Ta có:

\(\dfrac{-1234}{1244}=-1+\dfrac{10}{1244}\)

\(\dfrac{-4321}{4331}=-1+\dfrac{10}{4331}\)

Vì \(\dfrac{10}{1244}>\dfrac{10}{4331}\)

\(\Rightarrow-1+\dfrac{10}{1244}>-1+\dfrac{10}{4331}\)

hay \(\dfrac{-1234}{1244}>\dfrac{-4321}{4331}\)

\(\dfrac{1234}{1244}< \dfrac{1234+3037}{1244+3037}=\dfrac{4331}{4321}\)

\(\Rightarrow\dfrac{1234}{1244}< \dfrac{4331}{4321}\)

\(\Rightarrow-\dfrac{1234}{1244}>-\dfrac{4331}{4321}\)

\(\Rightarrow\dfrac{-1234}{1244}>\dfrac{4331}{-4321}\)

\(\left(x^2+2\right)^2\)

\(=\left(x^2\right)^2+2\cdot x^2\cdot2+2^2\)

\(=x^4+4x^2+4\)

(x^2+2)^2= x^4++4x^2+4

Ta có:

• BM = MN = NC = 2 cm.
• BD = BC/2 = 3 cm.
• CE = BC/2 = 3 cm.

Do đó, I là trung điểm của BD và K là trung điểm của CE.

Ta có:

• IK = ID/2 = 1,5 cm.

Vậy IK = 1,5 cm.

(1+2y)/18=(1+6y)/6x=(1+2y+1+6y)/18+6x=(2+8y)/18+6x=(1+4y)/9+3x

=>(1+4y)/9+3x=(1+4y)/24 =>9+3x=24 =>3x=15 =>x=5

(1+2y)/18=(1+6y)/6x=(1+2y+1+6y)/18+6x=(2+8y)/18+6x=(1+4y)/9+3x

=>(1+4y)/9+3x=(1+4y)/24 =>9+3x=24 =>3x=15 =>x=5

Nhé bạn !

x=2

Điểm A nằm đâu thế bạn ?

\(\dfrac{1}{32}\) = 2^-5

\(\dfrac{1}{8}\) = 2^-3

0,5 = \(\dfrac{1}{2}\) = 2^-1

0,25 = \(\dfrac{1}{4}\) = 2^-2

\(\dfrac{1}{32}\) = 2^-5

\(\left(-27\right)^5:32^3\)

\(=\left[\left(-3\right)^3\right]^5:\left(2^5\right)^3\)

\(=\left(-3\right)^{15}:2^{15}\)

\(=\left(-3:2\right)^{15}\)

\(=\left(-\dfrac{3}{2}\right)^{15}\)

\(\left(-27\right)^5\):\(32^3\)

=-14348907:32768

=-437,8938904

Bài 1

1) -1/4 + 3/4 : 6

= -1/4 + 1/8

= -1/8

2) (-1/6 - 5/13 + 11/12) - (8/13 - 7/6 - 1/3)

= -1/6 - 5/13 + 11/12 - 8/13 + 7/6 + 1/3

= (-1/6 + 7/6) + (-5/13 - 8/13) + (11/12 + 1/3)

= 1 - 1 + 5/4

= 5/4

3) (-2/3)² . 3/5 + √(4/25) : 9/4 - 1,75

= 4/9 . 3/5 + 2/5 . 4/9 - 7/4

= 4/9 . (3/5 + 2/5) - 7/4

= 4/9 - 7/4

= -47/36

Bài 2

1) -1 2/5 - x = 2/3 - 4/5

-7/5 - x = -2/15

x = -7/5 + 2/15

x = -19/15

2) [√(9/64)+ x] - 1 1/2 = -3/4

3/8 + x - 3/2 = -3/4

x = -3/4 - 3/8 + 3/2

x = 3/8

3) 2.3ˣ⁺² + 4.3ˣ⁺¹ = 10.3⁶

3ˣ⁺¹.(2.3 + 4) = 10.3⁶

3ˣ⁺¹ . 10 = 3⁶ . 10

3ˣ⁺¹ = 3⁶

x + 1 = 6

x = 6 - 1

x = 5