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a)1999*2000-1:1998+1999*2000=[(1999*2000)-(1999*2000)] va 1:1998
=0 + 1998
=1998
\(A=19\frac{1}{4}+\frac{1}{2}\times2\frac{1}{3}+5,75-\frac{1}{6}+74\)
MK GHI ĐẦY ĐỦ RA RÙI, BẠN TỰ BẤM MÁY TÍNH LÀM NHA ( MÌNH LƯỜI )
\(A=19\frac{1}{4}+\frac{1}{2}\times2\frac{1}{3}+5,75-\frac{1}{6}+74\)
\(A=\frac{77}{4}+\frac{1}{2}\times\frac{7}{3}+\frac{23}{4}-\frac{1}{6}+74\)
\(A=\frac{77}{4}+\frac{7}{6}+\frac{23}{4}-\frac{1}{6}+74\)
\(A=(\frac{77}{4}+\frac{23}{4})+(\frac{7}{6}-\frac{1}{6})+74\)
\(A=25+1+74\)
\(A=26+74\)
\(A=100\)
B=\(\left[\left(\frac{1}{3}+\frac{1}{4}\right)x\frac{12}{19}+\frac{12}{19}\right]:\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\left(\frac{7}{12}x\frac{12}{19}+\frac{12}{19}\right):\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\left(\frac{7}{19}+\frac{12}{19}\right):\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\frac{5}{4}-\frac{1}{4}+2012\)
B=1+2012
B=2013
\(B=[\left(\frac{1}{3}+\frac{1}{4}\right)\times\frac{12}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=[\frac{7}{12}\times\frac{12}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=[\frac{7}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=1:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=\frac{5}{4}-\frac{1}{4}+2012\)
\(B=1+2012\)
\(B=2013\)
\(\frac{x}{3\frac{1}{2}.2\frac{2}{3}}=\frac{9}{56}\Rightarrow\frac{x}{\frac{7}{2}.\frac{8}{3}}=\frac{9}{56}\Rightarrow x=\frac{9}{56}.\frac{28}{3}=\frac{3}{2}\)
\(x:\left(3\frac{1}{2}.2\frac{2}{3}\right)=\frac{9}{56}\)
\(x:\left(\frac{7}{2}.\frac{8}{3}\right)=\frac{9}{56}\)
\(x:\left(\frac{7.4}{3}\right)=\frac{9}{56}\)
\(x.\frac{3}{28}=\frac{9}{56}\)
\(x=\frac{9}{56}.\frac{28}{3}=\frac{3}{2}\)
Vậy \(x=\frac{3}{2}\)
a, \(5\frac{3}{4}:\frac{5}{6}-3\frac{3}{4}:\frac{5}{6}\)
\(=\left(5\frac{3}{4}-3\frac{3}{4}\right):\frac{5}{6}\)
\(=2\frac{3}{4}:\frac{5}{6}\)
\(=\frac{11}{4}.\frac{6}{5}\)
\(=\frac{66}{20}\)
\(=\frac{33}{10}\)
b, \(\frac{4}{5}.\frac{22}{47}+\frac{25}{47}:\frac{5}{4}\)
\(=\frac{4}{5}.\frac{22}{47}+\frac{25}{47}.\frac{4}{5}\)
\(=\frac{4}{5}.\left(\frac{22}{47}+\frac{25}{47}\right)\)
\(=\frac{4}{5}.1\)
\(=\frac{4}{5}\)
a) 5\(\frac{3}{4}\) : \(\frac{5}{6}\) - 3\(\frac{3}{4}\) : \(\frac{5}{6}\)
= ( 5\(\frac{3}{4}\) - 3\(\frac{3}{4}\) ) : \(\frac{5}{6}\)
= 2 : \(\frac{5}{6}\) = \(\frac{12}{5}\)
b) \(\frac{4}{5}\) x \(\frac{22}{47}\)+ \(\frac{25}{47}\) : \(\frac{5}{4}\)
= \(\frac{4}{5}\) x \(\frac{22}{47}\) + \(\frac{25}{47}\) x \(\frac{4}{5}\)
= \(\frac{4}{5}\) x ( \(\frac{22}{47}\) + \(\frac{25}{47}\) )
= \(\frac{4}{5}\) x 1 = \(\frac{4}{5}\)
