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\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{12}{15}+\frac{22}{33}+\frac{48}{64}\)
\(=\frac{11}{33}+\frac{16}{64}+\frac{3}{15}+\frac{12}{15}+\frac{22}{33}+\frac{48}{64}\)
\(=\left(\frac{11}{33}+\frac{22}{33}\right)+\left(\frac{16}{64}+\frac{48}{64}\right)+\left(\frac{3}{15}+\frac{12}{15}\right)\)
\(\frac{33}{33}+\frac{64}{64}+\frac{15}{15}\)
\(=1+1+1\)
\(=3\)
\(\frac{3}{5}-y=\frac{7}{12}x\frac{6}{5}\) \(\frac{4}{15}x\frac{5}{14}=\frac{4x5}{15x14}=\frac{2}{21}\)
\(\frac{3}{5}-y=\frac{7}{10}\)
\(y=\frac{3}{5}-\frac{7}{10}\)
\(y=-\frac{1}{10}\)
1.y + 3/4 = 4/5
y = 4/5 - 3/4
y =1/20
b.y - 3/11=9/22
y = 9/22 + 3/11
y = 15/22
c.9/2 - y = 2/9
y = 9/2 - 2/9
y = 77/18
2.a.\(\frac{18}{15}+\frac{7}{15}+\frac{12}{15}=\frac{18+12+7}{15}=\frac{37}{15}\)
b.\(\frac{9}{7}+\frac{8}{7}+\frac{11}{7}=\frac{9+8+11}{7}=\frac{28}{7}=4\)
\(\frac{15}{22}:\frac{33}{6}=\frac{4}{33}\)
\(\frac{15}{22}+\frac{y}{6}=\frac{4}{33}\)
\(\frac{y}{6}=\frac{15}{22}\div\frac{4}{33}\)
\(\frac{y}{6}=1\)
Vậy y = 6
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