Tìm x thuộc Z : a)2.(x-1) 4(x 2)= -12 b)-5.(2x 3)-3(4-3x)=13 c)-10(x-7) 5(4-x)=-15 d)4(2x-3)-7(x-2)=10 e)-3(4x 6)-2(-7x-1)=2 f)-(x 9)-(2x 5)=-x 8 g)-(2x 7) 2(5-3x)=-13 h)(25-39)-(x 15)=-(3x 7)...

1

NL

Nguyễn Lê Phước Thịnh

16 tháng 6 2022

a: \(\Leftrightarrow2x-2+4x+8=-12\)

=>6x+6=-12

=>6x=-18

hay x=-3

b: \(\Leftrightarrow-10x-15-12+9x=13\)

=>-x-27=13

=>-x=40

hay x=-40

c: \(\Leftrightarrow-10x+70+20-5x=-15\)

\(\Leftrightarrow-15x=-105\)

hay x=7

d: \(\Leftrightarrow8x-12-7x+14=10\)

=>x+2=10

hay x=8

e: \(\Leftrightarrow-12x-18+14x+2=2\)

=>2x-16=2

hay x=9

Bài 1:a)-2x-3.( x-17 )= 34-2.( -x+25 )b)17x+3.( -16x-37 )= 2x+43-4xc){-3x+2. [ 45-x-3 ( 3x+7 ) -2x]+4x} = 55g)-103-57: [ 5.( 2x-1 )2-( -9 )0 ]Bài 2:a)-5.( -x+7 )-3.( -x-5 )=-4.( 12-x )+48b)7.( -x-7 )-4.( -2x-11 )=7.( 4x+10 )+9c)-2.( 15-3x )-4.( -7x+8 )=-5-9.( -2x+1 )d)5.( -3x-7 )-4.( -2x-11 )=7.( 4x+10 )+9e)4( x-2 )2-13=( -3 )2.2-11.( -3 )f)-52-( 2x-1 )3=( -13 ).( -3...

NM

Nguyễn Minh Nhật

VIP

6 tháng 2 2020

0

NT

Nguyễn Trúc Phương

16 tháng 4 2016

Tìm x biet:

a,5/2x+x=32/15

b,x-7/2x=-32/15

c,-7/3x-7/4x+11/3=18/5

d,-5/6-3x=2/3

e,2x-5/9=-2/3

f,1/2-2/3x=7/12

g,7-|2x-3|=4

h,(19x+2.5^2):14=(13-8)^2-4^2

i,3/4x-2/3=2/7.1/6+5/7.1/6

k,(x+1/2).(2/3-2x)=0

l,x/2013-1/10-1/15-1/21-........-1/120=5/8

0

TM

Trang Minh

15 tháng 8 2017

a) -5 (2x + 6 ) +b | 3x + 9 | = 7x

b) 7(x - 4 ) - | 4x - 12 | = 0

c) | x - 5 | - | x - 3 | =0

d)| x + 1| + | -x + 12 | = 2x -7

e) | x + 2| - | x + 6 | - (-15) = 0

f) | 2x- 10 | + | 3y - 4 | = 0

g) | - 3x + 1 | - | 2x + 8 | + 3x = 0

h) 3( x - 1 ) - 5 | x + 3 | = 0

1

TM

Trang Minh

15 tháng 8 2017

Mọi người giúp mình nhanh nhé ! Mình đang cần gấp

giải các phương trình sau: a) 4x.(2x+3) - x.(8x-1)= 5.(x+2) b) (3x-5).(3x+5) - x.(9x-1) = 4 c) 3 - 4x . (25-2x) = 8x^2 + x - 300 d) 2. (1-3x/5) - 2+3x/10 = 7-3.(2x+1)/4 e) 5x + 2/6 - 8x - 1 /3 = 4x + 2 /5 - 5 f) 5x - 4/2 = 16x + 1/7 g) 12x + 5 / 3=2x - 7/4 h) 3t - 8/12 = 5-t /8 i) 5u + 6/15 = u - 4 /10 k) 3.(x-11)/4 = 3. (x+1) - 2.(2x+ 5)/10 l) 14 và 1/2 - 2. (x+3)/5 = 3x/2 - 2. (x-7 )/3 m ) 2x -5 / 6 - x +2 = 5x - 3/ 3 - 6x - 7/ 4 + x n) x-4/5 + 3x - 2/10 - x = 2x-5/3 - 7x+2/6 mình...

VD

Vũ Đình Đạt

21 tháng 2 2020

giải các phương trình sau: a) 4x.(2x+3) - x.(8x-1)= 5.(x+2) b) (3x-5).(3x+5) - x.(9x-1) = 4 c) 3 - 4x . (25-2x) = 8x^2 + x - 300 d) 2. (1-3x/5) - 2+3x/10 = 7-3.(2x+1)/4 e) 5x + 2/6 - 8x - 1 /3 = 4x + 2 /5 - 5 f) 5x - 4/2 = 16x + 1/7 g) 12x + 5 / 3=2x - 7/4 h) 3t - 8/12 = 5-t /8 i) 5u + 6/15 = u - 4 /10 k) 3.(x-11)/4 = 3. (x+1) - 2.(2x+ 5)/10 l) 14 và 1/2 - 2. (x+3)/5 = 3x/2 - 2. (x-7 )/3 m ) 2x -5 / 6 - x +2 = 5x - 3/ 3 - 6x - 7/ 4 + x n) x-4/5 + 3x - 2/10 - x = 2x-5/3 - 7x+2/6 mình...

0

VD

Vũ Đình Đạt

21 tháng 2 2020

giải các phương trình sau: a) 4x.(2x+3) - x.(8x-1)= 5.(x+2) b) (3x-5).(3x+5) - x.(9x-1) = 4 c) 3 - 4x . (25-2x) = 8x^2 + x - 300 d) 2. (1-3x/5) - 2+3x/10 = 7-3.(2x+1)/4 e) 5x + 2/6 - 8x - 1 /3 = 4x + 2 /5 - 5 f) 5x - 4/2 = 16x + 1/7 g) 12x + 5 / 3=2x - 7/4 h) 3t - 8/12 = 5-t /8 i) 5u + 6/15 = u - 4 /10 k) 3.(x-11)/4 = 3. (x+1) - 2.(2x+ 5)/10 l) 14 và 1/2 - 2. (x+3)/5 = 3x/2 - 2. (x-7 )/3 m ) 2x -5 / 6 - x +2 = 5x - 3/ 3 - 6x - 7/ 4 + x n) x-4/5 + 3x - 2/10 - x = 2x-5/3 - 7x+2/6 mình...

0

VD

Vũ Đình Đạt

21 tháng 2 2020

giải các phương trình sau: a) 4x.(2x+3) - x.(8x-1)= 5.(x+2) b) (3x-5).(3x+5) - x.(9x-1) = 4 c) 3 - 4x . (25-2x) = 8x^2 + x - 300 d) 2. (1-3x/5) - 2+3x/10 = 7-3.(2x+1)/4 e) 5x + 2/6 - 8x - 1 /3 = 4x + 2 /5 - 5 f) 5x - 4/2 = 16x + 1/7 g) 12x + 5 / 3=2x - 7/4 h) 3t - 8/12 = 5-t /8 i) 5u + 6/15 = u - 4 /10 k) 3.(x-11)/4 = 3. (x+1) - 2.(2x+ 5)/10 l) 14 và 1/2 - 2. (x+3)/5 = 3x/2 - 2. (x-7 )/3 m ) 2x -5 / 6 - x +2 = 5x - 3/ 3 - 6x - 7/ 4 + x n) x-4/5 + 3x - 2/10 - x = 2x-5/3 - 7x+2/6 mình...

0

VD

Vũ Đình Đạt

21 tháng 2 2020

giải các phương trình sau: a) 4x.(2x+3) - x.(8x-1)= 5.(x+2) b) (3x-5).(3x+5) - x.(9x-1) = 4 c) 3 - 4x . (25-2x) = 8x^2 + x - 300 d) 2. (1-3x/5) - 2+3x/10 = 7-3.(2x+1)/4 e) 5x + 2/6 - 8x - 1 /3 = 4x + 2 /5 - 5 f) 5x - 4/2 = 16x + 1/7 g) 12x + 5 / 3=2x - 7/4 h) 3t - 8/12 = 5-t /8 i) 5u + 6/15 = u - 4 /10 k) 3.(x-11)/4 = 3. (x+1) - 2.(2x+ 5)/10 l) 14 và 1/2 - 2. (x+3)/5 = 3x/2 - 2. (x-7 )/3 m ) 2x -5 / 6 - x +2 = 5x - 3/ 3 - 6x - 7/ 4 + x n) x-4/5 + 3x - 2/10 - x = 2x-5/3 - 7x+2/6 mình...

0

VD

Vũ Đình Đạt

21 tháng 2 2020

11

PN

Phan Nghĩa

17 tháng 5 2021

a,\(4x\left(2x+3\right)-x\left(8x-1\right)=5\left(x+2\right)\)

\(< =>8x^2+12x-8x^2+x=5x+10\)

\(< =>13x=5x+10< =>8x=10\)

\(< =>x=\frac{10}{8}=\frac{5}{4}\)

b, \(\left(3x-5\right)\left(3x+5\right)-x\left(9x-1\right)=4\)

\(< =>9x^2-25-9x^2+x=4\)

\(< =>x=4+29=33\)

PN

Phan Nghĩa

17 tháng 5 2021

c,\(3-4x\left(25-2x\right)=8x^2+x-300\)

\(< =>3-100x+8x^2=8x^2+x-300\)

\(< =>x+100x=3+300\)

\(< =>101x=303< =>x=\frac{303}{101}=3\)

d,\(2\left(1-\frac{3x}{5}\right)-\frac{2+3x}{10}=7-\frac{3\left(2x+1\right)}{4}\)

\(< =>2-\frac{6x}{5}-\frac{2+3x}{10}=7-\frac{6x+3}{4}\)

\(< =>-\frac{24x}{20}-\frac{4+6x}{20}+\frac{30x+15}{20}=5\)

\(< =>\frac{30x-6x-24x+15-4}{20}=5\)

\(< =>\frac{11}{5}=5< =>11=25\)(vo li)

Câu 1. Giải các phườn trình sau: a, 3x+6=0 b, 2x-10=0 c, 3x-7=11 d, 3x-9=0 e, 3x(2-x) =15(x-2) f, (x+5)(x+4)=0 g, x(x+4)=0 h, (2x -4)(x-2)=0 i, (x+1/5)(2x-3)=0 k, x²-4x=0 m, 4x²-1=0 n, x²-6x+9=0 l, (3x-5)²-(x+4)²=0 o, 7x(x+2)-5(x+2)=0 p, 3x(2x-5)-4x+10=0 q, (2-2x)-x²+1=0 r, x(1-3x)=5(1-3x) s, 2x-3/4+x+1/6=3 t, x-3/4-2x+1/3=x/6 u, x+1/13+x+2/12=x+3/11+x+4/10 v, 2x+1/15+2x+2/14=2x+3/13+2x+4/12 Giúp e nha mn. E cảm ơn trc ạ! ...

DP

Dung pham tuan dung

1 tháng 4 2020

5

M

Miinhhoa

1 tháng 4 2020

e, 3x(2-x) =15(x-2)

\(\Leftrightarrow3x\left(2-x\right)-15\left(x-2\right)=0\)

\(\Leftrightarrow-3x\left(x-2\right)-15\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(-3x-15\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x-2=0\\-3x-15=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)

Vậy..

f, (x+5)(x+4)=0

\(\Leftrightarrow\left\{{}\begin{matrix}x+5=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-5\\x=-4\end{matrix}\right.\)

Vậy..

g, x(x+4)=0

\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=-4\end{matrix}\right.\)

,h, (2x -4)(x-2)=0

\(\Leftrightarrow2\left(x-2\right)\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(2-1\right)=0\)

\(\Leftrightarrow x-2=0\Leftrightarrow x=2\)

i, (x+1/5)(2x-3)=0

\(\Leftrightarrow\left\{{}\begin{matrix}x+\frac{1}{5}=0\\2x-3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\frac{-1}{5}\\x=\frac{3}{2}\end{matrix}\right.\)

k, x²-4x=0

\(\Leftrightarrow x\left(x-2\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

m, 4x²-1=0

\(\Leftrightarrow\left(2x\right)^2-1^2=0\)

\(\Leftrightarrow\left(2x-1\right)\left(2x+1\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x-1=0\\2x+1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=1\\2x=-1\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{1}{2}\\x=\frac{-1}{2}\end{matrix}\right.\)

n, x²-6x+9=0

\(\Leftrightarrow x^2-2.x.3+3^2=0\)

\(\Leftrightarrow\left(x-3\right)^2=0\Leftrightarrow x-3=0\)

<=> x=3

l, (3x-5)²-(x+4)²=0

\(\Leftrightarrow\left(3x-5-x-4\right)\left(3x-5+x+4\right)=0\)

\(\Leftrightarrow\left(2x-9\right)\left(4x-1\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x-9=0\\4x-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=9\\4x=1\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{9}{2}\\x=\frac{1}{4}\end{matrix}\right.\)

Vậy ..

o, 7x(x+2)-5(x+2)=0

\(\Leftrightarrow\left(x+2\right)\left(7x-5\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x+2=0\\7x-5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\7x=5\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\x=\frac{5}{7}\end{matrix}\right.\)

Vậy....

p, 3x(2x-5)-4x+10=0

\(\Leftrightarrow3x\left(2x-5\right)-\left(4x-10\right)=0\)

\(\Leftrightarrow3x\left(2x-5\right)-2\left(2x-5\right)=0\)

\(\Leftrightarrow\left(2x-5\right)\left(3x-2\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x-5=0\\3x-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=5\\3x=2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{5}{2}\\x=\frac{2}{3}\end{matrix}\right.\)

Vậy...

q, (2-2x)-x²+1=0

\(\Leftrightarrow2\left(1-x\right)-\left(x^2-1^2\right)=0\)

\(\Leftrightarrow2\left(1-x\right)-\left(x-1\right)\left(x+1\right)=0\)

\(\Leftrightarrow2\left(1-x\right)+\left(1-x\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left(1-x\right)\left(2+x+1\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}1-x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-1\\x=-3\end{matrix}\right.\)

Vậy ....

r, x(1-3x)=5(1-3x)

\(\Leftrightarrow x\left(1-3x\right)-5\left(1-3x\right)=0\)

\(\Leftrightarrow\left(1-3x\right)\left(x-5\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}1-3x=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-3x=-1\\x=5\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{1}{3}\\x=5\end{matrix}\right.\)

s, 2x-3/4+x+1/6=3

\(\Leftrightarrow x-\frac{7}{12}=3\Leftrightarrow x=3+\frac{7}{12}=\frac{43}{12}\)

S

✟şin❖

1 tháng 4 2020

r, x(1-3x)=5(1-3x)

➜x(1-3x)-5(1-3x)=0

➜(x-5)(1-3x)=0

➜\(\left[{}\begin{matrix}x-5=0\\1-3x=0\end{matrix}\right.\text{➜}\left[{}\begin{matrix}x=5\\x=\frac{1}{3}\end{matrix}\right.\)

Mk lười lắm mai nha!!!~~~~~~~~~~~~