Question

[Kiara Nguyễn]

1/ Cho S= \(\dfrac{1}{11} + \dfrac{1}{12} + \dfrac{1}{13} + ... + \dfrac{1}{19} + \dfrac{1}{20}\)

So sánh S với \(\dfrac{1}{2}\)

2/ Tìm x biết: \(\dfrac{x}{12}= \dfrac{-1}{24}- \dfrac{1}{8}\)

3/Tính 1 cách hợp lí: \(\dfrac{2}{5.7}+ \dfrac{2}{7.9}+ ...+ \dfrac{2}{19.21}\)

GIÚP MK VS!!! MK ĐG GẤP LẮM >.< MƠN M.N NHÌU Ạ!

Answer 1

[Nguyễn Thanh Hằng]

. Ta có :

\(\dfrac{1}{11}>\dfrac{1}{20}\)

\(\dfrac{1}{12}>\dfrac{1}{20}\)

.................

\(\dfrac{1}{19}>\dfrac{1}{20}\)

\(\dfrac{1}{20}=\dfrac{1}{20}\)

\(\Leftrightarrow\dfrac{1}{11}+\dfrac{1}{12}+......+\dfrac{1}{20}>\dfrac{1}{20}+\dfrac{1}{20}+.....+\dfrac{1}{20}\)

\(\Leftrightarrow S>\dfrac{1}{20}.10\)

\(\Leftrightarrow S>\dfrac{1}{2}\)

2. \(\dfrac{x}{12}=\dfrac{-1}{24}-\dfrac{1}{8}\)

\(\Leftrightarrow\dfrac{x}{12}=-\dfrac{1}{6}\)

\(\Leftrightarrow6x=-12\)

\(\Leftrightarrow x=-2\)

Vậy ...

3. \(\dfrac{2}{5.7}+\dfrac{2}{7.9}+........+\dfrac{2}{19.21}\)

\(=\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+......+\dfrac{1}{19}-\dfrac{1}{21}\)

\(=\dfrac{1}{5}-\dfrac{1}{21}\)

\(=\dfrac{16}{105}\)

Answer 2

[Kiara Nguyễn]

Mơn bn dthw nhìu nek ><