Phân tích đa thức thành nhân tử1. 5x2 – 10xy + 5y2 – 20z2 2. 16x – 5x2 – 3 3. x2 – 5x + 5y – y2 4. 3x2 – 6xy + 3y2 – 12z25. x2 + 4x + 3 6. (x2 + 1)2 – 4x2 7. x2 – 4x –...
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Phân tích đa thức thành nhân tử
1. 5x2 – 10xy + 5y2 – 20z2 2. 16x – 5x2 – 3 3. x2 – 5x + 5y – y2 4. 3x2 – 6xy + 3y2 – 12z2
5. x2 + 4x + 3 6. (x2 + 1)2 – 4x2 7. x2 – 4x – 5
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Answer:
\(5x^2-10xy+5y^2-20z^2\)
\(=5.\left(x^2-2xy+y^2-4z^2\right)\)
\(=5.[\left(x+y\right)^2-\left(2z\right)^2]\)
\(=5.\left(x+y-2z\right).\left(x+y+2z\right)\)
\(16x-5x^2-3\)
\(=\left(-5x^2+15x\right)+\left(x-3\right)\)
\(=-5x.\left(x-3\right)+\left(x-3\right)\)
\(=\left(1-5x\right).\left(x-3\right)\)
\(x^2-5x+5y-y^2\)
\(=(x-y).(x+y)-5.(x-y)\)
\(=(x-y).(x+y-5)\)
\(3x^2-6xy+3y^2-12z^2\)
\(=3.(x^2-2xy+y^2-4z^2)\)
\(=3[\left(x-y\right)^2-\left(2z\right)^2]\)
\(=3.(x-y-2z).(x-y+2z)\)
\(x^2+4x+3\)
\(=(x^2+x)+(3x+3)\)
\(=x.(x+1)+3.(x+1)\)
\(=(x+1).(x+3)\)
\((x^2+1)^2-4x^2\)
\(=(x^2-2x+1).(x^2+2x+1)\)
\(=(x-1)^2.(x+1)^2\)
\(x^2-4x-5\)
\(=(x^2+x)-(5x+5)\)
\(=x.(x+1)-5.(x+1)\)
\(=(x-5).(x+1)\)