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6 tháng 8 2017

a,

\(\left(325-47\right)+\left(175-53\right)\\ =325-47+175-53\\ =325+175-47-53\\ =\left(325+175\right)-\left(47+53\right)\\ =500-100\\ =400\)

b,

\(\left(756-217\right)-\left(183-53\right)\\ =756-217-183+53\\ =756+53-217-183\\ =\left(756+53\right)-\left(217+183\right)\\ =809-400\\ =409\)

c,

\(\left(-5\right)\cdot6\cdot\left(-2\right)\cdot7\\ =\left[\left(-5\right)\cdot\left(-2\right)\right]\cdot\left(6\cdot7\right)\\ =10\cdot42\\ =420\)

d,

\(24\cdot36-\left(-24\right)\cdot64\\ =24\cdot36+24\cdot64\\ =24\cdot\left(36+64\right)\\ =24\cdot100\\ =2400\)

e,

\(24\cdot36-\left(-24\right)\cdot64\\ =24\cdot36+24\cdot64\\ =24\cdot\left(36+64\right)\\ =24\cdot100\\ =2400\)

6 tháng 8 2017

Bài 1: Tính:

a) (325+175) - (47+53)

= 500-100=400.

b) (756-217) - (183-53)

= 539-150= 389.

c) (-5).(-2).6.7

= 10.42=420

d) 24.36- (-24).64

= 864- (-1536)

= 2400.

Tick mk nha bn!!!!!

5 tháng 1 2018

a/ \(7-20+313\)

\(=\left(-13\right)+313\)

\(=300\)

b/ \(\left(-163\right)+177-\left(377-263\right)\)

\(=\left(-163\right)+177-114\)

\(=14-114\)

\(=-100\)

c/\(\left(325-47\right)+\left(175-53\right)\)

\(=278+122\)

\(=400\)

d/\(\left(217-756\right)-\left(41-183\right)\)

\(=\left(-539\right)-\left(-142\right)\)

\(=-397\)

\(=-100\)

5 tháng 1 2018

a/ 7 - 20 + 313

= - 13 + 313

= 300

b/ (-163) + 177 - (377 - 263)

= (-163) + 177 - 377 + 263

= [(-163) + 263] + (177 - 377)

= 100 + (-200)

= -100

c/ (325 - 47) + (175 - 53)

= 325 - 47 + 175 - 53

= (325 + 175) - (47 + 53)

= 500 - 100

= 400

d/ (217 - 756) - (41 - 183)

= 217 - 756 - 41 + 183

= (217 + 183) - ( 756 + 41)

= 400 - 797

= -397

12 tháng 2 2018

1,

(325-47)+(175-53)

=325-47+175-53

=(325+175)-(47+53)

=500-100

=400

2,

(756-217)-(183-44)

=756-217-183+44

=(756+44)-(217+183)

=800-400

=400

Bài 1: 

1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)

\(=-12-18\)

=-30

2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)

\(=36-2020+2019-136-27\)

\(=1-100-27\)

\(=-126\)

3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)

\(=144-97-244+197\)

\(=-100+100=0\)

4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)

\(=-24\cdot13+24\cdot3\)

\(=24\cdot\left(-13+3\right)\)

\(=24\cdot\left(-10\right)=-240\)

5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)

\(=54+55+56+57+58-64-65-66-67-68\)

\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)

\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)

=-50

6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)

\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)

\(=-24\cdot5+16\cdot5\)

\(=5\cdot\left(-24+16\right)\)

\(=-5\cdot8=-40\)

7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)

\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)

\(=47\cdot50-23\cdot50\)

\(=50\cdot\left(47-23\right)\)

\(=50\cdot24=1200\)

8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)

\(=-31\cdot\left(47+52+1\right)\)

\(=-31\cdot100=-3100\)

Bài 2: 

1) Ta có: \(-17-\left(2x-5\right)=-6\)

\(\Leftrightarrow-17-2x+5+6=0\)

\(\Leftrightarrow-2x-6=0\)

\(\Leftrightarrow-2x=6\)

hay x=-3

Vậy: x=-3

2) Ta có: \(10-2\left(4-3x\right)=-4\)

\(\Leftrightarrow10-8+6x+4=0\)

\(\Leftrightarrow6x+6=0\)

\(\Leftrightarrow6x=-6\)

hay x=-1

Vậy: x=-1

3) Ta có: \(-12+3\left(-x+7\right)=-18\)

\(\Leftrightarrow-12-3x+21+18=0\)

\(\Leftrightarrow-3x+27=0\)

\(\Leftrightarrow-3x=-27\)

hay x=9

Vậy: x=9

4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)

\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)

\(\Leftrightarrow-2x-3=-3\)

\(\Leftrightarrow-2x=0\)

hay x=0

Vậy: x=0

5) Ta có: x(x+3)=0

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-3\right\}\)

6) Ta có: (x-2)(x+4)=0

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)

Vậy: \(x\in\left\{2;-4\right\}\)

7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-1;3\right\}\)

25 tháng 1 2022

Bài 1: 

1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)

=−12−18=−12−18

=-30

2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27

=36−2020+2019−136−27=36−2020+2019−136−27

=1−100−27=1−100−27

=−126

Tớ chcs cậu học thật giỏi nha !

26 tháng 7 2016

(325 - 47) + (175 - 53)

=325 - 47 + 175 -53

=(325 + 175 ) - (47 + 53)

= 500 - 100

= 400
 

26 tháng 7 2016

b)(756-217)-(183-44)

=756-217-183+44

=(756+44)-(217+183)

=800-400

=400