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`7xx8xx12/6xx21xx16`
`=7xx8xx2xxx21xx16`
`=56xx2xx21xx16`
`=112xx21xx16`
`=2352xx16`
`=37632`
\(\dfrac{5}{6}-\dfrac{5}{8}+\dfrac{7}{12}=\dfrac{10}{48}+\dfrac{7}{12}=\dfrac{38}{48}\)
a) \(\left(9^4.8+9^4.5\right):\left(9^2.\left(10-1\right)\right)\)
=\(9^4.13:9^3=13.9=117\)
b) 100-(75-25)=100-50=50
Ta có: \(A=1-2+3-4+5-6+7-8+9\)
\(=(1+9)-(2+8)+(3+7)-(4+6)+5\)
\(=10-10+10-10+5\)
\(=5\)
Vậy \(A=5\)
B = 12 - 14 + 16 - 18 + ... + 2008 - 2010
B = -2 + (-2)+ (-2)+ (-2) + ...+ (-2)
B = -2 . 100
B = -200
a \(\Leftrightarrow3x=12\Leftrightarrow x=4\)
b \(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\2x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-\dfrac{3}{2}\end{matrix}\right.\)
c \(ĐKXĐ:x\ne2;x\ne-2\)
\(\Rightarrow\left(x+2\right)^2-6\left(x-2\right)=x^2\Leftrightarrow x^2+4x+4-6x+12=x^2\Leftrightarrow-2x+16=0\Leftrightarrow-2x=-16\Leftrightarrow x=8\left(TM\right)\)
a) Ta có: 3x-12=0
\(\Leftrightarrow3x=12\)
hay x=4
Vậy: S={4}
b) Ta có: (x-2)(2x+3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\2x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{-3}{2}\end{matrix}\right.\)
Vậy: \(S=\left\{2;\dfrac{-3}{2}\right\}\)
mk ko viết lại đề
\(A=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}+\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}+2^{12}.3^{12}}\)
\(=\frac{2^{12}.3^4\left(3-1\right)}{2^{12}.3^5\left(3+1\right)}+\frac{2^{12}.3^{10}\left(1+5\right)}{2.\left(2^{12}.3^{12}\right)}\)
\(=\frac{2}{3.4}+\frac{2^{12}.3^{10}.6}{2.2^{12}.3^{12}}=\frac{1}{6}+\frac{1}{3}=\frac{1}{2}\)
Vậy A= \(\frac{1}{2}\)
\(=\frac{5}{6}x\left(\frac{7}{12}+\frac{5}{12}\right)+\frac{1}{6}=\frac{5}{6}x1+\frac{1}{6}=1\)
a) \(\frac{5}{6}x\frac{7}{12}+\frac{5}{12}x\frac{5}{6}+\frac{1}{6}=\frac{5}{6}x\left(\frac{7}{12}+\frac{5}{12}\right)+\frac{1}{6}=\frac{5}{6}x1+\frac{1}{6}=\frac{5}{6}+\frac{1}{6}=1\)
b) \(\left(\frac{8}{15}x\frac{3}{4}x\frac{5}{4}\right):\frac{7}{8}=\frac{4x2x3x5}{5x3x4x4}x\frac{8}{7}=\frac{2}{4}x\frac{8}{7}=\frac{2x8}{4x7}=\frac{2x4x2}{4x7}=\frac{4}{7}\)
Chúc bạn học tốt.
😁😁😁
\(\frac{16}{7}x\frac{3}{8}-\frac{1}{3}=\frac{6}{7}-\frac{1}{3}=\frac{11}{21}\)
\(\frac{12}{6}x\frac{6}{3}+\frac{12}{6}=2x2+2=4+2=6\)
\(\left(\frac{12}{6}+\frac{12}{6}\right)x12=\left(2+2\right)x12=4x12=48\)
học tốt~~~
16/7 x 3/8 - 1/3 = 11/21
12/6 x 6/3 + 12/6 = 12/6 + ( 6/3 + 1) = 12/6 + 3=5
(12/6 +12/6) x 12 = 4 x 12 = 48
k mk nha