thuc hien phep tinh
a)205 -[ 1200 -(4^2 -2 x3)^ 3 ]:140
b)[ (25 -2^2 x3 )+ (3^2 x4 +16) ] :5
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S
22 tháng 8 2016
5/11+1/2+2/5+6/11+3/4+16/25+5/16
=1441/400
19/4+37/100+1/8+132/25+5/2+37/12
=1933/120
C
13 tháng 3 2017
a,3/7 +1/2-[-3]/70
=13/14 -[-3]/70
=65/70 -[-3]/70
=34/35
b,3/5+-1/25 -35/100
=14/25 - 35/100
=56 /100 -35/100
= 21/100
c ,5/12 -3/-16+3/4
=29/48 +3/4
= 29/48 +36/48
=65/48
d, 5/15 +4/-12 +1/7 -1/-6
= 1/3 +1/-3 +1/7-1/-6
=0+1/7-1/-6
= 13/42
13 tháng 3 2017
A.\(\dfrac{3}{7}+\dfrac{1}{2}+\dfrac{\left(-3\right)}{70}\)
=\([\dfrac{30}{70}+\dfrac{\left(-3\right)}{70}]\)+\(\dfrac{1}{2}\)
= \(\dfrac{27}{70}+\dfrac{35}{70}\)
=\(\dfrac{62}{70}=\dfrac{31}{35}\)
B.\(\dfrac{3}{5}+\dfrac{-1}{25}-\dfrac{35}{100}\)
=\(\dfrac{60}{100}+\dfrac{-4}{100}-\dfrac{35}{100}\)
=\(\dfrac{60+\left(-4\right)-35}{100}\)
=\(\dfrac{21}{100}\)
C.\(\dfrac{5}{12}-\dfrac{3}{-16}+\dfrac{3}{4}\)
=\(\left(\dfrac{5}{12}+\dfrac{9}{12}\right)-\dfrac{-3}{16}\)
=\(\dfrac{7}{6}-\dfrac{-3}{16}\)
=\(\dfrac{56}{48}-\dfrac{-9}{48}\)=\(\dfrac{65}{48}\)
D.\(\dfrac{5}{15}+\dfrac{4}{-12}+\dfrac{1}{7}-\dfrac{1}{-6}\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+(\dfrac{-2}{6}-\dfrac{-1}{6})\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{-1}{6}\)
=\((\dfrac{1}{3}+\dfrac{-1}{6})+\dfrac{1}{7}\)
=\(\dfrac{1}{6}+\dfrac{1}{7}\)=\(\dfrac{13}{42}\)
NT
0
TN
3
1 tháng 5 2018
\(\frac{4}{5}+\frac{-7}{15}.1,25\)
\(=\frac{4}{5}+\frac{-7}{12}\)
\(=\frac{13}{60}\)
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PS
0
LM
1
NL
0
HN
11 tháng 7 2018
\(125.\left(28+72\right)-25.\left(3^2.4+64\right)\)
\(=125.100-25.\left(9.4+64\right)\)
\(=125.100-25.\left(36+64\right)\)
\(=125.100-25.100\)
\(=100.\left(125-25\right)\)
\(=100.100\)
\(=10000\)
a: \(=205-\left[1200-\left(16-6\right)^3\right]:140\)
\(=205-\left[1200-10^3\right]:140\)
\(=205-\dfrac{200}{140}=205-\dfrac{10}{7}=\dfrac{1425}{7}\)
b: \(=\left[25-4\cdot3+9\cdot4+16\right]:5\)
\(=\left(25-12+36+16\right):5=\dfrac{65}{5}=13\)