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c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
{[(6,2:0,31-5/6.0,9).0,2+0,15]:0,2}:[(2+1/4/11.0,22:0,1).1/33]
={[(6,2:0,31-0,75).0,2+0,15]:0,2}:[(2+0,3:0,1).1/33]
={[19,25.0,2+0,15]:0,2}:[5.1/33]
={4:0,2}:5/33
=20:5/33
=132
a: \(=\left\{\left[\left(20-\dfrac{1}{4}\right)\cdot0.2\right]+\dfrac{3}{20}\right\}\cdot5:\left[\left(2+\dfrac{25}{11}\cdot\dfrac{22}{100}\cdot10\right)\cdot\dfrac{1}{33}\right]\)
\(=\left\{\left[\dfrac{79}{20}+\dfrac{3}{20}\right]\right\}\cdot5:\left[\dfrac{356}{55}\cdot\dfrac{1}{33}\right]\)
\(=\dfrac{82}{20}\cdot5:\dfrac{3856}{1815}\simeq104,516\)
b: \(=\dfrac{13}{30}+\dfrac{28}{45}\cdot\dfrac{5}{2}\cdot\left[\dfrac{5}{6}:\dfrac{53}{90}\right]\cdot\dfrac{53}{50}\)
\(=\dfrac{13}{30}+\dfrac{14}{9}\cdot\dfrac{3}{2}=\dfrac{83}{30}\)
a: \(=\left\{\left[\left(6.2:0.31-0.9\right)\cdot0.2+0.15\right]\cdot5\right\}:\left(2+1\cdot2,2\right)\)
\(=\left\{\left[\left(20-0.9\right)\cdot0.2+0.15\right]\cdot5\right\}:4.2\)
\(=3.97\cdot5:4.2=\dfrac{397}{84}\)
b: Bạn ghi lại đề đi bạn
