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(a-b+c-d)-9a+b+c+d)=a-b+c-d-a-b-c-d
=(a-a)-(b+b)+(c-c)-(d-d)
=0-2b+0-2d
=-2b-2d
(-a+b-c)+(a-b)-(a-b+c)
=-a+b-c+a-b-a+b-c
=(-a+a-a)+(b-b+b)-(c+c)
=-a+b-2c
-(a-b-c)+(b-c+d)-(a+b+d)
=-a+b+c+c-c+d-a-b-d
=(-a-a)+(b-b)+(c+c-c)+(d-d)
=-2a+0+c+0
=-2a+c
x+x+x+82=-2-x
3x+82=-2-x
3x+x=-2-82
4x=-84
x=-84:4=-21
5.(-40).x=-100
-200.x=-100
x=-100:(-200)
x=0,5
-1.(-3).(-6).x=36
-18.x=36
x=36:(-18)
x=-2
|1-4x|=7
Xảy ra hai trường hợp:1-4x=7=>4x=1-7=-6=>x=-6:4=-1,5
1-4x=-7=>4x=1+7=8=>x=8:4=2
Vì x là số nguyên nên ta chỉ có một đáp án đó là:2
x.(x-2)=0+> x=0 hoặc x=2
x.(x-2)>0=>x=-1;-2;-3;-4;...
\(ab+ac=a\left(b+c\right)\)
\(ab-ac+a=a\left(b-c+1\right)\)
\(ax-bx-cx+dx=x\left(a-b-c-d\right)\)
\(a\left(b+c\right)-d\left(b+c\right)=0\Leftrightarrow\left(b+c\right)\left(a-d\right)\)
\(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+b\right)\left(c-d\right)\)
\(ax+by+bx+ay=\left(ax+ay\right)+\left(bx+by\right)=a\left(x+y\right)+b\left(x+y\right)=\left(a+b\right)\left(x+y\right)\)
ab + ac = a( b + c )
ab - ac + a = a( b - c +1 )
ax - bx - cx + dx = x( a - b - c - d )
a( b + c ) - d( b + c ) = 0 <=> ( b + c ) ( a - d )
ac - ad + bc - bd = a( c - d ) + b( c - d ) = ( a + b ) ( c - d )
ax + by + bx + ay = ( ax + ay ) + ( bx + by ) = a( x + y ) + b( x + y ) = ( a + b ) ( x + y )
\(\text{ (a-b+c)-(a+c)}=a-b+c-a-c=\left(a-a\right)-b+\left(c-c\right)=-b\)
\(\left(a+b\right)-\left(b-a\right)+c=a+b-b+a+c=2a+c\)
\(-\left(a+b-c\right)+\left(a-b-c\right)=-a-b+c+a-b-c=-2b\)
\(a\left(b+c\right)-a\left(b+d\right)=ab+ac-ab+ad=ac+ad=a\left(c+d\right)\)
\(a\left(b-c\right)+a\left(d+c\right)=a\left(b-c+d+c\right)=a\left(b+d\right)\)
(a-b+c)-(a+c)=a+c-a-c-b=-b
(a+b)-(b-a)+c=a+b-b+a+c=2a+c
-(a+b-c)+(a-b-c)=a-b-c-a-b+c=-2b
a(b+c)-a(b+d)=a(b+c-b-d)=a(c-d)
a(b-c)+a(d+c)=a(b-c+d+c)=a(b+d)
1,(a-b+c)-(a+c)=a-b+c-a-c=-b
2,(a+b)-(b-c)+c=a+b-b+c+c=2c+a (không thể bằng 2a+c đc)
3,-(a+b-c)+(a-b-c)=-a-b+c+a-b-c=-2b
\(\left(a-b+c\right)-\left(a+c\right)\)
\(=a-b+c-a-c\)
\(=\left(a-a\right)+\left(c-c\right)-b\)
\(=0+0-b\)
\(=0-b\)
\(=-b\)
1) (a - b + c) - (a + c)
= a - b + c - a - c
= (a - a) - b + (c - c)
= 0 - b + 0 = -b
2) (a + b) - (b - a) + c
= a + b - b + a + c
= (a + a) + (b - b) + c
= 2a + 0 + c = 2a + c
3) -(a + b - c) + (a - b - c)
= -a - b + c + a - b - c
= (-a + a) - (b + b) + (c - c)
= 0 - 2b + 0 = -2b
4) a(b + c) - a(b + d)
= ab + ac - ab - ad
= (ab - ab) + a(c - d)
= 0 + a(c - d) = a(c - d)
5) tự lm