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a; \(\dfrac{-7}{13}\) + 2 + \(\dfrac{-6}{13}\)
= -(\(\dfrac{7}{13}\) + \(\dfrac{6}{13}\)) + 2
= - 1 + 2
= 1
B; \(\dfrac{-8}{17}\) + \(\dfrac{7}{8}\) + \(\dfrac{-9}{17}\)
= -(\(\dfrac{8}{17}\) + \(\dfrac{9}{17}\)) + \(\dfrac{7}{8}\)
= - 1 + \(\dfrac{7}{8}\)
= - \(\dfrac{1}{8}\)
c;\(\dfrac{-7}{11}\) + \(\dfrac{3}{23}\) + \(\dfrac{7}{14}\) + \(\dfrac{-3}{23}\) + \(\dfrac{-1}{5}\)
= (\(\dfrac{3}{23}\) + \(\dfrac{-3}{23}\)) - (\(\dfrac{7}{11}\) + \(\dfrac{1}{5}\)) + \(\dfrac{7}{14}\)
= - \(\dfrac{46}{55}\) + \(\dfrac{7}{14}\)
= - \(\dfrac{37}{110}\)
a) \(\dfrac{-7}{13}+2+\dfrac{-6}{13}\)
\(=\left(\dfrac{-7}{13}+\dfrac{-6}{13}\right)+2\)
\(=\dfrac{-13}{13}+2\)
\(=-1+2\)
\(=1\)
b) \(\dfrac{-8}{17}+\dfrac{7}{8}+\dfrac{-9}{17}\)
\(=\left(\dfrac{-8}{17}+\dfrac{-9}{17}\right)+\dfrac{7}{8}\)
\(=\dfrac{-17}{17}+\dfrac{7}{8}\)
\(=-1+\dfrac{7}{8}\)
\(=\dfrac{-8}{8}+\dfrac{7}{8}=\dfrac{-1}{8}\)
c) \(\dfrac{-7}{11}+\dfrac{3}{23}+\dfrac{7}{14}+\dfrac{-3}{23}+\dfrac{-1}{5}\)
\(=\left(\dfrac{3}{23}+\dfrac{-3}{23}\right)+\dfrac{-7}{11}+\dfrac{1}{2}+\dfrac{-1}{5}\)
\(=\dfrac{0}{23}+\dfrac{-7}{11}+\dfrac{1}{2}+\dfrac{-1}{5}\)
\(=\dfrac{-7}{11}+\dfrac{1}{2}+\dfrac{-1}{5}\)
\(=\dfrac{-14}{22}+\dfrac{11}{22}+\dfrac{-1}{5}\)
\(=\dfrac{-3}{22}+\dfrac{-1}{5}\)
\(=\dfrac{-15}{110}+\dfrac{-22}{110}=\dfrac{-37}{110}\)
a: -9/20=-36/320
17/320=17/320
b: -7/10=-231/330
1/33=10/330
c: -5/15=-1/3=-140/420
3/20=63/420
9/70=54/420
d: 10/42=5/21=20/84
-3/28=-9/84
-55/132=-5/12=-35/84
a) \(\dfrac{2}{3}\) của \(8,7\) là: \(\dfrac{2}{3}.8,7=\dfrac{29}{5}\)
b) \(\dfrac{2}{7}\) của \(\dfrac{-11}{6}\) là: \(\dfrac{2}{7}.\dfrac{-11}{6}=\dfrac{-11}{21}\)
c) \(2\dfrac{1}{3}\) của \(5,1\) là: \(5,1.2\dfrac{1}{3}=\dfrac{51}{10}.2\dfrac{1}{3}=\dfrac{119}{10}=11,9\)
d) \(2\dfrac{7}{11}\) của \(6\dfrac{3}{5}\) là: \(2\dfrac{7}{11}.6\dfrac{3}{5}=\dfrac{29}{11}.\dfrac{33}{5}=\dfrac{87}{5}\)
a) \(\dfrac{2}{3}\) của \(8,7\) là: \(\dfrac{2}{3}.8,7=\dfrac{29}{5}\)
b) \(\dfrac{2}{7}\) của \(\dfrac{-11}{6}\) là: \(\dfrac{2}{7}.\dfrac{-11}{6}=\dfrac{-11}{21}\)
c) \(2\dfrac{1}{3}\) của \(5,1\) là: \(5,1.2\dfrac{1}{3}=\dfrac{51}{10}.2\dfrac{1}{3}=\dfrac{119}{10}=11,9\)
d) \(2\dfrac{7}{11}\) của \(6\dfrac{3}{5}\) là: \(2\dfrac{7}{11}.6\dfrac{3}{5}=\dfrac{29}{11}.\dfrac{33}{5}=\dfrac{87}{5}\)
1) \(\dfrac{3}{2}\) : \(\dfrac{9}{4}\) =\(\dfrac{3}{2}\)x\(\dfrac{4}{9}\)=\(\dfrac{12}{18}\)=\(\dfrac{2}{3}\)
2)\(\dfrac{48}{55}\) : \(\dfrac{12}{11}\)= \(\dfrac{48}{55}\) x\(\dfrac{11}{12}\)= \(\)\(\dfrac{528}{660}\)=\(\dfrac{4}{5}\)
3)\(\dfrac{7}{10}\) : \(\dfrac{7}{5}\)=\(\dfrac{7}{10}\) x \(\dfrac{5}{7}\)= \(\dfrac{35}{70}\)=\(\dfrac{1}{2}\)
4)\(\dfrac{6}{7}\) : \(\dfrac{8}{7}\) = \(\dfrac{6}{7}\) x \(\dfrac{7}{8}\) =\(\dfrac{42}{56}\)=\(\dfrac{3}{4}\)
Sắp xếp các thương theo thứ tự tăng dần :\(\dfrac{1}{2}\);\(\dfrac{2}{3}\);\(\dfrac{3}{4}\);\(\dfrac{4}{5}\)
\(\Rightarrow\)\(\dfrac{7}{10}\) : \(\dfrac{7}{5}\) ; \(\dfrac{3}{2}\) :\(\dfrac{9}{4}\) ; \(\dfrac{6}{7}\) : \(\dfrac{8}{7}\) ; \(\dfrac{48}{55}\):\(\dfrac{12}{11}\).
a)\(\dfrac{2}{3}giờ< \dfrac{3}{4}giờ\)
b)\(\dfrac{7}{10}m< \dfrac{3}{4}m\)
c)\(\dfrac{7}{8}kg< \dfrac{9}{10}kg\)
d)\(\dfrac{5}{6}\)km/h >\(\dfrac{7}{9}\)km/h
giúp mk vs mn ơi , mai cô giáo ktra mk r
a: \(=\dfrac{8}{9}\cdot\dfrac{9}{4}\cdot\dfrac{12}{19}\cdot\dfrac{19}{24}=\dfrac{1}{2}\cdot2=1\)
b: \(=\dfrac{5}{16}\cdot\dfrac{17}{15}\cdot\dfrac{8}{17}=\dfrac{5}{16}\cdot\dfrac{8}{15}=\dfrac{40}{240}=\dfrac{1}{6}\)
c: \(=\dfrac{4}{13}\left(\dfrac{2}{7}+\dfrac{5}{7}\right)-\dfrac{3}{26}=\dfrac{4}{13}-\dfrac{3}{26}=\dfrac{5}{26}\)
c: \(=\dfrac{3}{4}\left(\dfrac{6}{11}+\dfrac{5}{11}\right)-\dfrac{1}{5}=\dfrac{3}{4}-\dfrac{1}{5}=\dfrac{11}{20}\)