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232 x 68 + 232 x 31 + 232
= 232 x ( 68 + 31 + 1 )
= 232 x 100
= 23200
\(\frac{1-\frac{6}{23}+\frac{6}{31}-\frac{6}{154}}{\frac{5}{2}-\frac{15}{23}+\frac{15}{31}-\frac{15}{154}}\)
\(=\frac{\frac{6}{6}-\frac{6}{23}+\frac{6}{31}-\frac{6}{154}}{\frac{15}{6}-\frac{15}{23}+\frac{15}{31}-\frac{15}{154}}\)
\(=\frac{6\left(\frac{1}{6}-\frac{1}{23}+\frac{1}{31}-\frac{1}{154}\right)}{15\left(\frac{1}{6}-\frac{1}{23}+\frac{1}{31}-\frac{1}{154}\right)}\)
\(=\frac{6}{15}=\frac{2}{5}\)
mk sửa đề tí nhé
\(M=\frac{2.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{23}\right)}{-5.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{23}\right)}+\frac{\frac{1}{17}-\frac{1}{23}+\frac{1}{31}}{3.\left(\frac{1}{17}-\frac{1}{23}+\frac{1}{31}\right)}=-\frac{2}{5}+\frac{1}{3}=\frac{1}{15}.\)
a) 67+135+33
= ( 67+33)+135
= 100 + 135
= 235
b) 146+121+54+379
= ( 146+54)+( 121+379)
= 200 + 500
= 700
c) 198+232-98-32
= ( 232-32)+(198-98)
= 200 + 100
= 300
d)1+2+3+4+.........+50
= ( 50+1) x 50:2 =1275
e)2+4+6+8+..........+100
= ( 100+2) x 50 : 2 =2550
f) 23 x 56 +56
= 1288 + 56
= 1344
g)32 x 19+32
= 608 + 32
= 640
\(a.67+135+33\)
\(=\left(67+33\right)+135\)
\(=100+135=235\)
\(b.141+121+54+379\)
\(=\left(146+54\right)+\left(121+379\right)\)
\(=200+500=700\)
\(c.198+232-98-32\)
\(=\left(232-32\right)+\left(198-98\right)\)
\(=200+100=300\)
\(f.23.56+56=1288+56=1344\)
\(g.32.19+32=608+32=640\)
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