bài 19: tìm xc) ( 34 - 2x ) . ( 2x - 6 ) = 0d) ( 2019 - x ) . ( 3x - 12 ) 0e) 57 . ( 9x - 27 ) = 0f) 25 ( 15 - x ) = 30g) 43 - ( 24 - x ) = 20h) 2 . ( x - 5 ) - 17 = 25i) 3 . ( x 7 ) - 15 = 27j) 1...

bài 19: tìm x c) ( 34 - 2x ) . ( 2x - 6 ) = 0 d) ( 2019 - x ) . ( 3x - 12 ) 0 e) 57 . ( 9x - 27 ) = 0 f) 25 + ( 15 - x ) = 30 g) 43 - ( 24 - x ) = 20 h) 2 . ( x - 5 ) - 17 = 25 i) 3 . ( x + 7 ) - 15 = 27 j) 15 + 4 . ( x - 2 ) = 95 k) 20 - ( x + 14 ) = 5 l) 14 + 3 . ( 5 - x ) = 27 nhanh nha, mik tick cho, ccau trình bày dễ hiểu, ko cần...

1

H9

HT.Phong (9A5)

9 tháng 7 2023

c) \(\left(34-2x\right)\left(2x-6\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6-0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

d) \(\left(2019-x\right)\left(3x-12\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

e) \(57\left(9x-27\right)=0\)

\(\Rightarrow9x-27=0\)

\(\Rightarrow9\left(x-3\right)=0\)

\(\Rightarrow x-3=0\)

\(\Rightarrow x=3\)

f) \(25+\left(15-x\right)=30\)

\(\Rightarrow25+15-x=30\)

\(\Rightarrow40-x=30\)

\(\Rightarrow x=40-30\)

\(\Rightarrow x=10\)

g) \(43-\left(24-x\right)=20\)

\(\Rightarrow43-24+x=20\)

\(\Rightarrow19+x=20\)

\(\Rightarrow x=20-19\)

\(\Rightarrow x=1\)

h) \(2\left(x-5\right)-17=25\)

\(\Rightarrow2\left(x-5\right)=17+25\)

\(\Rightarrow x-5=21\)

\(\Rightarrow x=21+5\)

\(\Rightarrow x=26\)

i) \(3\left(x+7\right)-15=27\)

\(\Rightarrow3\left(x+7\right)=27+15\)

\(\Rightarrow x+7=14\)

\(\Rightarrow x=14-7\)

\(\Rightarrow x=7\)

j) \(15+4\left(x-2\right)=95\)

\(\Rightarrow4\left(x-2\right)=95-15\)

\(\Rightarrow4\left(x-2\right)=80\)

\(\Rightarrow x-2=20\)

\(\Rightarrow x=20+2\)

\(\Rightarrow x=22\)

k) \(20-\left(x+14\right)=5\)

\(\Rightarrow x+14=20-5\)

\(\Rightarrow x+14=15\)

\(\Rightarrow x=15-14\)

\(\Rightarrow x=1\)

l) \(14+3\left(5-x\right)=27\)

\(\Rightarrow3\left(5-x\right)=27-14\)

\(\Rightarrow3\left(5-x\right)=13\)

\(\Rightarrow5-x=\dfrac{13}{3}\)

\(\Rightarrow x=5-\dfrac{13}{3}\)

\(\Rightarrow x=\dfrac{2}{3}\)

Đúng(2)

PP

Phượng Phạm

9 tháng 7 2023

2

KT

『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』

9 tháng 7 2023

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) . ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`( 2019 - x ) . ( 3x - 12 ) =0` `?`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}`

`e) `

`57 . ( 9x - 27 ) = 0`

`=>`\(9x-27=0\div57\)

`=> 9x - 27 = 0`

`=> 9x = 27`

`=> x = 27 \div 9`

`=> x = 3`

Vậy, `x = 3`

`f)`

`25 + ( 15 - x ) = 30`

`=> 15 - x = 30 - 25`

`=> 15 - x = 5`

`=> x = 15 -5 `

`=> x = 10`

Vậy, `x = 10`

`g) `

`43 - ( 24 - x ) = 20`

`=> 24 - x = 43 - 20`

`=> 24 - x = 23`

`=> x = 24 - 23`

`=> x = 1`

Vậy, `x = 1`

`h) `

`2 . ( x - 5 ) - 17 = 25`

`=> 2 ( x - 5) = 25+17`

`=> 2 ( x - 5) = 42`

`=> x - 5 = 42 \div 2`

`=> x - 5 = 21`

`=> x = 21 + 5`

`=> x = 26`

Vậy, `x = 26`

`i)`

`3 . ( x + 7 ) - 15 = 27`

`=> 3(x + 7) = 27 + 15`

`=> 3(x + 7) = 42`

`=> x +7 = 42 \div 3`

`=> x + 7 = 14`

`=> x = 14 - 7`

`=> x = 7`

Vậy, `x = 7`

`j)`

`15 + 4 . ( x - 2 ) = 95`

`=> 4(x - 2) = 95 - 15`

`=> 4(x - 2) = 80`

`=> x - 2 = 80 \div 4`

`=> x - 2 = 20`

`=> x = 20 + 2`

`=> x = 22`

Vậy, `x = 22`

`k)`

`20 - ( x + 14 ) = 5`

`=> x + 14 = 20 - 5`

`=> x + 14 = 15`

`=> x = 15 - 14`

`=> x = 1`

Vậy, `x = 1`

`l) `

`14 + 3 . ( 5 - x ) = 27`

`=> 3(5 - x) = 27 - 14`

`=> 3(5 - x) = 13`

`=> 5 - x = 13 \div 3`

`=> 5 - x = 13/3`

`=> x = 5- 13/3`

`=> x = 2/3`

Vậy, `x = 2/3.`

`@` `\text {Kaizuu lv uuu}`

Đúng(1)

PP

Phượng Phạm

9 tháng 7 2023

nhanh mik tick cho nha

PP

Phượng Phạm

8 tháng 7 2023

bài 19: tìm x

a) 5 . ( x - 7 ) = 0

b) 25 ( x - 4 ) = 0

c) ( 34 - 2x ) . ( 2x - 6 ) = 0

d) ( 2019 - x ) . ( 3x - 12 ) 0

e) 57 . ( 9x - 27 ) = 0

f) 25 + ( 15 - x ) = 30

g) 43 - ( 24 - x ) = 20

h) 2 . ( x - 5 ) - 17 = 25

i) 3 . ( x + 7 ) - 15 = 27

j) 15 + 4 . ( x - 2 ) = 95

k) 20 - ( x + 14 ) = 5

l) 14 + 3 . ( 5 - x ) = 27

2

H9

HT.Phong (9A5)

8 tháng 7 2023

a) \(5\left(x-7\right)=0\)

\(\Rightarrow x-7=0\)

\(\Rightarrow x=7\)

b) \(25\left(x-4\right)=0\)

\(\Rightarrow x-4=0\)

\(\Rightarrow x=4\)

c) \(\left(34-2x\right)\left(2x-6\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

d) \(\left(2019-x\right)\left(3x-12\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)

e) \(57\left(9x-27\right)=0\)

\(\Rightarrow9x-27=0\)

\(\Rightarrow9\left(x-3\right)=0\)

\(\Rightarrow x-3=0\)

\(\Rightarrow x=3\)

ND

Nguyễn Đức Trí

VIP

8 tháng 7 2023

a) 5.(x-7)=0⇔x-7=0⇔x=7

b) 25(x-4)=0⇔x-4=0⇔x=4

c) (34-2x).(2x-6)=0

⇔ 34-2x=0 hoặc 2x-6=0

⇔2x=34 hoặc 2x=6

⇔ x=17 hoặc x=3

d) (2019-x).(3x-12)=0

⇔ 2019-x=0 hoặc 3x-12=0

⇔ x=2019 hoặc x=4

e) 57.(9x-27)=0

⇔ 9x-27=0

⇔ x=3

f) 25+(15-x)=30

⇔ 15-x=5

⇔ x=10

g) 43-(24-x)=20

⇔ 24-x=23

⇔ x=1

h) 2.(x-5)-17=25

⇔ 2(x-5)=42

⇔x-5=21

⇔ x=26

i) 3(x+7)-15=27

⇔ 3(x+7)=42

⇔ x+7=14

⇔ x=7

j) 15+4(x-2)=95

⇔ 4(x-2)=80

⇔ x-2=20

⇔ x=22

k) 20-(x+14)=5

⇔ x+14=15

⇔ x=1

l) 14+3(5-x)=27

⇔ 3(5-x)=13

⇔ 5-x=13/3

⇔ x=5-13/3

⇔ x=2/3

AN

Ánh Ngọc

9 tháng 2 2020

tìm x

17x – ( -16x – 37) = 2x +

-2x –3. (x – 17) = 34 – 2(-x + 25

17x + 3. ( -16x – 37) = 2x + 43 - 4x

103 -57: [-2. (2x – 1)2 – (-9)0] = -106

3x – 32 > -5x + 1

15 + 4x < 2x – 145

-3. (2x + 5) -16 < -4. (3 – 2x)

-2x + 15 < 3x – 7 < 19 – x

x + (x+1) + (x+2) + (x+3) + .... + 13 + 14 = 14

25 + 24 + 23 +...+ x + (x - 2) + (x – 3) = 25

7

GL

ღ๖ۣۜLinh's ๖ۣۜLinh'sღ] ★we are one★

9 tháng 2 2020

17x + 3. ( -16x – 37) = 2x + 43 - 4x

<=>17x-48x-111=-2x+43

<=>-29x=154

<=> \(x=-\frac{154}{29}\)

GL

ღ๖ۣۜLinh's ๖ۣۜLinh'sღ] ★we are one★

9 tháng 2 2020

-3. (2x + 5) -16 < -4. (3 – 2x)

\(\Leftrightarrow-6x-31< -12+8x.\)

\(\Leftrightarrow-14x< 19\Rightarrow x< -\frac{19}{14}\)

NT

nguyen thanh thao

24 tháng 1 2017

Câu 1:

a) -2x-(x-17)=34-(-x+25)

b) 17x-(-16x-27)=2x+43

c) -2x-3(x-17)=34-2(-x+25)

d) 17x+3(-16x-37)=2x+43-4x

e) 3x-32>-5x+1

f)15+4x<2x-145

g)-3(2x+5)-16<-4(3-2x)

h) -2x+15<3x-7<19-x

i)x+(x+1)+(x+2)+(x+3)+....+13+14=14

j)25+24+23+...+x+(x-2)+(x-3)=25

Câu 2:

a) (x-3).(y+5)=-17

b) (x+1).(xy-2)=11

c) xy-7x+y=-22

d) xy-3x+y=-20

1

NL

Nguyễn Lê Phước Thịnh

10 tháng 4 2022

Câu 1:

a: =>-2x-x+17=34+x-25

=>-3x+17=x+9

=>-4x=-8

hay x=2

b: =>17x+16x+27=2x+43

=>33x+27=2x+43

=>31x=16

hay x=16/31

c: =>-2x-3x+51=34+2x-50

=>-5x+51=2x-16

=>-7x=-67

hay x=67/7

e: 3x-32>-5x+1

=>8x>33

hay x>33/8

VT

Vũ Trung Khang

16 tháng 2 2020

tìm số nguyên x

-2x-(x-17)=34-(-x+25)

17x-(16x-37)=2x+43

-2x-3(x+17)=34-2(-x+25)

17x+3(16x-37)=2x+43-14x

-2x+15<3x-7<19-x

25+24+23+.....+x+(x-2)+(x-3)

nhanh lên nha

2

M

Monsmoke

29 tháng 2 2020

không ai làm nhỉ

2U

๖²⁴ʱんuﾘｲú❄✎﹏

4 tháng 3 2020

\(-2x-\left(x-17\right)=34-\left(-x+25\right)\)

\(-2x-x+17=34+x-25\)

\(-2x-x-x=34-25-17\)

\(-4x=-8\Leftrightarrow x=2\)

\(17x-\left(16x-37\right)=2x+43\)

\(17x-16x+37=2x+43\)

\(17x-16x-2x=-37+43\)

\(-x=6\Leftrightarrow x=6\)

\(-2x-3\left(x+17\right)=34-2\left(-x+25\right)\)

\(-2x-3x-51=34+2x-50\)

\(-2x-3x-2x=34-50+51\)

\(-7x=35\Leftrightarrow x=-5\)

KH

khánh huyền

30 tháng 7 2021

Bài 1: Tìm x

a) (2x-1) ² - 25 = 0
b) 3x (x-1) + x - 1 = 0
c) 2(x+3) - x ² - 3x = 0
d) x(x - 2) + 3x - 6 = 0
e) 4x ² - 4x +1 = 0
f) x +5x ² = 0
g) x ² 2x -3 = 0

#Toán lớp 8

4

PS

Phía sau một cô gái

30 tháng 7 2021

a) \(\left(2x-1\right)^2-25=0\)

⇔ \(\left(2x-1\right)^2-5^2=0\)

⇔ \(\left(2x-1-5\right)\left(2x-1+5\right)=0\)

⇒ \(2x-1-5=0\) hoặc \(2x-1+5=0\)

⇔ \(x=3\) hoặc \(x=-2\)

Bài 6: Tìm số nguyên x, biếtA, 3 – (17 – x) = 289 – (36 + 289)B, 25 – (x + 5) = -415 – (15 – 415)C, 34 + (21 – x) = (3747 – 30) – 3746D, -2x – (x – 17) = 34 – (-x + 25)E, 17x + (-16x – 37) = 2x + 43G, (x + 12). (x – 3) = 0H, (-x + 5). (3 – x) = 0K, -28 – 7. |-3x + 15| = - 70M, 12 – 2. (-x + 3)2 = - 38N, - {-3x + 2. [45 – x – 3. (3x + 7) – 2x] + 4x} = 55Bài 7: So sánhA, (-99). 98. (-97) với 0B, (-5). (-4). (-3). (-2). (-1) với 0C, (-245)....

TC

Thùy Cái

30 tháng 7 2021

Bài 1: Tìm x

a) (2x-1) ² - 25 = 0

<=> (2x-1)² = 25

<=> 2x-1 = 5 hay 2x-1 =-5

<=> 2x= 6 hay 2x=-4

<=> x=3 hay x= -2

Vậy S={3; -2}
b) 3x (x-1) + x - 1 = 0

<=> (x-1)(3x+1)=0

<=> x-1=0 hay 3x+1=0

<=> x=1 hay 3x=-1

<=> x=1 hay x=\(\dfrac{-1}{3}\)

Vậy S={1;\(\dfrac{-1}{3}\)}

c) 2(x+3) - x ² - 3x = 0

<=> 2(x+3)- x(x+3)=0

<=> (x+3)(2-x)=0

<=> x+3=0 hay 2-x=0

<=> x=-3 hay x=2

Vậy S={-3;2}
d) x(x - 2) + 3x - 6 = 0

<=> x(x-2)+3(x-2)=0

<=> (x-2)(x+3)=0

<=> x-2=0 hay x+3=0

<=> x=2 hay x=-3

Vậy S={2;-3}
e) 4x ² - 4x +1 = 0

<=> (2x-1)²=0

<=> 2x-1=0

<=> 2x=1

<=> x=\(\dfrac{1}{2}\)

Vậy S={\(\dfrac{1}{2}\)}
f) x +5x² = 0

<=> x(1+5x)=0

<=>x=0 hay 1+5x=0

<=> x=0 hay 5x=-1

<=> x=0 hay x= \(\dfrac{-1}{5}\)

Vậy S={0;\(\dfrac{-1}{5}\)}
g) x ²+ 2x -3 = 0

<=> x²-x+3x-3=0

<=> x(x-1)+3(x-1)=0

<=> (x-1)(x+3)=0

<=> x-1=0 hay x+3=0

<=> x=1 hay x=-3

Vậy S={1;-3}

Đúng(1)

NN

Nguyễn Ngọc Anh

31 tháng 1 2019

2

NT

nguyễn tuấn thảo

31 tháng 1 2019

A , 3 - ( 17 - x ) = 289 - ( 36 + 289 )

3 - 17 + x = 0 - 36

-14 + x = -36

x = -36 - ( - 14 ) = -22

B, 25 - ( x + 5 ) = -415 - ( 15 - 415 )

25 - x - 5 = 0 - 15

20 - x = -15

x = 20 - ( - 15 ) = 35

C , 34 + ( 21 - x ) = ( 3747 - 30 ) - 3746

34 + 21 - x = 1 - 30

55 - x = -29

x = 55 - (-29 ) = 74

NT

nguyễn tuấn thảo

31 tháng 1 2019

D , -2x - ( x -17 ) = 34 - ( -x + 25 )

- 2x - x + 17 = 34 - 25 + x

- 3x + 17 = 9 + x

- 3x - x = 9 - 17

-4x = -8

x = -8 : ( - 4 )

x = 2

E , 17x + ( -16x - 37 ) = x + 43

17x - 16x -37 = x + 43

x - 37 = x + 43

-37 - 43 = x - x

- 80 = 0 ( vô lý )

G , ( x + 12 ) . (x - 3 ) = 0

\(\hept{\begin{cases}x+12=0\\x-3=0\end{cases}}\)

\(\hept{\begin{cases}x=-12\\x=3\end{cases}}\)

Đề bài: Tìm số nguyên xa)-2x – (x – 17) = 34 – (-x + 25)b)17x – ( -16x – 37) = 2x + 43c)-2x –3. (x – 17) = 34 – 2(-x + 25)d)17x + 3. ( -16x – 37) = 2x + 43 - 4xe){-3x+ 2. [45 - x - 3(3x+7) -2x]+4x}= -48 g)-57: [-2. (2x – 1)2 – (-9)0] = -106h)-2x + 3. i)3x – 32 > -5x + 1k)15 + 4x < 2x – 145l)-3. (2x + 5) -16 < -4. (3 – 2x)m)-2x + 15 < 3x – 7 < 19 – xn)x + (x+1) + (x+2) + (x+3) + .... + 13 + 14 = 14p)25 + 24 + 23 +...+ x + (x - 2) + (x – 3) = 25 ...

PT

Phung Tuan Anh

11 tháng 2 2020

0

VN

vân nguyễn

28 tháng 7 2021

tìm x biết:

a) x - 3= (3 - x)^2

b) x^3 + 3/2x^2 + 3/4x + 1/8 = 1/64

c) 8x^3 - 50x = 0

d) (x - 2) (x^2 + 2x + 7) + 2(x^2 - 4) - 5(x - 2) = 0

e) x(x + 3) - x^2 - 3x = 0

f) x^3 + 27 + (x + 3) (x - 9) = 0

Giúp mik vs ạ

#Toán lớp 8

2

NL

Nguyễn Lê Phước Thịnh

29 tháng 7 2021

a) Ta có: \(\left(x-3\right)=\left(3-x\right)^2\)

\(\Leftrightarrow\left(x-3\right)^2-\left(x-3\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\)

b) Ta có: \(x^3+\dfrac{3}{2}x^2+\dfrac{3}{4}x+\dfrac{1}{8}=\dfrac{1}{64}\)

\(\Leftrightarrow x^3+3\cdot x^2\cdot\dfrac{1}{2}+3\cdot x\cdot\dfrac{1}{4}+\left(\dfrac{1}{2}\right)^3=\dfrac{1}{64}\)

\(\Leftrightarrow\left(x+\dfrac{1}{2}\right)^3=\left(\dfrac{1}{4}\right)^3\)

\(\Leftrightarrow x+\dfrac{1}{2}=\dfrac{1}{4}\)

hay \(x=-\dfrac{1}{4}\)

c) Ta có: \(8x^3-50x=0\)

\(\Leftrightarrow2x\left(4x^2-25\right)=0\)

\(\Leftrightarrow x\left(2x-5\right)\left(2x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\)