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a) 7.x - x = 521 : 519 + 3.22 - 70
6x = 25 + 12 - 1
6x = 36
x = 6
b) 7x - 2x = 617 : 615 + 44 : 11
5x = 36 + 4
5x = 40
x = 8
c) 5x + x = 39 - 311 : 39
6x = 39 - 9
6x = 30
x = 5
d) [(6x - 39) : 7]. 4 = 12
(6x - 39) : 7 = 12 : 4
(6x - 39) : 7 = 3
6x - 39 = 3 . 7
6x - 39 = 21
6x = 21 + 39
6x = 60
x = 10
x =
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Bài 9,
62x73+36x33=36x73+36x27=36(73+27)=36x100=3600.
197-\([\)6x(5-1)2+20220\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.
Bài 10,
21-4x=13
=>4x=21-13=8
=>x=8:4=2.
30:(x-3)+1=45:43=42=16
=>30:(x-3)=16-1=15
=>x-3=30:15=2
=>x=2+3=5.
(x-1)3+5x6=38
=>(x-1)3+30=38
=>(x-1)3=38-30=8=23
=>x-1=2
=>x=3.
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a) x(x+1)=2+4+6+8+...+2500
x(x+1)=(2500+2).1250:2
x(x+1)=1563750
Ta thấy: x và x+1 là 2 số liên tiếp
Mà x(x+1)=1563750=>x=1250;x+1=1251
Vậy x=1250
b) x-3=12:{390:[500-(5^3+7^2.5)]}
x-3=12:[390:(500-254.64)]
x-3=12:(390:245.35)
x-3=12:1.58
x-3=7.54
=>x=10.5
Vậy x=10.5
c) x+3^3.12=3^3.19
=>x=2.46
Vậy x=2.46
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1/ -7264 + (1543 + 7264)
=-7264 + 1543 + 7264=1543
2/ (144 – 97) – 144
=144-97-144=-97
3/ (-145) – (18 – 145)(Vì có dấu trừ ở trước ngoặc nên p đổi dấu)
=-145-18+145=-18
4/ 111 + (-11 + 27)
=111-11+27=137
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a, Bội (6) = {0; 6}
b, Số đối của: -4 = 4 ; 0 = 0
c, \(3^2+10:2=9+10:2=9+5=14\)
Câu 2:
\(\left(15-\left[3^{20}:3^{19}+2022^0\right]\right):11=\left(15-\left[3^{20-19}+1\right]\right):11=\left(15-\left[3^1+1\right]\right):11\)
\(=\left(15-4\right):11=11:11=1\)
Câu 3:
\(2x-7=39\)
\(2x=39+7\)
\(2x=46\)
\(x=46:2\)
\(x=23\)
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\(\text{7x - x = 5}^{21}:5^{19}+3.2^2-7^0\)
\(\text{(7-1)x=5}^2\text{ + 3. 4 - 1}\)
\(\text{6x = 25 + 12 - 1}\)
\(\text{6x = 36}\)
\(\text{ x = 6}\)
a)7.x-x=521 :519 +3.22 -70
x.(7-1)=52+12-1
x.6 =36
x =36:6=6
b)7.x-2.x=617:615+44:11
x.(7-2)=62+4
x.5 =40
x=40:5=8
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\(a,\left(-5\right).\left|x\right|=-75\)
\(\left|x\right|=\frac{-75}{-5}=15\)
\(\Rightarrow\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
Vậy....
\(b,\left(-6\right)^3.x^2=-1944\)
\(-216.x^2=-1944\)
\(x^2=9\)
\(\Rightarrow x=\pm3\)
Vậy....
\(d,\left|9-x\right|=-7+64\)
\(\left|9-x\right|=57\)
\(\Rightarrow\orbr{\begin{cases}9-x=57\\9-x=-57\end{cases}\Rightarrow\orbr{\begin{cases}x=-48\\x=66\end{cases}}}\)
Vậy...
\(e,\left|x+101\right|-\left(-16\right)=\left(-43\right).\left(-5\right)\)
\(\left|x+101\right|+16=215\)
\(\left|x+101\right|=199\)
\(\Rightarrow\orbr{\begin{cases}x+101=199\\x+101=-199\end{cases}\Rightarrow\orbr{\begin{cases}x=98\\x=-300\end{cases}}}\)
Vậy..
hok tốt!!
a,\(\left(-5\right).\left|x\right|=-75\)
\(=>\left|x\right|=-75:\left(-5\right)=15\)
\(=>\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
b,\(\left(-6\right)^3.x^2=-1944\)
\(=>\frac{1944}{216}=x^2\)
\(=>x=\sqrt{\frac{1944}{216}}=3\)
\(=\dfrac{-2}{3}\cdot\dfrac{12}{19}-\dfrac{2}{3}\cdot\dfrac{7}{19}+1\)
=-2/3(12/19+7/19)+1
=1-2/3
=1/3