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24 tháng 2 2023

mình hứa sẽ tick

24 tháng 2 2023

= 2/5 + 1/5 + 1/5

= 4/5

b. = 2/7 + 4/7 + 5/21

= 6/21 + 12/21 + 5/21

= 23/21

HT

2 tháng 6 2021

a. \(\frac{22}{55}\)\(\frac{25}{125}\)\(\frac{1020}{5100}\)

\(\frac{2}{5}\)\(\frac{1}{5}\)\(\frac{1}{5}\)

\(\frac{4}{5}\)

B. \(\frac{22}{77}\)\(\frac{56}{98}\)\(\frac{25}{105}\)

\(\frac{2}{7}\)\(\frac{4}{7}\)\(\frac{5}{21}\)

\(\frac{6}{7}\)\(\frac{5}{21}\)

\(\frac{23}{21}\)

2 tháng 6 2021

23/21 bn nhé

ai lớp 4 hoặc 5 kb mik nhé mik luôn sẵn sàng

20 tháng 2 2023

a)\(\dfrac{22}{25}+\dfrac{25}{125}+\dfrac{36}{96}\)
\(=\dfrac{22}{25}+\dfrac{1}{5}+\dfrac{3}{8}\)
\(=\dfrac{176}{200}+\dfrac{40}{200}+\dfrac{75}{200}\)
\(=\dfrac{291}{200}\)
b)\(\dfrac{22}{77}+\dfrac{56}{98}+\dfrac{25}{105}\)
\(=\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{5}{21}\)
\(=\dfrac{6}{7}+\dfrac{5}{21}\)
\(=\dfrac{18}{21}+\dfrac{5}{21}=\dfrac{23}{21}\)

20 tháng 2 2023

Ngu như con cặc

\(A=\left(\dfrac{15-\sqrt{x}}{x-25}+\dfrac{2}{\sqrt{x}+5}\right):\dfrac{\sqrt{x}+1}{\sqrt{x}-5}\)

\(=\dfrac{15-\sqrt{x}+2\sqrt{x}-10}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}\cdot\dfrac{\sqrt{x}-5}{\sqrt{x}+1}\)

\(=\dfrac{1}{\sqrt{x}+1}\)

9 tháng 9 2021

\(A=\left(\dfrac{15-\sqrt{x}}{x-25}+\dfrac{2}{\sqrt{x}+5}\right):\dfrac{\sqrt{x}+1}{\sqrt{x}-5}\left(x\ge0;x\ne25\right)\\ A=\dfrac{15-\sqrt{x}+2\left(\sqrt{x}-5\right)}{\left(\sqrt{x}-5\right)\left(\sqrt{x}+5\right)}\cdot\dfrac{\sqrt{x}-5}{\sqrt{x}+1}\\ A=\dfrac{5+\sqrt{x}}{\sqrt{x}+5}\cdot\dfrac{1}{\sqrt{x}+1}=\dfrac{1}{\sqrt{x}+1}\)

23 tháng 9 2021

\(C=\left(\dfrac{15-\sqrt{x}}{x-25}+\dfrac{2}{\sqrt{x}+5}\right):\dfrac{\sqrt{x}+1}{\sqrt{x}-5}\left(đk:x\ge0,x\ne25\right)\)

\(=\dfrac{15-\sqrt{x}+2\left(\sqrt{x}-5\right)}{\left(\sqrt{x}-5\right)\left(\sqrt{x}+5\right)}.\dfrac{\sqrt{x}-5}{\sqrt{x}+1}\)

\(=\dfrac{\sqrt{x}+5}{\left(\sqrt{x}-5\right)\left(\sqrt{x}+5\right)}.\dfrac{\sqrt{x}-5}{\sqrt{x}+1}=\dfrac{1}{\sqrt{x}+1}\)

23 tháng 9 2021

\(ĐK:x\ge0;x\ne25\)

\(C=\dfrac{15-\sqrt{x}+2\sqrt{x}-10}{\left(\sqrt{x}-5\right)\left(\sqrt{x}+5\right)}\cdot\dfrac{\sqrt{x}-5}{\sqrt{x}+1}\\ C=\dfrac{\sqrt{x}+5}{\left(\sqrt{x}+5\right)\left(\sqrt{x}+1\right)}=\dfrac{1}{\sqrt{x}+1}\)

5 tháng 2 2023

`x/7 = 22/77`

`=>77x= 22.7`

`=>77x= 154`

`=>x=154:77`

`=>x=2`

 

5 tháng 2 2023

\(\dfrac{2}{7}\)\(\dfrac{22}{77}\)

7 tháng 4 2022

a)\(\dfrac{56}{70}=\dfrac{56:14}{70:14}=\dfrac{4}{5}\)

b)\(\dfrac{-120}{86}=\dfrac{-120:2}{86:2}=-\dfrac{60}{43}\)

c)\(\dfrac{915+85}{1017-117}=\dfrac{1000}{900}=\dfrac{10}{9}\)

d)\(\dfrac{3838}{5454}=\dfrac{19}{27}\)

7 tháng 4 2022

a) \(\dfrac{56}{70}=\dfrac{4}{5}\)

\(b,-\dfrac{120}{86}=-\dfrac{60}{43}\)

\(c,\dfrac{10}{9}\)

\(d,\dfrac{19}{27}\)

\(P=\dfrac{32}{64}\cdot\dfrac{-57}{19}+\dfrac{35}{21}\cdot\dfrac{22}{44}=\dfrac{1}{2}\left(-3+\dfrac{5}{3}\right)=\dfrac{1}{2}\cdot\dfrac{-4}{3}=\dfrac{-2}{3}\)

\(Q=\dfrac{75}{125}\cdot\dfrac{82}{164}+\dfrac{49}{98}\cdot\dfrac{-35}{105}=\dfrac{1}{2}\left(\dfrac{3}{5}-\dfrac{1}{3}\right)=\dfrac{1}{2}\cdot\dfrac{4}{15}=\dfrac{2}{15}\)

\(=5\left(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}\right)\)

\(=5\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{7}-\dfrac{1}{8}\right)\)

\(=5\cdot\dfrac{5}{24}=\dfrac{25}{24}\)

10 tháng 2 2023

`5/12 + 5/20 + 5/30 + 5/42 + 5/56`

`= 5/(3.4) + 5/(4.5) + 5/(5.6) + 5/(6.7) + 5/(7.8)`

`= 5 . (1/(3.4) + 1/(4.5) + ... + 5/(7.8))`

`= 5 . (1/3 - 1/4 + 1/4 - 1/5 + ...+ 1/7 - 1/8)`

`= 5 . (1/3 - 1/8) `

`= 5 . 5/24 = 25/24`