Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
`@` `\text {Ans}`
`\downarrow`
`a)`
Thu gọn:
`P(x)=`\(5x^4 + 3x^2 - 3x^5 + 2x - x^2 - 4 +2x^5\)
`= (-3x^5 + 2x^5) + 5x^4 + (3x^2 - x^2) + 2x - 4`
`= -x^5 + 5x^4 + 2x^2 + 2x - 4`
`Q(x) =`\(x^5 - 4x^4 + 7x - 2 + x^2 - x^3 + 3x^4 - 2x^2\)
`= x^5 + (-4x^4 + 3x^4) - x^3 + (x^2 - 2x^2) + 7x - 2`
`= x^5 - x^4 - x^3 - x^2 + 7x - 2`
`@` Tổng:
`P(x)+Q(x)=`\((-x^5 + 5x^4 + 2x^2 + 2x - 4) + (x^5 - x^4 - x^3 - x^2 + 7x - 2)\)
`= -x^5 + 5x^4 + 2x^2 + 2x - 4 + x^5 - x^4 - x^3 - x^2 + 7x - 2`
`= (-x^5 + x^5) - x^3 + (5x^4 - x^4) + (2x^2 - x^2) + (2x + 7x) + (-4-2)`
`= 4x^4 - x^3 + x^2 + 9x - 6`
`@` Hiệu:
`P(x) - Q(x) =`\((-x^5 + 5x^4 + 2x^2 + 2x - 4) - (x^5 - x^4 - x^3 - x^2 + 7x - 2)\)
`= -x^5 + 5x^4 + 2x^2 + 2x - 4 - x^5 + x^4 + x^3 + x^2 - 7x + 2`
`= (-x^5 - x^5) + (5x^4 + x^4) + x^3 + (2x^2 + x^2) + (2x - 7x) + (-4+2)`
`= -2x^5 + 6x^4 + x^3 + 3x^2 - 5x - 2`
`b)`
`@` Thu gọn:
\(H (x) = ( 3x^5 - 2x^3 + 8x + 9) - ( 3x^5 - x^4 + 1 - x^2 + 7x)\)
`= 3x^5 - 2x^3 + 8x + 9 - 3x^5 + x^4 - 1 + x^2 - 7x`
`= (3x^5 - 3x^5) + x^4 - 2x^3 - x^2 + (8x + 7x) + (9+1)`
`= x^4 - 2x^3 - x^2 + 15x + 10`
\(R( x) = x^4 + 7x^3 - 4 - 4x ( x^2 + 1) + 6x\)
`= x^4 + 7x^3 - 4 - 4x^3 - 4x + 6x`
`= x^4 + (7x^3 - 4x^3) + (-4x + 6x) - 4`
`= x^4 + 3x^3 + 2x - 4`
`@` Tổng:
`H(x)+R(x)=` \((x^4 - 2x^3 - x^2 + 15x + 10)+(x^4 + 3x^3 + 2x - 4)\)
`= x^4 - 2x^3 - x^2 + 15x + 10+x^4 + 3x^3 + 2x - 4`
`= (x^4 + x^4) + (-2x^3 + 3x^3) - x^2 + (15x + 2x) + (10-4)`
`= 2x^4 + x^3 - x^2 + 17x + 6`
`@` Hiệu:
`H(x) - R(x) =`\((x^4 - 2x^3 - x^2 + 15x + 10)-(x^4 + 3x^3 + 2x - 4)\)
`=x^4 - 2x^3 - x^2 + 15x + 10-x^4 - 3x^3 - 2x + 4`
`= (x^4 - x^4) + (-2x^3 - 3x^3) - x^2 + (15x - 2x) + (10+4)`
`= -5x^3 - x^2 + 13x + 14`
`@` `\text {# Kaizuu lv u.}`
a: A(x)=3x^5+x^4+x^2+2x
B(x)=-3x^5-x^4+x^2+x-2
b: M(x)=3x^5+x^4+x^2+2x-3x^5-x^4+x^2+x-2
=2x^2+3x-2
c: M(-2)=8-6-2=0
d: M(3)=2*3^2+3*3-2=18+9-2=25
=>x=3 ko là nghiệm
`a,`
`P(x)=5x^3+3-3x^2+x^4-2x-2+2x^2+x`
`P(x)=x^4+5x^3+(-3x^2+2x^2)+(-2x+x)+(3-2)`
`P(x)=x^4+5x^3-x^2-x+1`
`Q(x)=2x^4+x^2+2x+2-3x^2-5x+2x^3-x^4`
`Q(x)=(2x^4-x^4)+2x^3+(x^2-3x^2)+(2x-5x)+2`
`Q(x)=x^4+2x^3-2x^2-3x+2`
`b,`
`P(x)-Q(x)=(x^4+5x^3-x^2-x+1)-(x^4+2x^3-2x^2-3x+2)`
`P(x)-Q(x)= x^4+5x^3-x^2-x+1-x^4-2x^3+2x^2+3x-2`
`P(x)-Q(x)=(x^4-x^4)+(5x^3-2x^3)+(-x^2+2x^2)+(-x+3x)+(1-2)`
`P(x)-Q(x)=3x^3+x^2+2x-1`
kiến thức lớp 8 chắc mới làm dc
\(A=\left(1+\frac{1}{\left(2-1\right)\left(2+1\right)}\right)\left(1+\frac{1}{\left(3-1\right)\left(3+1\right)}\right)+....+\frac{1}{\left(100-1\right)\left(100+1\right)}\)
\(A=\left(1+\frac{1}{2^2}\right)\left(1+\frac{1}{3^2}\right)......\left(1+\frac{1}{100^2}\right)\)
ok tự giải típ nhé
A=(1+1/1.3)+........+(1+1/99.100)
=>A=[ (1.3+1)/(1.3 ) ] .[ (2.4+1)/(2.4) ] .... [ (99.101+1)/(99.101) ]
=>A=( 4/1.3 ).( 9/2.4)......( 10000/99.101)
=>A=( 22/1.3).( 32/2..4).......( 1002/99.101)
=>A=\(\frac{2^2.3^2........99^2.100^2}{1.3.2.4.....99.101}\)
=>A=\(\frac{2.3....100.2.3.....100}{1.2.....99.3.4.....101}\)
=>A=\(\frac{100.2}{101}\)
=>A=\(\frac{200}{101}\)
Vậy A=\(\frac{200}{101}\)
`@` `\text {Ans}`
`\downarrow`
`a)`
\(P(x) = 5x^3 + 3 - 3x^2 + x^4 - 2x - 2 + 2x^2 + x\)
`= x^4 + 5x^3 + (-3x^2 + 2x^2) + (-2x+x) + (3-2)`
`= x^4 + 5x^3 - x^2 - x + 1`
\(Q(x) = 2x^4 + x^2 + 2x + 2 - 3x^2 - 5x + 2x^3 - x^4\)
`= (2x^4 - x^4) + 2x^3 + (x^2 - 3x^2) + (2x-5x) + 2`
`= x^4 + 2x^3 - 2x^2 - 3x +2`
`b)`
`P(x)+Q(x) = (x^4 + 5x^3 - x^2 - x + 1) + (x^4 + 2x^3 - 2x^2 - 3x +2)`
`= x^4 + 5x^3 - x^2 - x + 1 + x^4 + 2x^3 - 2x^2 - 3x +2`
`= (x^4+x^4)+(5x^3 + 2x^3) + (-x^2 - 2x^2) + (-x-3x) + (1+2)`
`= 2x^4 + 7x^3 - 3x^2 - 4x + 3`
`P(x)-Q(x)=(x^4 + 5x^3 - x^2 - x + 1) - (x^4 + 2x^3 - 2x^2 - 3x +2)`
`= x^4 + 5x^3 - x^2 - x + 1 - x^4 - 2x^3 + 2x^2 + 3x -2`
`= (x^4 - x^4) + (5x^3 - 2x^3) + (-x^2+2x^2)+(-x+3x)+(1-2)`
`= 3x^3 + x^2 + 2x - 1`
`Q(x)-P(x) = (x^4 + 2x^3 - 2x^2 - 3x +2)-(x^4 + 5x^3 - x^2 - x + 1)`
`= x^4 + 2x^3 - 2x^2 - 3x +2-x^4 - 5x^3 + x^2 + x - 1`
`= (x^4-x^4)+(2x^3 - 5x^3)+(-2x^2+x^2)+(-3x+x)+(2-1)`
`= -3x^3 - x^2 - 2x + 1`
`@` `\text {Kaizuu lv u.}`
Ta có
2 ⋅ P ( x ) = 2 ⋅ − 6 x 5 − 4 x 4 + 3 x 2 − 2 x = − 12 x 5 − 8 x 4 + 6 x 2 − 4 x Khi dó 2 P ( x ) + Q ( x ) = − 12 x 5 − 8 x 4 + 6 x 2 − 4 x + 2 x 5 − 4 x 4 − 2 x 3 + 2 x 2 − x − 3
= - 12 x 5 - 8 x 4 + 6 x 2 - 4 x + 2 x 5 - 4 x 4 - 2 x 3 + 2 x 2 - x - 3 = - 12 x 5 + 2 x 5 + - 8 x 4 - 4 x 4 - 2 x 3 + 6 x 2 + 2 x 2 + ( - 4 x - x ) - 3 = - 10 x 5 - 12 x 4 - 2 x 3 + 8 x 2 - 5 x - 3
Chọn đáp án B
4
Thay \(x=2\) vào đa thức \(P\left(x\right)\), ta được:
\(P\left(2\right)=3.2^5-2.2^4-2.2^5-2.2^2-2+3.2^2+2\)
\(=3.32-2.16-2.32-2.4-2+3.4+2\)
\(=96-32-64-8-2+12+2\)
\(=4\)