Question

[Nguyễn Thùy Linh]

Tính:  ^{\(C=\frac{\left(3.4.2^4\right)^2}{5.2^5.4^2-16^2}\)}

Answer 1

[Nguyễn Huy Hải]

chép nhầm đề. Làm lại:

\(C=\frac{\left(3.4.2^4\right)^2}{5.2^5.4^2-16^2}=\frac{3^2.2^4.2^8}{5.2^5.2^4-2^8}=\frac{9.2^{12}}{5.2^9-2^8}=\frac{9.2^{12}}{2^8.\left(5.2-1\right)}=\frac{9.2^4}{9}=\frac{2^4}{1}=2^4=16\)

Answer 2

[Nguyễn Huy Hải]

Gấp lắm thì làm vậy

\(C=\frac{\left(3.4.2^2\right)^2}{5.2^5.4^2-16^2}=\frac{3^2.2^4.2^4}{5.2^5.2^4-2^8}=\frac{3^2.2^8}{5.2^9-2^8}=\frac{3^2.2^8}{2^8.\left(5.2-1\right)}=\frac{9}{9}=1\)