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a) \(\dfrac{3}{7}\)
b)\(\dfrac{9}{4}\)
c)\(\dfrac{1}{3}\)
d)\(\dfrac{41}{32}\)
e)\(\dfrac{73}{60}\)
\(2-\dfrac{3}{4}x\dfrac{8}{5}+\dfrac{1}{2}\)
\(=2-\dfrac{24}{20}+\dfrac{1}{2}\)
\(=2-\dfrac{24+10}{20}\)
\(=\dfrac{2}{1}-\dfrac{34}{20}=\dfrac{40-34}{20}=\dfrac{6}{20}=\dfrac{3}{10}\)
\(2-\dfrac{3}{4}\times\dfrac{8}{5}+\dfrac{1}{2}=\dfrac{2\times20}{1\times20}-\dfrac{24}{20}+\dfrac{1\times10}{2\times10}\\ =\dfrac{40-24+10}{20}=\dfrac{26}{20}=\dfrac{13}{10}\)
4/5 + 3/10 - 1/5 x 6 : 4/7
=11/10 - 1/5 x 6 : 4/7
= 9/10 x 6 : 4/7
= 27/5 : 4/7
= 189/20
chúc hok tốt
\(\frac{4}{5}.\frac{3}{7}+\frac{4}{5}.\frac{6}{7}-\frac{4}{5}.\frac{4}{14}\)
\(=\frac{4}{5}.\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{14}\right)\)
\(=\frac{4}{5}.1\)
\(=\frac{4}{5}\)
Ta có biểu thức :
\(M=\frac{11}{6}-\frac{5}{6}\div\left(m+\frac{3}{10}\right)\)
a ) Nếu \(m=\frac{1}{2}\) thì \(M=\frac{11}{6}-\frac{5}{6}\div\left(\frac{1}{2}+\frac{3}{10}\right)=\frac{5}{4}\)
b ) Nếu \(M=\frac{5}{3}\) thì
\(\frac{11}{6}-\frac{5}{6}\div\left(m+\frac{3}{10}\right)=\frac{5}{3}\)
\(1\div\left(m+\frac{3}{10}\right)=\frac{5}{3}\)
\(m+\frac{3}{10}=1\div\frac{5}{3}\)
\(m+\frac{3}{10}=\frac{3}{5}\)
\(m=\frac{3}{5}-\frac{3}{10}\)
\(m=\frac{3}{10}\)
\(\dfrac{3}{1}-\dfrac{5}{6}-\dfrac{1}{3}=\dfrac{18}{6}-\dfrac{5}{6}-\dfrac{2}{6}=\dfrac{11}{6}\)
\(2-\left(\dfrac{5}{8}+\dfrac{1}{4}\right)=2-\left(\dfrac{5}{8}+\dfrac{2}{8}\right)=\dfrac{2}{1}-\dfrac{7}{8}=\dfrac{16}{8}-\dfrac{7}{8}=\dfrac{9}{8}\)
\(2+\left(\dfrac{5}{4}-\dfrac{6}{8}\right)=2+\left(\dfrac{10}{8}-\dfrac{6}{8}\right)=\dfrac{2}{1}+\dfrac{1}{2}=\dfrac{4}{2}+\dfrac{1}{2}=\dfrac{5}{2}\)
\(\dfrac{19}{12}-\left(\dfrac{6}{24}+\dfrac{3}{4}\right)=\dfrac{19}{12}-\left(\dfrac{6}{24}+\dfrac{18}{24}\right)=\dfrac{19}{12}-1=\dfrac{19}{12}-\dfrac{12}{12}=\dfrac{7}{12}\)