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\(P=\dfrac{\left(17,005-4,505\right)^2+125,075}{\left\{\left[0,1936:0,88+3,53\right]^2-7,5625\right\}:0,52}\)
\(=\dfrac{\left(12,5\right)^2+125,075}{\left\{\left[3,75\right]^2-7,5625\right\}:0,52}\)
\(=\dfrac{156,25+125,075}{\left\{14,0625-7,5625\right\}:0,52}\)
\(=\dfrac{281,325}{6,5:0,52}\)
\(=\dfrac{281,325}{12,5}\)
\(=22,506\)
\(Q=\dfrac{\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right).\dfrac{1016}{5}+\dfrac{187}{4}}{\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(\dfrac{37}{3}-\dfrac{100}{7}\right)}\)
\(=\dfrac{\left(\dfrac{1431}{108}-\dfrac{236}{108}-\dfrac{1170}{108}\right).\dfrac{1016}{5}+\dfrac{187}{4}}{\left(\dfrac{30}{21}+\dfrac{70}{21}\right):\left(\dfrac{259}{21}-\dfrac{300}{21}\right)}\)
\(=\dfrac{\dfrac{25}{108}.\dfrac{1016}{5}+\dfrac{187}{4}}{\dfrac{100}{21}:\dfrac{-1}{21}}\)
\(=\dfrac{\dfrac{1270}{27}+\dfrac{187}{4}}{-100}\)
\(=\dfrac{\dfrac{5080}{108}+\dfrac{5049}{108}}{-100}\)
\(=\dfrac{10129}{108}.\left(-\dfrac{1}{100}\right)\)
\(=-\dfrac{10129}{10800}\)
\(P=\dfrac{\left(17,005-4,505\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
\(P=\dfrac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
\(P=\dfrac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(P=\dfrac{250}{\left(14,0625-7,5625\right):0,52}\)
\(P=\dfrac{250}{6,5:0,52}=\dfrac{250}{12,5}=20\)
\(P=\dfrac{\left(17.005-4.505\right)^2+125\cdot\dfrac{3}{4}}{\left(3.75^2-2.75^2\right):0.52}\)
\(=\dfrac{\left(12.5\right)^2+12.5\cdot\dfrac{15}{2}}{\left(3.75+2.75\right):0.52}\)
\(=\dfrac{12.5\left(12.5+7.5\right)}{6.5:0.52}=\dfrac{12.5\cdot20}{12.5}=20\)
\(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).203\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
= \(\dfrac{\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right).\dfrac{5076}{25}+\dfrac{187}{4}}{\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(\dfrac{37}{3}-\dfrac{100}{7}\right)}\)
= \(\dfrac{\dfrac{25}{108}.\dfrac{5076}{25}+\dfrac{187}{4}}{\dfrac{100}{21}:\dfrac{-41}{21}}\)
=\(\dfrac{\dfrac{5076}{108}+\dfrac{187}{4}}{\dfrac{-100}{4}}\)
= \(\dfrac{47+\dfrac{187}{4}}{-25}\)
= \(\dfrac{375}{4}:\left(-25\right)\)
= \(\dfrac{-15}{4}\)
\(E=\dfrac{\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right).\dfrac{5751}{25}+\dfrac{187}{4}}{\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(\dfrac{37}{3}-\dfrac{100}{7}\right)}\)
\(=\dfrac{\dfrac{25}{108}.\dfrac{5751}{25}+\dfrac{187}{4}}{\dfrac{100}{21}:\left(\dfrac{-44}{21}\right)}\)
\(=\dfrac{53,25+\dfrac{187}{4}}{\dfrac{-25}{11}}\)
\(=\dfrac{100}{\dfrac{-25}{11}}\)
\(=-44\)
\(P=\dfrac{\left(17.005-4.505\right)^2+93.75}{\left[\left(0.22+3.53\right)^2-\left(2.75\right)^2\right]:0,52}\)
\(=\dfrac{156.25+93.75}{6.5:0.52}=\dfrac{250}{12.5}=20\)
\(P=\dfrac{\left(17,005-4,505\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:052}\)
\(=\dfrac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{250}{\left(14,0625-75625\right):0,52}\)
\(=\dfrac{250}{6,5:0,52}\)
\(=\dfrac{250}{12,5}=20\)
Vây P = 20
P/s: Lấy máy tính tính lại xem đúng k chứ nhiều số rắc rối quá
hơi sai sai tki pGiang Thủy Tiên
sai đề r bạn ơiiiii