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14 tháng 2 2016

=9/2/5

=47/5

a: x=-5/11+2/11=-3/11

b: =>x=-3/24+20/24+1/24=18/24=3/4

c: =>5/8-x=1/9+5/4=4/36+45/36=49/36

=>x=5/8-49/36=-53/72

d: =>2/3-x=1/3

=>x=1/3

e: =>1/5:x=12/35

=>x=7/12

2: \(=\dfrac{-2}{75}+\dfrac{5}{39}=\dfrac{33}{325}\)

3: \(=\dfrac{6}{11}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{6}{11}\)

4: \(=\dfrac{7}{19}\left(\dfrac{5}{13}+\dfrac{8}{13}-1\right)=-2\cdot\dfrac{7}{19}=-\dfrac{14}{19}\)

5: \(=\dfrac{2}{7}\left(\dfrac{4}{23}-\dfrac{27}{23}+1\right)=0\)

6: \(=\dfrac{3}{8}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\dfrac{11}{8}=\dfrac{3}{8}+\dfrac{11}{8}=\dfrac{14}{8}=\dfrac{7}{4}\)

15 tháng 5 2017

\(\dfrac{-9}{46}-4\dfrac{1}{23}:\left(3\dfrac{1}{4}-x:\dfrac{3}{5}\right)+2\dfrac{8}{23}=1\)

\(\dfrac{-9}{46}+2\dfrac{8}{23}-4\dfrac{1}{23}:\left(3\dfrac{1}{4}-x:\dfrac{3}{5}\right)=1\)

\(\dfrac{-9}{46}+\dfrac{54}{23}-\dfrac{93}{23}:\left(\dfrac{13}{4}-x:\dfrac{3}{5}\right)=1\)

\(\dfrac{-9}{46}+\dfrac{108}{46}-\dfrac{93}{23}:\left(\dfrac{13}{4}-x:\dfrac{3}{5}\right)=1\)

\(\dfrac{99}{46}-\dfrac{93}{23}:\left(\dfrac{13}{4}-x:\dfrac{3}{5}\right)=1\)

\(\dfrac{93}{23}:\left(\dfrac{13}{4}-x:\dfrac{3}{5}\right)=\dfrac{99}{46}-1\)

\(\dfrac{93}{23}:\left(\dfrac{13}{4}-x:\dfrac{3}{5}\right)=\dfrac{99}{46}-\dfrac{46}{46}\)

\(\dfrac{93}{23}:\left(\dfrac{13}{4}-x:\dfrac{3}{5}\right)=\dfrac{53}{46}\)

\(\dfrac{13}{4}-x:\dfrac{3}{5}=\dfrac{93}{23}:\dfrac{53}{46}\)

\(\dfrac{13}{4}-x:\dfrac{3}{5}=\dfrac{93}{23}\cdot\dfrac{46}{53}\)

\(\dfrac{13}{4}-x:\dfrac{3}{5}=\dfrac{186}{53}\)

\(x:\dfrac{3}{5}=\dfrac{13}{4}-\dfrac{186}{53}\)

\(x:\dfrac{3}{5}=\dfrac{689}{212}-\dfrac{744}{212}\)

\(x:\dfrac{3}{5}=\dfrac{-55}{212}\)

\(x=\dfrac{-55}{212}\cdot\dfrac{3}{5}\)

\(x=\dfrac{-33}{212}\)

Vậy \(x=\dfrac{-33}{212}\).

5 tháng 3 2016

5/8.x=23/4+1/8

5/8.x=47/8

x=47/8:5/8=47/5

17 tháng 1 2022
64646464646464646464646464646464646464 [more]
AH
Akai Haruma
Giáo viên
3 tháng 1

Bài 1:

$10+3(x-6)=5^{10}:5^8=5^2=25$

$3(x-6)=25-10=15$

$x-6=15:3=5$

$x=5+6=11$

 

AH
Akai Haruma
Giáo viên
3 tháng 1

Bài 2:

a. $100-[150-8(7-4)^2]=100-(150-8.3^2)=100-150+8.3^2$

$=-50+72=72-50=22$
b. $=-999-23+999-10-67=(-999+999)-10-(67+23)$

$=0-10-90=-(10+90)=-100$