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Bài 1:
a: UCLN(30;90)=30
BCNN(30;90)=90
b: UCLN(140;210;56)=14
BCNN(140;210;56)=840
c: UCLN(105;84;30)=3
BCNN(105;84;30)=420
1: UCLN(12;18)=6
BCNN(12;18)=36
2: UCLN(24;48)=24
BCNN(24;48)=48
a, Ta có: 24 = 2 3 . 3 ; 10 = 2.5
=> ƯCLN(24;10) = 2
BCNN(24;10) = 2 3 . 3 .5 = 120
b, Ta có: 150 = 2 . 3 . 5 2 ; 84 = 2 2 . 3 . 7
=> ƯCLN(150;84) = 2.3 = 6
BCNN(150;84) = 2 2 . 3 . 5 2 . 7
c, Ta có: 140 = 2 2 . 5 . 7 ; 210 = 2.3.5.7; 56 = 2 3 . 7
=> ƯCLN(140;210;56) = 2.7 = 14
BCNN(140;210;56) = 2 3 . 3 . 5 . 7 = 840
d, Ta có: 105 = 3.5.7; 84 = 2 2 . 3 . 7 ; 30 = 2.3.5
=> ƯCLN(105;84;30) = 3
BCNN(105;84;30) = 2 2 . 3 . 5 . 7 = 420
\(a,24=2^3\cdot3; 10=2\cdot5\\ ƯCLN\left(10,24\right)=2\\ BCNN\left(10,24\right)=2^3\cdot3\cdot5=120\\ b,9=3^2; 24=2^3\cdot3\\ ƯCLN\left(9,24\right)=3\\ BCNN\left(9,24\right)=2^3\cdot3^2=72\\ c,12=2^2\cdot3; 52=2^2\cdot13\\ ƯCLN\left(12,52\right)=2^2=4\\ BCNN\left(12,52\right)=2^2\cdot3\cdot13=156\\ d,14=2\cdot7;21=3\cdot7;56=2^3\cdot7\\ ƯCLN\left(14,21,56\right)=7\\ BCNN\left(14,21,56\right)=2^3\cdot3\cdot7=168\\ e,8=2^3;12=2^2\cdot3;15=3\cdot5\\ ƯCLN\left(8,12,15\right)=1\\ BCNN\left(8,12,15\right)=2^3\cdot3\cdot5=120\\ f,6=2\cdot3;8=2^3;10=2\cdot5\\ ƯCLN\left(6,8,10\right)=2\\ BCNN\left(6,8,10\right)=2^3\cdot3\cdot5=120\)
a) Ta có:
\(24=2^3.3\)
\(10=2.5\)
\(ƯCLN\left(24;10\right)=2\)
\(BCNN\left(24;10\right)=2^3.3.5=120\)
__________
b) Ta có:
\(300=2^2.3.5^2\)
\(280=2^3.5.7\)
\(ƯCLN\left(300;280\right)=2^2.5=20\)
\(BCNN\left(300;280\right)=2^3.3.5^2.7=4200\)
__________
c) Ta có:
\(30=2.3.5\)
\(90=2.3^2.5\)
\(ƯCLN\left(30;90\right)=2.3.5=30\)
\(BCNN\left(30;90\right)=2.3^2.5=90\)
_________
d) Ta có:
\(14=2.7\)
\(21=3.7\)
\(56=2^3.7\)
\(ƯCLN\left(14;21;56\right)=7\)
\(BCNN\left(14;21;56\right)=2^3.3.7=168\)
\(#Wendy.Dang\)
dễ mà