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9 tháng 12 2019

a)

4Al + 3O2\(\rightarrow\) 2Al2O3

Al2O3 +6HNO3\(\rightarrow\) 2Al(NO3)3 + 3H2O

Al(NO3)3 + 3NaOH \(\rightarrow\)Al(OH)3 + 3NaNO3

2Al(OH)3 \(\underrightarrow{^{to}}\) Al2O3 + 3H2O

Al2O3 +6HCl \(\rightarrow\) 2AlCl3 + 3H2O

AlCl3 không điện phân nóng chảy được \(\rightarrow\) Al2O3 \(\underrightarrow{^{\text{đpnc}}}\)2Al + \(\frac{3}{2}\)O2

b) 2Fe + 3Cl2 \(\rightarrow\) 2FeCl3

FeCl3 + 3NaOH \(\rightarrow\)Fe(OH)3 + 3NaCl

2Fe(OH)3\(\rightarrow\)Fe2O3 + 3H2O

Fe2O3 + 3CO \(\rightarrow\)2Fe + 3CO2

Fe + 2HCl\(\rightarrow\) FeCl2 + 2

FeCl2 + 2AgNO3\(\rightarrow\)Fe(NO3)2 + 2AgCl (thường ra Fe+3 )

c) 2Mg + O2\(\rightarrow\)2MgO

MgO + 2HCl \(\rightarrow\) MgCl2 + H2O

MgCl2 + 2NaOH \(\rightarrow\) Mg(OH)2 + 2NaCl

Mg(OH)2 + H2SO4 \(\rightarrow\)MgSO4 + 2H2O

MgSO4 + BaCl2 \(\rightarrow\) MgCl2 + BaSO4

d) Cu(OH)2\(\underrightarrow{^{to}}\) CuO + H2O

CuO + H2SO4\(\rightarrow\)CuSo4 + H2O

CuSO4 + BaCl2 \(\rightarrow\) BaSO4 + CuCl2

CuCl2 + 2AgNO3 \(\rightarrow\) Cu(NO3)2 + 2AgCl

Fe + Cu(NO3)2\(\rightarrow\) Fe(NO3)2 + Cu

Cu + \(\frac{1}{2}\)O2 \(\rightarrow\) CuO

e) 4Na + O2\(\rightarrow\) 2Na2O

Na2O + H2O \(\rightarrow\) 2NaOH

2NaOH + CO2 \(\rightarrow\)Na2CO3 + H2O

Na2CO3 + H2SO4\(\rightarrow\) Na2SO4 + CO2 + H2O

Na2SO4 + BaCl2 \(\rightarrow\)BaSO4 + 2NaCl

NaCl + AgNO3\(\rightarrow\) AgCl + NaNO3

f) Fe3O4 + 4CO\(\rightarrow\) 3Fe + 4CO2

2Fe + 3Cl2 \(\rightarrow\)2FeCl3

FeCl3 + 3AgNO3 \(\rightarrow\) Fe(NO3)3 +3AgCl

Fe(NO3)3 + 3NaOH \(\rightarrow\) Fe(OH)3 + 3NaNO3

Lần sau đăng tách riêng ra nhé

Nhìn rối mắt lắm

9 tháng 12 2019

a) Al -> Al2O3-> Al(NO3)3-> Al(OH)3 -> Al2O3 -> AlCl3 -> Al

(1) 2A1 + O2 t0→ Al2O3

(2) Al2O3 + 6HCl → 2AlCl3 + 3H2O

(3) Al(NO3)3 + 3NaOH (vừa đủ) → 3NaNO3 + Al (OH)3

(4) 2Al(OH)3 →t0 Al2O3+ ЗН2О

(5) 2Al2O3 đpnc−−→đpnc 4Al + 3O2

(6) 2Al + 3Cl2 t→t0 2AlCl3

b) Fe -> FeCl3 -> Fe(OH)3 -> Fe2O3-> Fe -> FeCl2 -> Fe(NO3)3

(1) 2Fe + 3Cl2 → 2FeCl3

(2) FeCl3 + 3NaOH → 3NaCl + Fe(OH)3

(3) 2Fe(OH)3 → Fe2O3 + 3H2O

(4) Fe2O3 + H2→ Fe + H2O

(5) 3Fe + 2HCl → 2FeCl2 +H2↑

(6) Fe(NO3)3+3NaOH ➞Fe(OH)3 +3Na(NO3)

dài wá mình trả lời những câu còn lại sau : thông cảm cho mk nha❗❕

30 tháng 11 2018

a.

2Al2O3 \(\underrightarrow{t^o}\)4Al + 3O2\(\uparrow\)

Al + 6HNO3 \(\rightarrow\) Al(NO3)3\(\downarrow\) + 3NO2 + 3H2O

Al(NO3)3 + NaOH \(\rightarrow\) Al(OH)3\(\downarrow\) + NaNO3

2Al(OH)3 \(\xrightarrow[criolit]{đpnc}\) Al2O3 + 3H2O

Al2O3 + 3H2SO4 \(\rightarrow\) Al2(SO4)3 + 3H2O

Al2(SO4)3 + 3BaCl2 \(\rightarrow\) 3BaSO4\(\downarrow\) + 2AlCl3

2AlCl3 \(\xrightarrow[criolit]{đpnc}\) 2Al + 3Cl2\(\uparrow\)

2Al + 3CuSO4 \(\rightarrow\) 3Cu + Al2(SO4)3

4 tháng 12 2016

a/

  • C + O2 ===> CO2
  • CO2 + Ca(OH)2 ===> CaCO3 + H2O
  • CaCO3 + Ba(OH)2 ===> Ca(OH)2 + BaCO3
  • CO2 + Ca(OH)2 ===> CaCO3 + H2O
  • CaCO3 + 2HCl ===> CaCl2 + CO2 + H2O

b/

  • 4Al + 3O2 ===> 2Al2O3
  • Al2O3 + 6HNO3 ===> 2Al(NO3)3 + 3H2O
  • Al(NO3)3 + 3NaOH ===> Al(OH)3 + 3NaNO3
  • 2Al(OH)3 + 6HCl ===> 2AlCl3 + 3H2O
  • 2AlCl3 + 3Mg ===> 3MgCl2 + 2Al

 

4 tháng 12 2016

a)c+o2->co2

co2+ca(oh)2->caco3 +h2o

caco3+ba(oh)2->CA(OH)2+baco3

co2+ca(oh)2->caco3 +h2o

caco3+bacl2->cacl2+baco3

 

20 tháng 12 2019

a) 2Fe+3Cl2--->2FeCl3

FeCl3+3NaOH--->3NaCl+Fe(OH)3

3Fe(OH)3-->Fe2O3+3H2O

Fe2O3+H2---->2Fe+3H2O

Fe+H2SO4---->FeSO4+H2

FeSO4+BaCl2---->FeCl2+BaSO4

b) Fe+2HCl--->FeCl2+H2

FeCl2+AgNO3--->2AgCl+Fe(NO3)2

Fe(NO3)2+2NaOH--->2NaNO3+Fe(OH)2

Fe(OH)2+Na2SO4--->2NaOH+FeSO4

FeSO4+Zn----->ZnSO4+Fe

Fe+.....Ko biết

c)4 Al+3O2--->2Al2O3

Al2O3+3H2SO4--->Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2---->2AlCl3+3BaCl2

Alcl3+3NaOH--->Al(OH)3+3NaCl

2Al(OH)3--->Al2O3+3H2O

2Al2O3--->4Al+3O2

20 tháng 12 2019

a) 2Fe+3Cl2--->2FeCl3

FeCl3+3NaOH--->3NaCl+Fe(OH)3

3Fe(OH)3-->Fe2O3+3H2O

Fe2O3+H2---->2Fe+3H2O

Fe+H2SO4---->FeSO4+H2

FeSO4+BaCl2---->FeCl2+BaSO4

b) Fe+2HCl--->FeCl2+H2

FeCl2+AgNO3--->2AgCl+Fe(NO3)2

Fe(NO3)2+2NaOH--->2NaNO3+Fe(OH)2

Fe(OH)2+Na2SO4--->2NaOH+FeSO4

FeSO4+Zn----->ZnSO4+Fe

ko có PTHH

c)4 Al+3O2--->2Al2O3

Al2O3+3H2SO4--->Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2---->2AlCl3+3BaCl2

Alcl3+3NaOH--->Al(OH)3+3NaCl

2Al(OH)3--->Al2O3+3H2O

2Al2O3--->4Al+3O2

21 tháng 12 2021

\(a,2Fe+3Cl_2\xrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\to Fe(OH)_3\downarrow+3NaCl\\ 2Fe(OH)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ Fe+H_2SO_4\to FeSO_4+H_2\\ FeSO_4+BaS\to BaSO_4\downarrow+FeS\\ FeS+2HCl\to FeCl_2+H_2\\ FeCl_2+2AgNO_3\to Fe(NO_3)_2+2AgCl\downarrow\)

\(b,2Al_2O_3\xrightarrow[criolit]{đpnc}4Al+3O_2\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ Al+NaOH+H_2O\to NaAlO_2+\dfrac{3}{2}H_2\)

26 tháng 11 2023

\(a,4Al+3O_2\xrightarrow[t^0]{}2Al_2O_3\\ Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\xrightarrow[t^0]{}Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow[đpnc]{criolit}4Al+3O_2\\ b,3Fe+2O_2\xrightarrow[t^0]{}Fe_3O_4\\ Fe_3O_4+8HCl\rightarrow2FeCl_3+FeCl_2+4H_2O\\ FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\\ 2Fe\left(OH\right)_3\xrightarrow[t^0]{}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow[t^0]{}2Fe+3CO_2\)

\(c,2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\\ Fe_2\left(SO_4\right)_3+3BaCl_2\rightarrow2FeCl_3+3BaSO_4\\ FeCl_3+AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\)