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Bài 1:
Gọi số cần tìm là ab thì theo giả thiết, ta có: ab+a+b=65 <=> 11a+2b=65 => a\(\le\)5 và a lẻ (do 2b chẵn, 65 lẻ) => a\(\in\)(1;3;5) rồi giải ra tìm b.
Bài 2:
(chưa biết)
Gọi số phải tìm là \(\overline{ab}\)\((0< a,b< 10;a,b\in N)\)
Theo bài ra ta có :
\(\overline{ab}+a+b=65\)
\(\Rightarrow10a+b+a+b=65\)
\(\Rightarrow11a+2b=65\)
Vì 2b là số chẵn
\(\Rightarrow\)11a là số lẻ
Mà 11a<65\(\Rightarrow a\in\left(1;3;5\right)\)
Thử lại:a=5\(\Rightarrow b=5\)
Vậy số phải tìm là 55
Số đó là : 263
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địt lồn mẹ mày bú buồi đầu buồi liếm lông chim
Gọi số cần tìm là abc (a > 0); a, b, c < 10)
Theo đề bài ta có: abc +a+b+c = 555
Nhìn vào biểu thức trên, ta thấy phép cộng ko có nhớ sang hàng trăm. Vậy a=5
Khi đó ta có: 5bc +5+b+c=555
500 +bc+5+b+c=555
505 +bb+c+c=555
bb +c x2=555-505
bb + c x2=50
Nếu c đạt giá trị lớn nhất là chín thì bb đạt giá trị nhỏ nhất là:
50-9x2=32, do đó b>2
Vì bb +cx2=50 nên bb <50 nên b<5
Vì 2<b<5 nên b=3 hoặc 4
Vì cx2 và 50 đều là số chẵn nên b phải là số chẵn. Do đó b=4
Khi đó ta có:
44+cx2=50
cx2=50-44
cx2=6
c=6:2=3
Vậy abc là 543.
Mỏi tay quá!
Gọi số cần tìm là ab (a khác 0; a,b là các chữ số)
Ta có:
ab + a + b = 84
=> 10a + b + a + b = 84
=> 11a + 2b = 84
=> 11a < 84
=> a < 8 (1)
Do b là chữ số => b < 10 => 2b < 20
=> 11a > 64 => a > 5 (2)
Từ (1) và 92), do 2b chẵn, 84 chẵn => 11a chẵn => a = 6
Ta có: 11 x 6 + 2 x b = 84
=> 66 + 2 x b = 84
=> 2 x b = 84 - 66
=> 2 x b = 18
=> b = 18 : 2 = 9
Vậy số cần tìm là 69
Ủng hộ mk nha ^_-