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\(=\left(1+\frac{1}{2}\right)+\left(1+\frac{1}{4}\right)+\left(1+\frac{1}{8}\right)+\left(1+\frac{1}{16}\right)+...+1+\frac{1}{1024}\)
\(=\left(1+1+1+...+1\right)+\left(1+\frac{1}{2}+\frac{1}{4}+....+\frac{1}{1024}\right)\)
\(=9+\frac{1}{512}=\frac{4609}{512}\)
a.5/6 - 26/5 X 1/13 = 13/30
b.( 19/23 - 22/46 ) X 23/46 = 3/23
c.25/8 x 14/30 = 35/24
d.( 3/4 x 5/7 ) x ( 20/9 x 14/15 ) = 10/9
e.4/35 x 25/32 x 38/24 = 95/672
g. 1/2 x 3/4 x 2/3 x 4/5 = 1/5
h.5/6 x 11/4 - 5/4 x 23/6 = -5/2
i.9/16 x 13/4 - 9/4 x 5/16 + 9/16 x 17/4 = 225/64
k.( 7 x 1/3 ) x ( 1/7 x 6 ) = 2
m.2/3 x ( 3/5 + 3/7 ) = 34/35
n.4/5 x ( 5/8 + 7/4 ) = 19/10
p.( 1/33 + 31/333 - 341/3333 ) x ( 1/2 - 1/3 - 1/6 ) = 0
mih giành cả nửa tiếng để giải đó , k nha
\(\frac{5}{1.6}\)+ \(\frac{5}{6.11}\)+ .........+\(\frac{5}{501.506}\)
=\(\frac{1}{1.6}+\frac{1}{6.11}+.....+\frac{1}{501.506}\)
=\(\frac{1}{1}-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+......+\frac{1}{501}-\frac{1}{506}\)
=\(\frac{1}{1}-\frac{1}{506}\)
= tự tính nha
(9/2-2xX):11/7=77/20
9/2-2xX=121/20
2xX=-31/20
X=-31/40
k mk nha mk đung đó
\(\left(\frac{9}{2}-2\times x\right):1\frac{4}{7}=\frac{11}{4}\times\frac{7}{5}\)
\(\left(\frac{9}{2}-2\times x\right):\frac{11}{7}=\frac{77}{20}\)
\(\frac{9}{2}-2\times x=\frac{77}{20}\times\frac{11}{7}\)
\(\frac{9}{2}-2\times x=\frac{121}{20}\)
\(2\times x=\frac{9}{2}-\frac{121}{20}\)
\(2x=\frac{-31}{20}\)
\(x=\frac{-31}{20}:2\)
\(x=\frac{-31}{40}\)
giúp mk xem lại đề chút nha! vì lớp 5 chưa học số âm!
2/
a) \(\frac{4}{1\cdot5}+\frac{4}{5\cdot9}+\frac{4}{9\cdot13}+\frac{4}{13\cdot17}+\frac{4}{17\cdot21}\)
\(=\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+....+\frac{1}{17}-\frac{1}{21}\right)\)
\(=1-\frac{1}{21}=\frac{20}{21}\)
b) \(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot...\cdot\left(1-\frac{1}{2017}\right)\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot..\cdot\frac{2016}{2017}\)
\(=\frac{1}{2017}\)
c) \(A=2000-5-5-5-..-5\)(có 200 số 5)
\(A=2000-\left(5\cdot200\right)\)
\(A=2000-1000\)
\(A=1000\)
\(\frac{2}{9}\times\frac{5}{17}+\frac{7}{9}+\frac{2}{9}\times\frac{12}{17}\)
\(=\frac{2}{9}\times\left(\frac{5}{17}+\frac{12}{17}\right)+\frac{7}{9}\)
\(=\frac{2}{9}\times1+\frac{7}{9}\)
\(=\frac{2}{9}+\frac{7}{9}\)
\(=1\)
\(\frac{2}{9}\)× \(\frac{5}{17}\)+ \(\frac{7}{9}\)+\(\frac{2}{9}\)×\(\frac{12}{17}\)
= \(\frac{2}{9}\)×( \(\frac{5}{17}\)+\(\frac{12}{17}\)) + \(\frac{7}{9}\)
= \(\frac{2}{9}\)× \(\frac{17}{17}\)+\(\frac{7}{9}\)
= \(\frac{2}{9}\)+ \(\frac{7}{9}\)
= 1