Câu 1: Hiệu điện thế giữa hai bản kim loại phẳng, đặt song song, cách nhau 2 cm là bao nhiêu nếu cường độ điện trường giữa hai bản là 4000 V/m?
A. 80 V B. 8000 V C. 2000 V D. 2.105V
Câu 2: Nếu cường độ điện trường giữa đám mây và mặt đất là 2.104 V/m và đám mây cách mặt đất 1.103 m thì hiệu điện thế giữa đám mây và mặt đất là:
A. 2.107 V B. 1,3.1023 V C. 2.101 V D. 5.10-2 V
Câu 1:![2.10 to the power of 4.1.10 cubed equals 2.10 to the power of 7 space V](data:image/svg+xml;charset=utf8,%3Csvg%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F2000%2Fsvg%22%20xmlns%3Awrs%3D%22http%3A%2F%2Fwww.wiris.com%2Fxml%2Fmathml-extension%22%20height%3D%2222%22%20width%3D%22156%22%20wrs%3Abaseline%3D%2218%22%3E%3C!--MathML%3A%20%3Cmath%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmo%3E.%3C%2Fmo%3E%3Cmsup%3E%3Cmn%3E10%3C%2Fmn%3E%3Cmn%3E4%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmo%3E.%3C%2Fmo%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmo%3E.%3C%2Fmo%3E%3Cmsup%3E%3Cmn%3E10%3C%2Fmn%3E%3Cmn%3E3%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmo%3E%3D%3C%2Fmo%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmo%3E.%3C%2Fmo%3E%3Cmsup%3E%3Cmn%3E10%3C%2Fmn%3E%3Cmn%3E7%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmo%3E%26%23xA0%3B%3C%2Fmo%3E%3Cmi%3EV%3C%2Fmi%3E%3C%2Fmath%3E--%3E%3Cdefs%3E%3Cstyle%20type%3D%22text%2Fcss%22%3E%40font-face%7Bfont-family%3A'math1dd165a6c6b5bc8158c57065d13'%3Bsrc%3Aurl(data%3Afont%2Ftruetype%3Bcharset%3Dutf-8%3Bbase64%2CAAEAAAAMAIAAAwBAT1MvMi7iBBMAAADMAAAATmNtYXDEvmKUAAABHAAAADxjdnQgDVUNBwAAAVgAAAA6Z2x5ZoPi2VsAAAGUAAAA%2BGhlYWQQC2qxAAACjAAAADZoaGVhCGsXSAAAAsQAAAAkaG10eE2rRkcAAALoAAAADGxvY2EAHTwYAAAC9AAAABBtYXhwBT0FPgAAAwQAAAAgbmFtZaBxlY4AAAMkAAABn3Bvc3QB9wD6AAAExAAAACBwcmVwa1uragAABOQAAAAUAAADSwGQAAUAAAQABAAAAAAABAAEAAAAAAAAAQEAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACAgICAAAAAg1UADev96AAAD6ACWAAAAAAACAAEAAQAAABQAAwABAAAAFAAEACgAAAAGAAQAAQACAC4APf%2F%2FAAAALgA9%2F%2F%2F%2F0%2F%2FFAAEAAAAAAAAAAAFUAywAgAEAAFYAKgJYAh4BDgEsAiwAWgGAAoAAoADUAIAAAAAAAAAAKwBVAIAAqwDVAQABKwAHAAAAAgBVAAADAAOrAAMABwAAMxEhESUhESFVAqv9qwIA%2FgADq%2FxVVQMAAAEAIAAAAKAAgAADAC8YAbAEELAD1LADELAC1LADELAAPLACELABPACwBBCwA9SwAxCwAjywABCwATwwMTczFSMggICAgAACAIAA6wLVAhUAAwAHAGUYAbAIELAG1LAGELAF1LAIELAB1LABELAA1LAGELAHPLAFELAEPLABELACPLAAELADPACwCBCwBtSwBhCwB9SwBxCwAdSwARCwAtSwBhCwBTywBxCwBDywARCwADywAhCwAzwxMBMhNSEdASE1gAJV%2FasCVQHAVdVVVQABAAAAAQAA1XjOQV8PPPUAAwQA%2F%2F%2F%2F%2F9Y6E3P%2F%2F%2F%2F%2F1joTcwAA%2FyAEgAOrAAAACgACAAEAAAAAAAEAAAPo%2F2oAABdwAAD%2FtgSAAAEAAAAAAAAAAAAAAAAAAAADA1IAVQDIACADVgCAAAAAAAAAACgAAABuAAAA%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%2F)format('truetype')%3Bfont-weight%3Anormal%3Bfont-style%3Anormal%3B%7D%3C%2Fstyle%3E%3C%2Fdefs%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%224.5%22%20y%3D%2218%22%3E2%3C%2Ftext%3E%3Ctext%20font-family%3D%22math1dd165a6c6b5bc8158c57065d13%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2211.5%22%20y%3D%2218%22%3E.%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2223.5%22%20y%3D%2218%22%3E10%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2212%22%20text-anchor%3D%22middle%22%20x%3D%2235.5%22%20y%3D%2211%22%3E4%3C%2Ftext%3E%3Ctext%20font-family%3D%22math1dd165a6c6b5bc8158c57065d13%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2241.5%22%20y%3D%2218%22%3E.%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2248.5%22%20y%3D%2218%22%3E1%3C%2Ftext%3E%3Ctext%20font-family%3D%22math1dd165a6c6b5bc8158c57065d13%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2255.5%22%20y%3D%2218%22%3E.%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2267.5%22%20y%3D%2218%22%3E10%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2212%22%20text-anchor%3D%22middle%22%20x%3D%2279.5%22%20y%3D%2211%22%3E3%3C%2Ftext%3E%3Ctext%20font-family%3D%22math1dd165a6c6b5bc8158c57065d13%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2291.5%22%20y%3D%2218%22%3E%3D%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%22104.5%22%20y%3D%2218%22%3E2%3C%2Ftext%3E%3Ctext%20font-family%3D%22math1dd165a6c6b5bc8158c57065d13%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%22111.5%22%20y%3D%2218%22%3E.%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%22123.5%22%20y%3D%2218%22%3E10%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2212%22%20text-anchor%3D%22middle%22%20x%3D%22135.5%22%20y%3D%2211%22%3E7%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20font-style%3D%22italic%22%20text-anchor%3D%22middle%22%20x%3D%22148.5%22%20y%3D%2218%22%3EV%3C%2Ftext%3E%3C%2Fsvg%3E)
Áp dụng công thức
U=E.d=4000.0,02=80(V)
=> Chọn A
Câu 2:
Chọn gốc điện thế tại mặt đất
Hiệu điện thế giữa đám mây và mặt đất là:
U=Ed=
=> Chọn A