x-1}=x^3-3x+5\)
2022-08-24 10:32:12
Thay x = 1 vào ta được
\(1-m^2+m-7-3m^2+3m+6=0\Leftrightarrow-4m^2+4m=0\Leftrightarrow-4m\left(m-1\right)=0\Leftrightarrow m=0;m=1\)
2022-08-24 10:31:05
\(5.5\sqrt{a^2}-25a=25\left|a\right|-25a=-25a-25a=-50a\)
2022-08-24 10:28:59
.
2022-08-21 14:50:13
.
2022-08-21 14:50:04
.
2022-08-21 14:49:57