tim x biet : \(\frac{25-x}{56}=\frac{6}{16}\)
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8 tháng 4 2018
25 - x / 56 = 6/16
( 25 - x ) : 56 = 6/16
25 - x = 6/16 x 56
25 - x = 21
x = 25 - 21
x = 4
8 tháng 4 2018
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\frac{x}{56}=25-\frac{6}{16}\)
\(\frac{x}{56}=24\frac{5}{8}\)
\(\frac{x}{56}=24\frac{35}{56}\)
\(\frac{x}{56}=\frac{24\cdot56+35}{56}\)
\(\frac{x}{56}=\frac{1379}{56}\)
Vậy số cần tìm là \(1379\)
IA
28 tháng 2 2020
\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\cdot\frac{2}{9}=\frac{16}{9}\)
\(x-2011=8\)
\(x=2019\)
LT
28 tháng 2 2020
\(\frac{x-2011}{12}+\frac{x-2011}{20}+\frac{x-2011}{30}+\frac{x-2011}{42}+\frac{x-2011}{56}+\frac{x-2011}{72}=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{8}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\frac{2}{9}=\frac{16}{9}\)
\(x-2011=8\Rightarrow x=2019\)
LN
2 tháng 4 2017
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\frac{25-x}{56}=\frac{3}{8}\)
\(\frac{25-x}{56}=\frac{21}{56}\)
\(\Rightarrow25-x=21\)
\(\Rightarrow x=25-21\)
\(\Rightarrow x=4\)
Vậy x=4
2 tháng 4 2017
=>(25-x)16=6x56=280
25-x=17.5
x=7.5=15/2
vậy x=15/2
KH
2 tháng 4 2017
Theo đề ta có: \(\frac{25-x}{56}=\frac{6}{16}\)
Ta rút gọn: \(\frac{25-x}{56}=\frac{3}{8}\)
\(\Leftrightarrow\)25 -x . 8 = 56 . 3
\(\Rightarrow\)25 - x . 8 = 168
\(\Rightarrow\)25 - x = 168 : 8
\(\Rightarrow\)25 - x = 21
\(\Rightarrow\) - x = 21 - 25
\(\Rightarrow\) - x = -4
\(\Rightarrow\) x = 4
Vậy x = 4.
AK
8 tháng 4 2018
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\Rightarrow\frac{25-x}{56}=\frac{3}{8}\)
\(\Rightarrow\left(25-x\right).8=56.3\)
\(\Rightarrow25.8-8x=168\)
\(\Rightarrow200-8x=168\)
\(\Rightarrow8x=200-168\)
\(\Rightarrow8x=32\)
\(\Rightarrow x=32:8\)
\(\Rightarrow x=4\)
Tham khảo nha !!!
8 tháng 4 2018
Cách này dễ hơn nèk :
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\Leftrightarrow\)\(\frac{25-x}{56}=\frac{3}{8}\)
\(\Leftrightarrow\)\(\frac{25-x}{56}=\frac{21}{56}\)
\(\Leftrightarrow\)\(25-x=21\)
\(\Leftrightarrow\)\(x=25-21\)
\(\Leftrightarrow\)\(x=4\)
Vậy \(x=4\)
Chúc bạn học tốt ~
1 tháng 6 2020
\(\frac{8}{23}\cdot\frac{46}{24}-x=\frac{1}{3}\)
=> \(\frac{2}{3}-x=\frac{1}{3}\)
=> \(x=\frac{1}{3}\)
\(\frac{10}{12}\div x=\frac{28}{9}\cdot\frac{3}{56}\)
=> \(\frac{10}{12}\div x=\frac{1}{6}\)
=> \(x=\frac{60}{12}=5\)
\(\frac{x-12}{4}=\frac{1}{2}\)
=> \(\left(x-12\right)\cdot2=4\cdot1\)
=> \(2x-24=4\)
=> \(2x=28\)
=> \(x=14\)
CP
5
NT
2
CW
1 tháng 1 2017
\(\frac{x-3}{2013}+\frac{x-4}{2012}=\frac{x-5}{2011}+\frac{x-6}{2010}\)
\(\Leftrightarrow\frac{x-3-2013}{2013}+\frac{x-2-2012}{2012}=\frac{x-5-2011}{2011}+\frac{x-6-2010}{2010}\)(mỗi vế trừ đi 2)
\(\Leftrightarrow\frac{x-2016}{2013}+\frac{x-2016}{2012}-\frac{x-2016}{2011}-\frac{x-2016}{2010}=0\)
\(\Leftrightarrow\left(x-2016\right)\left(\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}\right)=0\)
Mà \(\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}\ne0\)
\(\Rightarrow x-2016=0\Leftrightarrow x=2016\)
TC
5 tháng 10 2019
Cộng mỗi vế cho 1
Ta có: \(\frac{x-3-2013}{2013}+\frac{x-4-2012}{2012}=\frac{x-5-2011}{2011}+\frac{x-6-2010}{2010}\)
\(=>\left(\frac{x-2016}{2013}+\frac{x-2016}{2012}\right)-\left(\frac{x-2016}{2011}+\frac{x-2016}{2010}\right)=0\)
\(=>\left(x-2016\right).\left(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2010}\right)\)
Mà \(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2010}\ne0\)
\(=>x-2016=0\\ =>x=2016\)
25-x/56 = 6/16
=> 2.(25-x)/112=7.6/112
=> 2.(25-x)= 42
=> 50 - 2x = 42
=> -2x = 50 - 42
=> -2x = 8
=> x = 8:(-2)
=> x = 4