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9 tháng 1 2022

a) 

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(Mg+2HCl\rightarrow MgCl_2+H_2\)

\(Zn+2HCl\rightarrow ZnCl_2+H_2\)

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

b)

\(CuO+2HCl\rightarrow CuCl_2+H_2O\)

\(FeO+2HCl\rightarrow FeCl_2+H_2O\)

\(Fe_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

c) \(KOH+HCl\rightarrow KCl+H_2O\)

\(Fe\left(OH\right)_2+2HCl\rightarrow FeCl_2+2H_2O\)

\(Fe\left(OH\right)_3+3HCl\rightarrow FeCl_3+3H_2O\)

d) 

\(NaOH+HCl\rightarrow NaCl+H_2O\)

\(AgNO_3+HCl\rightarrow AgCl+HNO3\)

\(CaCO_3+2HCl\rightarrow CaCl_2+CO_2+H_2O\)

\(NaHCO_3+HCl\rightarrow NaCl+H_2O+CO_2\)

29 tháng 11 2019

a) SO2 + Na2O -> Na2SO3

Na2SO3 + H2SO4 -> Na2SO4 + SO2 + H2O

Na2SO4 + Ba(OH)2 -> BaSO4 \(\downarrow\)+ 2NaOH

2NaOH + CO2 -> Na2CO3 + H2O

b) CaO + CO2 -> CaCO3

CaCO3 \(\rightarrow^{t^o}\) CaO + CO2

CaO + H2O -> Ca ( OH)2

Ca ( OH)2 + CO2 -> CaCO3 + H2O

CaCO3 + H2SO4 -> CaSO4 + CO2 + H2O

29 tháng 11 2019

c) 2Fe + 3Cl2 \(\rightarrow^{t^o}\) 2FeCl3

FeCl3 + 3NaOH -> Fe(OH)3 \(\downarrow\) + 3NaCl

2Fe(OH)3 \(\rightarrow^{t^o}\) Fe2O3 + 3H2O

Fe2O3 + 3H2SO4 -> Fe2(SO4)3 + 3H2O

Fe2(SO4)3 + 3BaCl2 -> 2FeCl3 + 3BaSO4\(\downarrow\)

d) Fe + 2HCl -> FeCl2 + H2

FeCl2 + 2AgNO3 -> 2AgCl\(\downarrow\) + Fe(NO3)2

Fe(NO3)2 + 2NaOH -> Fe(OH)2\(\downarrow\) + 2NaNO3

Fe(OH)2 + H2SO4 -> FeSO4 + 2H2O

3 tháng 8 2019

Bài 3 :

4FeS + 7O2 --t--> 2Fe2O3 + 4SO2

Fe2O3 + 6HNO3 -> 2Fe(NO3)3 + 3H2O

Fe(NO3)3 + 3 NaOH -> Fe(OH)3 +3NaNO3

2Fe(OH)3 --t--> Fe2O3 + 3H2O

Fe2O3 + 3H2 -t-> 2Fe + 3H2O

Fe + S -t-> FeS

3 tháng 8 2019

1, FeCl3 + 3KOH → Fe(OH)3 + 3KCl

2Fe(OH)3 \(\underrightarrow{t^o}\)Fe2O3 + 3H2O

Fe2O3 + 3H2 \(\underrightarrow{t^o}\) 2Fe + 3H2O

3Fe + 2O2 \(\underrightarrow{t^o}\) Fe3O4

2, 2Ca + O2 \(\underrightarrow{t^o}\) 2CaO

CaO + H2O → Ca(OH)2

Ca(OH)2 + CO2 → CaCO3 + H2O

CaCO3 + H2O + CO2→ Ca(HCO3)2

Ca(HCO3)2 + 2HCl → CaCl2 + 2H2O + 2CO2

CaCl2 + Ca(OH)2 → 2CaO + 2HCl

3, 4FeS + 7O2 \(\underrightarrow{t^o}\) 2Fe2O3 + 4SO2

Fe2O3 + 6HNO3 → 2Fe(NO3)3 + 3H2O

Fe(NO3)3 + 3KOH → Fe(OH)3 + 3KNO3

2Fe(OH)3 \(\underrightarrow{t^o}\) Fe2O3 + 3H2O

Fe2O3 + 3H2 \(\underrightarrow{t^o}\) 2Fe + 3H2O

Fe + S \(\underrightarrow{t^o}\) FeS

1) \(Al\xrightarrow[]{\left(1\right)}Al_2O_3\xrightarrow[]{\left(2\right)}AlCl_3\xrightarrow[]{\left(3\right)}Al\left(OH\right)_3\) 2) \(Al\xrightarrow[]{\left(1\right)}AlCl_3\xrightarrow[]{\left(2\right)}Al\left(OH\right)_3\xrightarrow[]{\left(3\right)}Al_2O_3\) 3) \(Fe\xrightarrow[]{\left(1\right)}FeSO_4\xrightarrow[]{\left(2\right)}FeCl_2\xrightarrow[]{\left(3\right)}Fe\left(OH\right)_2\xrightarrow[]{\left(4\right)}FeO\) 4)...
Đọc tiếp

1) \(Al\xrightarrow[]{\left(1\right)}Al_2O_3\xrightarrow[]{\left(2\right)}AlCl_3\xrightarrow[]{\left(3\right)}Al\left(OH\right)_3\)

2) \(Al\xrightarrow[]{\left(1\right)}AlCl_3\xrightarrow[]{\left(2\right)}Al\left(OH\right)_3\xrightarrow[]{\left(3\right)}Al_2O_3\)

3) \(Fe\xrightarrow[]{\left(1\right)}FeSO_4\xrightarrow[]{\left(2\right)}FeCl_2\xrightarrow[]{\left(3\right)}Fe\left(OH\right)_2\xrightarrow[]{\left(4\right)}FeO\)

4) \(Fe\left(OH\right)_2\xrightarrow[]{\left(1\right)}FeO\xrightarrow[]{\left(2\right)}FeSO_4\xrightarrow[]{\left(3\right)}FeCl_2\xrightarrow[]{\left(4\right)}Fe\left(OH\right)_2\)

5) \(Fe\xrightarrow[]{\left(1\right)}FeCl_2\xrightarrow[]{\left(2\right)}Fe\left(NO_3\right)_2\xrightarrow[]{\left(3\right)}Fe\left(OH\right)_2\xrightarrow[]{\left(4\right)}FeSO_4\)

6) \(Fe\xrightarrow[]{\left(1\right)}FeCl_3\xrightarrow[]{\left(2\right)}Fe\left(OH\right)_3\xrightarrow[]{\left(3\right)}Fe_2\left(SO_4\right)_3\xrightarrow[]{\left(4\right)}FeCl_3\)

7) \(Fe\left(NO_3\right)_3\xrightarrow[]{\left(1\right)}Fe\left(OH\right)_3\xrightarrow[]{\left(2\right)}Fe_2O_3\xrightarrow[]{\left(3\right)}Fe\xrightarrow[]{\left(4\right)}FeCl_3\)

8) \(Fe_2\left(SO_4\right)_3\xrightarrow[]{\left(1\right)}Fe\left(OH\right)_3\xrightarrow[]{\left(2\right)}Fe_2O_3\xrightarrow[]{\left(3\right)}Fe_2\left(SO_4\right)_3\xrightarrow[]{\left(4\right)}FeCl_3\)

2
5 tháng 12 2019

1

1)4 Al+3O2→2Al2O3

(2)Al2O3+6HCl→2AlCl3+3H2O

(3)AlCl3+3NaOH→Al(OH)3+3NaCl

2

4Al+3O2→2Al2O3

Al2O3+6HCl→2AlCl3+3H2O

AlCl3+3NaOH→Al(OH)3+3NaCl

3

Fe+H2SO4→FeSO4+H2

(2)FeSO4+BaCl2→FeCl2+BaSO4

(3)FeCl2+2NaOH→Fe(OH)2+2NaCl

(4)Fe(OH)2→FeO+H2O

4

Fe+H2SO4→FeSO4+H2

FeSO4+BaCl2→FeCl2+BaSO4

FeCl2+2NaOH→Fe(OH)2+2NaCl

Fe(OH)2→FeO+H2O

5

Fe+2HCl→FeCl2+H2

(2)FeCl2+2AgNO3→Fe(NO3)2+2AgCl

(3)Fe(NO3)2+2NaOH→Fe(OH)2+2NaNO3

(4)Fe(OH)2+MgSO4→FeSO4+Mg(OH)2

5 tháng 12 2019

Câu 1 :

( 1 ) 4Al + 3O2 → 2Al2O3 ( Nhiệt độ )

( 2 ) Al2O3 + 6HCl → 2AlCl3 + 3H2O

( 3 ) AlCl3 + 3NaOH → Al(OH)3 + 3NaCl

Câu 2 :

( 1 ) 2Al + 6HCl → 2AlCl3 + 3H2

( 2 ) AlCl3 + 3NaOH → Al(OH)3 + 3NaCl

( 3 ) 2Al(OH)3 → Al2O3 + 3H2O ( Nhiệt độ )

Câu 3 :

( 1 ) Fe + H2SO4 → H2 + FeSO4

( 2 ) BaCl2 + FeSO4 → FeCl2 + BaSO4

( 3 ) FeCl2 + 2NaOH → NaCl + Fe(OH)2

( 4 ) Fe(OH)2 → FeO + H2O ( Nhiệt độ )

Câu 4 :

( 1 ) Fe(OH)2 → FeO + H2O ( Nhiệt độ )

( 2 ) FeO + H2SO4 → H2O + FeSO4

( 3 ) BaCl2 + FeSO4 → FeCl2 + BaSO4

( 4 ) FeCl2 + 2NaOH → NaCl + Fe(OH)2

Câu 5 :

( 1 ) Fe + 2HCl → FeCl2 + H2

( 2 ) 2AgNO3 + FeCl2 → 2AgCl + Fe(NO3)2

( 3 ) Fe(NO3)2 + NaOH → NaNO3 + Fe(OH)2

( 4 ) H2SO4 + Fe(OH)2 → 2H2O + FeSO4

Câu 6 :

( 1 ) 3Cl2 + 2Fe → 2FeCl3 ( Nhiệt độ )

( 2 ) 3NaOH + FeCl3 → 3NaCl + Fe(OH)3

( 3 ) 3H2SO4 + 2Fe(OH)3 → Fe2(SO4)3 + 6H2O

( 4 ) 3BaCl2 + Fe2(SO4)3 → 2FeCl3 + 3BaSO4

Câu 7 :

( 1 ) 3NaOH + Fe(NO3)3 → 3NaNO3 + Fe(OH)3

( 2 ) 2Fe(OH)3 → Fe2O3 + 3H2O ( Nhiệt độ )

( 3 ) 2Al + Fe2O3 → Al2O3 + 2Fe

( 4 ) 3Cl2 + 2Fe → 2FeCl3 ( Nhiệt độ )

Câu 8 :

( 1 ) Fe2(SO4)3 + 6NaOH → 3Na2SO4 + 2Fe(OH)3

( 2 ) 2Fe(OH)3 → Fe2O3 + 3H2O ( Nhiệt độ )

( 3 ) Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O

( 4 ) 3BaCl2 + Fe2(SO4)3 → 2FeCl3 + 3BaSO4

Câu 1 ) A / Mg(NO3) \(\underrightarrow{\left(1\right)}\) Mg(OH)2 \(\underrightarrow{\left(2\right)}\) MgCl2\(\underrightarrow{\left(3\right)}\) KCl \(\underrightarrow{\left(4\right)}\) KNO3 B/...
Đọc tiếp

Câu 1 ) A / Mg(NO3) \(\underrightarrow{\left(1\right)}\) Mg(OH)2 \(\underrightarrow{\left(2\right)}\) MgCl2\(\underrightarrow{\left(3\right)}\) KCl \(\underrightarrow{\left(4\right)}\) KNO3

B/ \(Na\underrightarrow{\left(1\right)}Na_2O\underrightarrow{\left(2\right)}NaOH\underrightarrow{\left(3\right)}Na_2SO_4\underrightarrow{\left(4\right)}NaCl\underrightarrow{\left(5\right)}NaNO_3\underrightarrow{\left(6\right)}NaCl\underrightarrow{\left(7\right)}NaOH\)

C/\(Mg\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgCl_2\underrightarrow{\left(3\right)}Mg\left(NO_3\right)_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgSO_4\underrightarrow{\left(6\right)}MgCO_3\)

D/\(CuSO_4\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuO\underrightarrow{\left(3\right)}CuCl_2\underrightarrow{\left(4\right)}Cu\left(OH\right)_2\underrightarrow{\left(5\right)}CuSO_4\)

E/\(CuCl_2\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuSO_4\underrightarrow{\left(3\right)}Cu\underrightarrow{\left(4\right)}CuO\)

F/ \(Cu\left(OH\right)_2\underrightarrow{\left(1\right)}CuO\underrightarrow{\left(2\right)}CuCl_2\underrightarrow{\left(3\right)}Cu\left(NO_3\right)_2\underrightarrow{\left(4\right)}NaNO_3\)

G/\(Fe_2O_3\underrightarrow{\left(1\right)}FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{\left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe_2\left(SO_4\right)_3\)

H/ \(ZnCl_2\underrightarrow{\left(1\right)}Zn\left(OH\right)_2\underrightarrow{\left(2\right)}ZnCl_2\underrightarrow{\left(3\right)}NaCl\underrightarrow{\left(4\right)}NaNO_3\)

M/\(CuO\underrightarrow{\left(1\right)}CuCl_2\underrightarrow{\left(2\right)}Cu\left(OH\right)_2\underrightarrow{\left(3\right)}CuO\underrightarrow{\left(4\right)}CuSO_4\)

N/\(Fe\left(OH\right)_2\underrightarrow{\left(1\right)}FeO\underrightarrow{\left(2\right)}FeCl_2\underrightarrow{\left(3\right)}Fe\left(ỌH_2\right)\underrightarrow{\left(4\right)}FeSO_4\underrightarrow{\left(5\right)}FeCl_2\underrightarrow{\left(6\right)}Fe\left(NO_3\right)_2\)

Z/ \(Mg\left(OH\right)_2\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgSO_4\underrightarrow{\left(3\right)}MgCl_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgCl_2\underrightarrow{\left(6\right)}Mg\left(NO_3\right)_2\)

X/\(Al\left(OH\right)_3\underrightarrow{\left(1\right)}Al_2O_3\underrightarrow{\left(2\right)}AlCl_3\underrightarrow{\left(3\right)}Al\underrightarrow{\left(4\right)}Al_2\left(SO_4\right)_3\)

11
7 tháng 11 2018

g) 1. Fe2O3 + 6HCl → 2FeCl3 + 3H2O

2. FeCl3 + 3NaOH → 3NaCl + Fe(OH)3

3. 2Fe(OH)3 \(\underrightarrow{to}\) Fe2O3 + 3H2O

4. Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O

7 tháng 11 2018

h) 1. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2

2. Zn(OH)2 + 2HCl → ZnCl2 + 2H2O

3. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2

4. NaCl + AgNO3 → NaNO3 + AgCl↓

Bài 1 : Chuỗi phản ứng : a) \(Al\xrightarrow[]{\left(1\right)}Al_2O_3\xrightarrow[]{\left(2\right)}AlCl_3\xrightarrow[]{\left(3\right)}Al\left(OH\right)_3\) b) \(Al\xrightarrow[\left(1\right)]{}Al_2O_3\xrightarrow[]{\left(2\right)}AlCl_3\xrightarrow[\left(3\right)]{}Al\left(OH\right)_3Al_2O_3\) c) \(Fe\xrightarrow[]{\left(1\right)}FeSO_4\xrightarrow[]{\left(2\right)}FeCl_2\xrightarrow[]{\left(3\right)}Fe\left(OH\right)_2\xrightarrow[]{\left(4\right)}FeO\) d)...
Đọc tiếp

Bài 1 : Chuỗi phản ứng :

a) \(Al\xrightarrow[]{\left(1\right)}Al_2O_3\xrightarrow[]{\left(2\right)}AlCl_3\xrightarrow[]{\left(3\right)}Al\left(OH\right)_3\)

b) \(Al\xrightarrow[\left(1\right)]{}Al_2O_3\xrightarrow[]{\left(2\right)}AlCl_3\xrightarrow[\left(3\right)]{}Al\left(OH\right)_3Al_2O_3\)

c) \(Fe\xrightarrow[]{\left(1\right)}FeSO_4\xrightarrow[]{\left(2\right)}FeCl_2\xrightarrow[]{\left(3\right)}Fe\left(OH\right)_2\xrightarrow[]{\left(4\right)}FeO\)

d) \(Zn\xrightarrow[]{\left(1\right)}ZnSO_4\xrightarrow[]{\left(2\right)}ZnCl_2\xrightarrow[]{\left(3\right)}Zn\left(OH\right)_2\xrightarrow[]{\left(4\right)}ZnO\)

e) \(Mg\left(OH\right)_2\xrightarrow[]{\left(1\right)}MgCl_2\xrightarrow[]{\left(2\right)}Mg\left(NO_3\right)_2\xrightarrow[]{\left(3\right)}Mg\left(OH\right)_2\xrightarrow[]{\left(4\right)}MgO\)

f) \(Fe\left(OH\right)_2\xrightarrow[]{\left(1\right)}FeO\xrightarrow[]{\left(2\right)}FeSO_4\xrightarrow[]{\left(3\right)}FeCl_2\xrightarrow[]{\left(4\right)}Fe\left(OH\right)_2\)

g) \(Fe\xrightarrow[]{\left(1\right)}FeCl_2\xrightarrow[]{\left(2\right)}Fe\left(NO_3\right)_2\xrightarrow[]{\left(3\right)}Fe\left(OH\right)_2\xrightarrow[]{\left(4\right)}FeSO_4\)

h) \(S\xrightarrow[]{\left(1\right)}SO_2\xrightarrow[]{\left(2\right)}SO_3\xrightarrow[]{\left(3\right)}H_2SO_4\xrightarrow[]{\left(4\right)}SO_2\)

k) \(Cu\xrightarrow[]{\left(1\right)}CuO\xrightarrow[]{\left(2\right)}CuSO_4\xrightarrow[]{\left(3\right)}Cu\left(NO_3\right)_2\xrightarrow[]{\left(4\right)}Cu\left(OH\right)_2\)

Bài 2 : Phân biệt các chất rắn

a) Hai chất rắn: \(Cao\)\(P_2O_5\)

b) Hai chất rắn: BaO và \(P_2O_5\)

c) Hai chất rắn :\(Na_2O\)\(P_2O_5\)

d) Hai chất rắn :\(K_2O\)\(P_2O_5\)

e) Ba chất rắn : MgO, \(Na_2O\), \(P_2O_5\)

GIÚP MINH VỚI Ạ !!!!

4
25 tháng 11 2019

Bài 2

a) -Cho nước vào

CaO+H2O---->Ca(OH)2

P2O5+3H2O--->2H2PO4

-Cho QT vào Ca(OH)2 và H3PO4

-Lm QT hóa xanh là Ca(OH)2

-->MT bđ là CaO

-Lm QT hóa đỏ là H3PO4

-->MT bđ là P2O5

b) -Cho nước

BaO+H2O--->Ba(OH)2

P2O5+3H2O--->2H2PO4

-Cho QT vào Ba(OH)2 và H3PO4

-Lm QT hóa xanh là Ba(OH)2

-->MT bđ là BaO

-Lm QT hóa đỏ là H3PO4

-->MT bđ là P2O5

c)-Cho nước vào

Na2O+H2O--->2NaOH

P2O5+3H2O--->2H2PO4

-Cho QT vào NaOH và H3PO4

-Lm QT hóa xanh là NaOH

-->MT bđ là Na2O

-Lm QT hóa đỏ là H3PO4

-->MT bđ là P2O5

d)

K2O+H2O--->2KOH

P2O5+3H2O--->2H2PO4

-Cho QT vào KOH và H3PO4

-Lm QT hóa xanh là KOH

-->MT bđ là K2O

-Lm QT hóa đỏ là H3PO4

-->MT bđ là P2O5

e)-Cho nước vào

+Ko tan là Mgo

+Tan là Na2O và P2O5

Na2O+H2O--->2NaOH

P2O5+3H2O--->2H2PO4

-Cho QT vào NaOH và H3PO4

-Lm QT hóa xanh là NaOH

-->MT bđ là Na2O

-Lm QT hóa đỏ là H3PO4

-->MT bđ là P2O5

25 tháng 11 2019

a) Al(1)−→Al2O3(2)−→AlCl3(3)−→Al(OH)3Al→(1)Al2O3→(2)AlCl3→(3)Al(OH)3

b) Al−→(1)Al2O3(2)−→AlCl3−→(3)Al(OH)3Al2O3Al→(1)Al2O3→(2)AlCl3→(3)Al(OH)3Al2O3

c) Fe(1)−→FeSO4(2)−→FeCl2(3)−→Fe(OH)2(4)−→FeOFe→(1)FeSO4→(2)FeCl2→(3)Fe(OH)2→(4)FeO

d) Zn(1)−→ZnSO4(2)−→ZnCl2(3)−→Zn(OH)2(4)−→ZnOZn→(1)ZnSO4→(2)ZnCl2→(3)Zn(OH)2→(4)ZnO

e) Mg(OH)2(1)−→MgCl2(2)−→Mg(NO3)2(3)−→Mg(OH)2(4)−→MgOMg(OH)2→(1)MgCl2→(2)Mg(NO3)2→(3)Mg(OH)2→(4)MgO

f) Fe(OH)2→FeO+H2O

(2)FeO+H2SO4→FeSO4+H2O

(3)FeSO4+BaCl2→FeCl2+BaSO4

(4)FeCl2+2NaOH→Fe(OH)2+2NaCl

g) Fe(1)+2HCl→FeCl2+H2

(2)FeCl2+2AgNO3→Fe(NO3)2+2AgCl

(3)Fe(NO3)2+3NaOH→Fe(OH)2+2NaNO3

(4)Fe(OH)2+MgSO4→FeSO4+Mg(OH)2

h) S(1)+O2→SO2

(2)2SO2+O2→2SO3

(3)SO3+H2O→H2SO4

(4)6H2SO4+2Fe→Fe2(SO4)3+6H2O+2SO2

k) 2Cu(1)+O2→2CuO

(2)CuO+H2SO4→CuSO4+H2O

(3)CuSO4+Ba(NO3)2→Cu(NO3)2+BaSO4

(4)Cu(NO3)2+2NaOH→Cu(OH)2+2NaNO3

6 tháng 7 2021

Đáp án C

Ví dụ : $NaOH + HCl \to NaCl + H_2O$

6 tháng 7 2021

C.NaOH

27 tháng 6 2018

a;

Fe2(SO4)3 +3BaCl2 ->2FeCl3 +3BaSO4

FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl

2Fe(OH)3 -> Fe2O3 +3H2O

Fe2O3 +3H2SO4 -> Fe2(SO4)3 + 3H2O

Fe2(SO4)3 +6NaOH -> 2Fe(OH)3 +3Na2SO4

2Fe(OH)3 +3H2SO4 -2Fe2(SO4)3 +6H2O

27 tháng 6 2018

d;

2Cu + O2 -> 2CuO

CuO + H2SO4 -> CuSO4 + H2O

CuSO4 + 2NaOH -> Cu(OH)2 + 2Na2SO4