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\(\left(\frac{1}{3}+\frac{1}{5}\right).x=\frac{8}{25}\)
\(\frac{8}{15}.x=\frac{8}{25}\)
\(x=\frac{8}{25}:\frac{8}{15}\)
\(x=\frac{1}{5}\)
a) \(\left(\frac{1}{3}x\frac{1}{5}\right)\)x X = \(\frac{8}{25}\)
\(\frac{1}{15}\)x X = \(\frac{8}{25}\)
X = \(\frac{8}{25}:\frac{1}{15}\)
X = \(\frac{24}{5}\)
b) \(\frac{1}{2}:\frac{4}{5}:x=\frac{7}{3}\)
\(\frac{5}{8}:x=\frac{7}{3}\)
\(x=\frac{5}{8}:\frac{7}{3}\)
\(x=\frac{15}{56}\)
a \(\dfrac{6}{15}+\dfrac{11}{15}=\dfrac{17}{15}\)
b \(\dfrac{22}{77}-\dfrac{14}{77}=\dfrac{8}{77}\)
c \(\dfrac{11}{13}\times\dfrac{26}{31}=11\times\dfrac{2}{31}=\dfrac{22}{31}\)
d \(\dfrac{1}{2}\times3\times\dfrac{2}{5}=\dfrac{3}{5}\)
\(a,\dfrac{7}{12}+\dfrac{3}{4}\times\dfrac{2}{9}=\dfrac{7}{12}+\dfrac{1}{6}=\dfrac{7}{12}+\dfrac{2}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)
\(b,\dfrac{8}{9}-\dfrac{4}{15}:\dfrac{2}{5}=\dfrac{8}{9}-\dfrac{4}{15}\times\dfrac{5}{2}=\dfrac{8}{9}-\dfrac{2}{3}=\dfrac{8}{9}-\dfrac{6}{9}=\dfrac{2}{9}\)
`a, 3/4 + 1/2 xx 7/2`
`= 3/4 + 7/4`
`=10/4`
`=5/2`
`b, 6/15 - 1/3 : 5/3`
`= 6/15 - 1/3 xx 3/5`
`= 6/15 - 3/15`
`= 3/15`
`=1/5`
`c, x-4/9 = 3/7 : 9/4`
`=> x-4/9= 3/7 xx 4/9`
`=> x-4/9= 12/63`
`=> x-4/9=4/21`
`=> x= 4/21 +4/9`
`=>x= 40/63`
`d, 7/9 xx 3/5 -1/2=1/5`
`->` sao lại bằng có `x` ko vậy ạ?
`a,`
`3/4+1/2 \times 7/2=3/4+7/4=10/4=5/2`
`b,`
`6/15 - 1/3 \div 5/3=6/15-1/5=1/5`
`c,` Tìm x?
`x-4/9=3/7 \div 9/4`
`x-4/9=4/21`
`x=4/21+4/9`
`x=40/63`
`d, 7/9x \times 3/5-1/2=1/5`
`7/9x \times 3/5=1/5+1/2`
`7/9x \times 3/5=7/10`
`7/9x=7/10 \div 3/5`
`7/9x=7/6`
`x=7/6 \div 7/9=3/2`
a)
\(\left(x-\dfrac{2}{3}\right):\dfrac{1}{2}=\dfrac{5}{7}\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{5}{7}\) x \(\dfrac{1}{2}\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{5}{14}\)
\(\Rightarrow x=\dfrac{5}{14}+\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{15}{42}+\dfrac{2}{42}\)
\(\Rightarrow x=\dfrac{17}{42}\)
b)
\(x\) x \(\dfrac{1}{2}=1-\dfrac{1}{3}\)
\(x\) x \(\dfrac{1}{2}=\dfrac{3}{3}-\dfrac{1}{3}\)
\(x\) x \(\dfrac{1}{2}=\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{2}{3}:\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{2}{3}\) x \(2=\dfrac{4}{3}\)
c)
\(\dfrac{26}{5}-x=\dfrac{9}{15}\) x \(\dfrac{25}{3}\)
\(\dfrac{26}{5}-x=5\)
\(\Rightarrow x=\dfrac{26}{5}-5\)
\(\Rightarrow x=\dfrac{26}{5}-\dfrac{25}{5}\)
\(\Rightarrow x=\dfrac{1}{5}\)