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a) 9/18 - (-7/12) + 13/32
= 13/12 + 13/32
= 143/96
b) (5/-8) + 14/25 - 6/10
= (-13/200) - 6/10
= -133/200
Chúc bạn học tốt!! ^^
a: \(\dfrac{9}{18}-\dfrac{-7}{12}+\dfrac{13}{32}\)
\(=\dfrac{1}{2}+\dfrac{7}{12}+\dfrac{13}{32}\)
\(=\dfrac{48}{96}+\dfrac{56}{96}+\dfrac{39}{96}\)
\(=\dfrac{143}{96}\)
b: \(\dfrac{-5}{8}+\dfrac{14}{25}-\dfrac{6}{10}\)
\(=\dfrac{-125}{200}+\dfrac{112}{200}-\dfrac{120}{200}\)
\(=\dfrac{-133}{200}\)
a)\(-\frac{2}{7}x\frac{21}{8}=\frac{-2x3x7}{7x4x2}=-\frac{3}{4}\)
b) 0,24 x -15/4=-9/10
c) (-2) x (-7/12)=7/6
d) (-32/25) : 6=-16/75
\(a.\frac{-2}{7}\times\frac{21}{8}=\frac{\left(-2\right)\times21}{7\times8}=\frac{-1\times3}{1\times4}=\frac{-3}{4}.\)
\(b.0,24\times\frac{-15}{4}=\frac{6}{25}\times\frac{\left(-15\right)}{4}=\frac{6\times\left(-15\right)}{25\times4}=\frac{3\times\left(-3\right)}{5\times2}=\frac{-9}{10}\)
\(c.\left(-2\right)\times\frac{\left(-7\right)}{12}=\frac{\left(-2\right)\times\left(-7\right)}{12}=\frac{14}{12}=\frac{7}{6}\)
\(d.\frac{-32}{25}:6=\frac{-32}{25}\times\frac{1}{6}=\frac{-16}{75}\)
a) (-37) + 14 + 26 + 37
= [(-37) + 37] + (14 + 26)
= 0 + 40 = 40
b) (-24) + 6 + 10 + 24
= [(-24) + 24] + (10 + 6)
= 0 + 16 = 16
c) 15 + 23 + (-25) + (-23)
= [15 + (-25)] + [23 + (-23)]
= (-10) + 0 = -10
d) 60 + 33 + (-50) + (-33)
= [60 + (-50)] + [33 + (-33)]
= 10 + 0 = 10
e) (-16) + (-209) + (-14) + 209
= [(-16) + (-14)] + [(-209) + 209]
= (-30) + 0 = -30
f) \(-3^2+\left(-54\right)\div\left[\left(-2\right)^8+7\right]\times\left(-2\right)^2\\ =\left(-9\right)+\left(-54\right)\div263\times4\\ =\left(-9\right)+\dfrac{-216}{263}=\dfrac{-2583}{263}\)
a. \(\left[\left(-37\right)+37\right]+\left(14+16\right)\) = 30
B. \(\left[\left(-24\right)+24\right]+\left(10+6\right)\) = 16
C. \(\left[\left(-23\right)+23\right]+\left(15-23\right)\)= -8
d. \(\left[33-33\right]+\left(60-50\right)\) = 10
e. \(\left(209-209\right)+\left(-16-14\right)\)= -30
= [15/32 . 64 . 81 . 25]/225 . 27 . 0,0625 . 64
= 60750/225 . 27 . 0,0625 . 64
= 270 . 27 . 0,0625 . 64
= 29160
\(\dfrac{-6}{25}+\left|\dfrac{-4}{5}\right|-\left|\dfrac{2}{25}\right|\)
\(=\dfrac{-6}{25}+\dfrac{4}{5}-\dfrac{2}{25}\)
\(=\dfrac{-6}{25}+\dfrac{20}{25}-\dfrac{2}{25}\)
\(=\dfrac{12}{25}\)
Chọn B