Question

[Nguyễn Gia BảoB]

Thực hiện phép chia sau :
a,\(x^6+x^7-x^9:x\)                  g,\(\left(x^2+5x-6\right):\left(x-1\right)\)
b, \(6x^4+4x^3+8x^2:2x^3\)        f, \(\left(x^2+4x-3\right):\left(x-3\right)\)
c,\(14x^4+21x^5-7x^7:x^3\)       h, \(\left(x^2+4x-7\right):\left(x-2\right)\)
d,\(\left(-x^2+4x\right):\left(x-4\right)\)          i,\(\left(x^3+5x^2+11x+10\right):\left(x+2\right)\)
e,\(\left(x^2+x-12\right):\left(x-3\right)\)

 

Answer 1

[HT.Phong (9A5)]

\(a)\left(x^6+x^7-x^9\right):x\\ =x^6:x+x^7:x-x^9:x\\ =x^5+x^6x^8\\ b)\left(6x^4+4x^3+8x^2\right):2x^2\\ =6x^4:2x^2+4x^3:2x^2+8x^2:2x^2\\ =3x^2+2x+4\\ c)\left(14x^4+21x^5+7x^7\right):x^3\\ =14x^4:x^3+21x^5:x^3+7x^7:x^3\\ =14x+21x^2+7x^4\\ d)\left(-x^2+4x\right):\left(x-4\right)\\ =-x\left(x-4\right):\left(x-4\right)\\ =-x\)

Answer 2

[HT.Phong (9A5)]

\(e)\left(x^2+x-12\right):\left(x-3\right)\\ =\left(x^2-3x+4x-12\right):\left(x-3\right)\\ =\left[x\left(x-3\right)+4\left(x-3\right)\right]:\left(x-3\right)\\ =\left(x-3\right)\left(x+4\right):\left(x-3\right)\\ =x+4\\ g)\left(x^2+5x-6\right):\left(x-1\right)\\ =\left(x^2-x+6x-6\right):\left(x-1\right)\\ =\left[x\left(x-1\right)+6\left(x-1\right)\right]:\left(x-1\right)\\ =\left(x+6\right)\left(x-1\right):\left(x-1\right)\\ =x+6\\ i)\left(x^3+5x^2+11x+10\right):\left(x+2\right)\\ =\left(x^3+2x^2+3x^2+6x+5x+10\right):\left(x+2\right)\\ =\left[x^2\left(x+2\right)+3x\left(x+2\right)+5\left(x+2\right)\right]:\left(x+2\right)\\ =\left(x^2+3x+5\right)\left(x+2\right):\left(x+2\right)\\ =x^2+3x+5\)

(xem lại đề câu f vs h)