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6 tháng 5 2018

a) \(F=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+...+\frac{1}{990}\)

\(F=\frac{1}{3.6}+\frac{1}{6.9}+\frac{1}{9.12}+...+\frac{1}{30.33}\)

\(3F=\frac{3}{3.6}+\frac{3}{6.9}+\frac{3}{9.12}+...+\frac{3}{30.33}\)

\(3F=\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+...+\frac{1}{30}-\frac{1}{33}\)

\(3F=\frac{1}{3}-\frac{1}{33}\)

\(F=\frac{1}{3}.\left(\frac{1}{3}-\frac{1}{33}\right)\)

\(F=\frac{1}{3}.\frac{1}{3}-\frac{1}{3}.\frac{1}{33}=\frac{1}{9}-\frac{1}{99}=\frac{11}{99}-\frac{1}{99}=\frac{10}{99}\)

b) \(A=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)

\(A=7.\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+...+\frac{1}{69.70}\right)\)

\(A=7.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+...+\frac{1}{69}-\frac{1}{70}\right)\)

\(A=7.\left(\frac{1}{10}-\frac{1}{70}\right)=7.\left(\frac{7}{70}-\frac{1}{70}\right)=7.\frac{6}{70}\)

\(A=\frac{7.6}{70}=\frac{1.6}{10}=\frac{1.3}{5}=\frac{3}{5}\)

a, \(F=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+...+\frac{1}{990}\)

\(F=\frac{1}{3}\cdot\left(\frac{3}{3\cdot6}+\frac{3}{6\cdot9}+\frac{3}{9\cdot12}+...+\frac{3}{30\cdot33}\right)\)

\(F=\frac{1}{3}\cdot\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{30}-\frac{1}{33}\right)\)

\(F=\frac{1}{3}\cdot\left(\frac{1}{3}-\frac{1}{33}\right)\)

\(F=\frac{1}{3}-\frac{10}{33}\)

\(F=\frac{10}{99}\)

C=7/10x11+7/11x12+7/12x13+.................+7/69x70

C=1x7/10x11+1x7/11x12+...........+1x7/69x70

C=7(1/10x11+1/11x12+1/12x13+....+1/69x70)

C=7(1/10-1/11+1/11-1/12+1/12-1/13+.......+1/69-1/70)

C=7(1/10-1/70)

C=7(7/70-1/70)

C=7x6/70

C=3/5

27 tháng 7 2023

`A=7/(10*11)+7/(11*12)+7/(12*13)+...+7/(69*70)`

`1/7A=1/(10*11)+1/(11*12)+1/(12*13)+..+1/(69*70)`

`1/7A=1/10-1/11+1/11-1/12+1/12-1/13+...+1/69-1/70`

`1/7A=1/10-1/70`

`1/7A=7/70-1/70`

`1/7A=6/70`

`A=3/5`

27 tháng 7 2023

\(A=\dfrac{7}{10.11}+\dfrac{7}{11.12}+\dfrac{7}{12.13}+...+\dfrac{7}{69.70}\)

\(A=7.\left(\dfrac{1}{10.11}+\dfrac{1}{11.12}+\dfrac{1}{12.13}+...+\dfrac{1}{69.70}\right)\)

\(A=7\left(\dfrac{11-10}{10.11}+\dfrac{12-11}{11.12}+\dfrac{13-12}{12.13}+...+\dfrac{70-69}{69.70}\right)\)

\(A=7.\left(\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{13}+...+\dfrac{1}{69}-\dfrac{1}{70}\right)\)

\(A=7.\left(\dfrac{1}{10}-\dfrac{1}{70}\right)\)

\(A=7.\dfrac{3}{35}=\dfrac{3}{5}\)

30 tháng 7 2016

\(A=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)

    \(=7.\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+...+\frac{1}{69.70}\right)\)

    \(=7.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+...+\frac{1}{69}-\frac{1}{70}\right)\)

    \(=7.\left(\frac{1}{10}-\frac{1}{70}\right)\)

      \(=7.\frac{3}{35}=\frac{3}{5}\)

30 tháng 7 2016

\(A=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\) 

\(A=1\left(\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\right)\)

\(A=7\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+...+\frac{1}{69.70}\right)\)

\(A=7\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)

\(A=7\left(\frac{1}{10}-\frac{1}{70}\right)=7.\frac{3}{35}=\frac{3}{5}\)

15 tháng 4 2015

 

C=7/10x11+7/11x12+7/12x13+.................+7/69x70

C=1x7/10x11+1x7/11x12+...........+1x7/69x70

C=7(1/10x11+1/11x12+1/12x13+....+1/69x70)

C=7(1/10-1/11+1/11-1/12+1/12-1/13+.......+1/69-1/70)

C=7(1/10-1/70)

C=7(7/70-1/70)

C=7x6/70

C=3/5

 

8 tháng 6 2016

\(=7.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+....+\frac{1}{69}-\frac{1}{70}\right)\)

\(=7.\left(\frac{1}{10}-\frac{1}{70}\right)\)

\(=7.\frac{3}{35}\)

\(=\frac{3}{5}\)

= 7/10-7/11+7/11-7/12+7/12-7/13+...+7/69-7/70

=7/10-7/70

=42/70

k mk nha

7/10x11+7/11x12+7/12x13+.................+7/69x70
=1x7/10x11+1x7/11x12+...........+1x7/69x70
=7(1/10x11+1/11x12+1/12x13+....+1/69x70)
=7(1/10‐1/11+1/11‐1/12+1/12‐1/13+.......+1/69‐1/70)
=7(1/10‐1/70)
=7(7/70‐1/70)
=7x6/70

=3/5

NHỚ TK MK NHA

13 tháng 8 2017

\(\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}=\)

\(7\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)

\(=7.\left(\frac{1}{10}-\frac{1}{70}\right)=7.\frac{7-1}{70}=\frac{6}{10}=\frac{3}{5}\)

15 tháng 6 2016

1/10×11 + 1/11×12 + 1/12×13 + ... + 1/999×1000

= 1/10 - 1/11 + 1/11 - 1/12 + 1/12 - 1/13 + ... + 1/999 - 1/1000

= 1/10 - 1/1000

= 100/1000 - 1/1000

= 99/1000

1/10×11 + 1/11×12 + 1/12×13 + ... + 1/999×1000

= 1/10 - 1/11 + 1/11 - 1/12 + 1/12 - 1/13 + ... + 1/999 - 1/1000

= 1/10 - 1/1000

= 100/1000 - 1/1000

= 99/1000

1 tháng 11 2014

mới đầu mình cũng định làm như lê thành đạt , nhưng x là dấu nhân thì đâu thể làm theo cách đấy .

vd:1/(10x11)x1/(11x12) khác vs 1/(10x11)+1/(11x12)

hay cậu cho đề sai ????