$\dfrac{4}{\left(2 \dfrac{2}{1 \dfrac{4}{5}}\right)x-\left(1 \dfrac{4}{2 \dfrac{1}{1 \dfrac{7}{8}}}\right)} \dfrac{1}{\left(2 \dfrac{1}{3 \dfrac{1}{4}}\right)}=4 \dfrac{2}{1 \dfrac{8}{9}}$Tìm x biết...

LH

Lan Hương

1 tháng 10 2023

$\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}$

2

VN

Võ Ngọc Phương

CTVHS VIP

1 tháng 10 2023

$\left(3-x\right)^3=-\dfrac{27}{64}$

$\left(3-x\right)^3=\left(\dfrac{-3}{4}\right)^3$

$=>3-x=\dfrac{-3}{4}$

$x=3-\dfrac{-3}{4}=\dfrac{12}{4}+\dfrac{3}{4}$

$x=\dfrac{15}{4}$

________

$\left(x-5\right)^3=\dfrac{1}{-27}$

$\left(x-5\right)^3=\left(\dfrac{-1}{3}\right)^3$

$=>x-5=\dfrac{-1}{3}$

$x=\dfrac{-1}{3}+5=\dfrac{-1}{3}+\dfrac{15}{3}$

$x=\dfrac{14}{3}$

_____________

$\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8}$

$\left(x-\dfrac{1}{2}\right)^3=\left(\dfrac{3}{2}\right)^3$

$=>x-\dfrac{1}{2}=\dfrac{3}{2}$

$x=\dfrac{3}{2}+\dfrac{1}{2}$

$x=2$

________

$\left(2x-1\right)^2=\dfrac{1}{4}$

$\left(2x-1\right)^2=\left(\dfrac{1}{2}\right)^2$ hoặc $\left(2x-1\right)^2=\left(\dfrac{-1}{2}\right)^2$

$=>2x-1=\dfrac{1}{2}$ $2x-1=\dfrac{-1}{2}$

$2x=\dfrac{1}{2}+1=\dfrac{1}{2}+\dfrac{2}{2}$ $2x=\dfrac{-1}{2}+1=\dfrac{-1}{2}+\dfrac{2}{2}$

$2x=\dfrac{3}{2}$ $2x=\dfrac{1}{2}$

$x=\dfrac{3}{2}:2=\dfrac{3}{2}.\dfrac{1}{2}$ $x=\dfrac{1}{2}:2=\dfrac{1}{2}.\dfrac{1}{2}$

$x=\dfrac{3}{4}$ $x=\dfrac{1}{4}$

____________

$\left(2-3x\right)^2=\dfrac{9}{4}$

$\left(2-3x\right)^2=\left(\dfrac{3}{2}\right)^2$ hoặc $\left(2-3x\right)^2=\left(\dfrac{-3}{2}\right)^2$

$=>2-3x=\dfrac{3}{2}$ $2-3x=\dfrac{-3}{2}$

$3x=2-\dfrac{3}{2}=\dfrac{4}{2}-\dfrac{3}{2}$ $3x=2-\dfrac{-3}{2}=\dfrac{4}{2}+\dfrac{3}{2}$

$3x=\dfrac{1}{2}$ $3x=\dfrac{7}{2}$

$x=\dfrac{1}{2}.\dfrac{1}{3}$ $x=\dfrac{7}{2}.\dfrac{1}{3}$

$x=\dfrac{1}{6}$ $x=\dfrac{7}{6}$

______________

$\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}$ -> Kiểm tra đề câu này

Đúng(2)

DD

Đồng Đạo Quang Tiến

1 tháng 10 2023

(3-x)³^{_{=(-$\dfrac{3}{4}$)}}³

^{3-x=-$\dfrac{3}{4}$}

^{x=3-(-$\dfrac{3}{4}$}⁾

^{x=$\dfrac{15}{4}$}

NK

Nezuko Kamado

29 tháng 10 2021

Tìm x :

1) $\left(-0,75x+\dfrac{5}{2}\right).\dfrac{4}{7}-\left(-\dfrac{1}{3}\right)=-\dfrac{5}{6}$

2) $\left(4x-9\right)\left(2,5+\dfrac{-7}{3}x\right)=0$

3) $\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0$

4)$\left(\dfrac{3}{5}-\dfrac{2}{3}x\right)^3=\dfrac{-64}{125}$

ĐỀ 1: 1. Tính: a. $\dfrac{7}{23}\left[\left(\dfrac{-8}{6}\right)-\dfrac{45}{18}\right]$ b. $\dfrac{1}{5}:\dfrac{1}{10}-\dfrac{1}{3}\left(\dfrac{6}{5}-\dfrac{9}{4}\right)$ c. $\dfrac{3}{5}.\left(\dfrac{-8}{3}\right)-\dfrac{3}{5}:\left(-6\right)$ d. $\dfrac{1}{2}\left(\dfrac{4}{3}+\dfrac{2}{5}\right)-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)$ e. $\dfrac{6}{7}:\left(\dfrac{3}{26}-\dfrac{3}{13}\right)+\dfrac{6}{7}\left(\dfrac{1}{10}-\dfrac{8}{5}\right)$ 2. Tìm x,...

1

NL

Nguyễn Lê Phước Thịnh

29 tháng 10 2021

3: $\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0$

$\Leftrightarrow\left|x-\dfrac{3}{4}\right|=\dfrac{1}{2}$

$\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{2}\\x-\dfrac{3}{4}=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{1}{4}\end{matrix}\right.$

Đúng(2)

LT

Lê Thị Ngọc Duyên

20 tháng 8 2017

1

TT

Thanh Trà

20 tháng 8 2017

1.Tính

a.$\dfrac{7}{23}\left[(-\dfrac{8}{6})-\dfrac{45}{18}\right]=\dfrac{7}{23}.-\dfrac{12}{6}=-\dfrac{7}{6}$

b.$\dfrac{1}{5}\div\dfrac{1}{10}-\dfrac{1}{3}(\dfrac{6}{5}-\dfrac{9}{4})=2-(-\dfrac{7}{20})=\dfrac{47}{20}$

c.$\dfrac{3}{5}.(-\dfrac{8}{3})-\dfrac{3}{5}\div(-6)=-\dfrac{3}{2}$

d.$\dfrac{1}{2}.(\dfrac{4}{3}+\dfrac{2}{5})-\dfrac{3}{4}.(\dfrac{8}{9}+\dfrac{16}{3})=-\dfrac{19}{5}$

e.$\dfrac{6}{7}\div(\dfrac{3}{26}-\dfrac{3}{13})+\dfrac{6}{7}.(\dfrac{1}{10}-\dfrac{8}{5})=-\dfrac{61}{7}$

Bài 2

a.$1^2_5x+\dfrac{3}{7}=\dfrac{4}{5}$

$x=\dfrac{13}{49}$

b.$\left|x-1,5\right|=2$

Xảy ra 2 trường hợp

TH1

$x-1,5=2$

$x=3,5$

TH2

$x-1,5=-2$

$x=-0,5$

Vậy $x=3,5$ hoặc $x=-0,5$ .

Ngại làm quá trời ơi,lần sau bn tách ra nhá làm vậy mỏi tay quá.

LT

Lê Thị Ngọc Duyên

20 tháng 8 2017

Ths bn nhé

Tìm x, biết:a) x+$\dfrac{1}{6}$=$\dfrac{-3}{8}$ b) $2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}$c) $\dfrac{1}{2}x$+$\dfrac{1}{8}x=\dfrac{3}{4}$ d)...

LN

Lê Ngọc Anh

8 tháng 3 2022

#Toán lớp 6

2

HP

hưng phúc

8 tháng 3 2022

$a.x+\dfrac{1}{6}=-\dfrac{3}{8}$

$\Leftrightarrow x=-\dfrac{13}{24}$

$b.2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}$

$\Leftrightarrow2-\dfrac{3}{4}+x=\dfrac{7}{12}$

$\Leftrightarrow x=-\dfrac{2}{3}$

$c.\dfrac{1}{2}x+\dfrac{1}{8}x=\dfrac{3}{4}$

$\Leftrightarrow\dfrac{5}{8}x=\dfrac{3}{4}$

$\Leftrightarrow x=\dfrac{6}{5}$

$d.75\%-1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2$

$=\dfrac{75}{100}-\dfrac{3}{2}+\dfrac{1}{2}:\dfrac{5}{12}-\dfrac{1}{4}$

$=-\dfrac{3}{4}+\dfrac{6}{5}-\dfrac{1}{4}$

$=\dfrac{1}{5}$

Đúng(1)

DC

dâu cute

8 tháng 3 2022

a) $x+\dfrac{1}{6}=\dfrac{-3}{8}$

$x=\dfrac{-3}{8}-\dfrac{1}{6}$

$x=\dfrac{-13}{24}$

vậy x =....

b) $2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}$

$\dfrac{3}{4}-x=2-\dfrac{7}{12}$

$\dfrac{3}{4}-x=\dfrac{17}{12}$

$x=\dfrac{3}{4}-\dfrac{17}{12}$

$x=\dfrac{-2}{3}$

vậy x =....

Đúng(1)

NT

Nguyễn Thu Huyền

1 tháng 9 2023

Tìm...

$a,\dfrac{-8}{5}:\left(1+\dfrac{2}{3}\right)$ $b,\dfrac{7}{5}x\dfrac{15}{49}-\left(\dfrac{4}{5}+\dfrac{2}{3}\right):\dfrac{11}{5}$$c,\dfrac{1}{3}:\left(\dfrac{2}{9}-\dfrac{7}{8}\right)$ $d,\left(\dfrac{1}{6}-\dfrac{4}{5}\right):\dfrac{7}{5}$Giúp mik...

3

T

Toru

1 tháng 9 2023

$a,3-x=x+1,8$

$\Rightarrow-x-x=1,8-3$

$\Rightarrow-2x=-1,2$

$\Rightarrow x=0,6$

$b,2x-5=7x+35$

$\Rightarrow2x-7x=35+5$

$\Rightarrow-5x=40$

$\Rightarrow x=-8$

$c,2\left(x+10\right)=3\left(x-6\right)$

$\Rightarrow2x+20=3x-18$

$\Rightarrow2x-3x=-18-20$

$\Rightarrow-x=-38$

$\Rightarrow x=38$

$d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x$

$\Rightarrow8x-3+1=1+6x+x$

$\Rightarrow8x-3=7x$

$\Rightarrow8x-7x=3$

$\Rightarrow x=3$

$e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x$

$\Rightarrow-3x+x=\dfrac{4}{3}-\dfrac{2}{9}$

$\Rightarrow-2x=\dfrac{10}{9}$

$\Rightarrow x=-\dfrac{5}{9}$

Đúng(3)

T

Toru

1 tháng 9 2023

$g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}$

$\Rightarrow\dfrac{1}{2}x-\dfrac{3}{4}x=-\dfrac{1}{2}-\dfrac{5}{6}$

$\Rightarrow-\dfrac{1}{4}x=-\dfrac{4}{3}$

$\Rightarrow x=\dfrac{16}{3}$

$h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)$

$\Rightarrow x-4=5-x$

$\Rightarrow x+x=5+4$

$\Rightarrow2x=9$

$\Rightarrow x=\dfrac{9}{2}$

$k,7x^2-11=6x^2-2$

$\Rightarrow7x^2-6x^2=-2+11$

$\Rightarrow x^2=9\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.$

$m,5\left(x+3\cdot2^3\right)=10^2$

$\Rightarrow5\left(x+24\right)=100$

$\Rightarrow x+24=20$

$\Rightarrow x=-4$

$n,\dfrac{4}{9}-\left(\dfrac{1}{6^2}\right)=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}$

$\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}=\dfrac{4}{9}-\dfrac{1}{36}$

$\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}=\dfrac{5}{12}$

$\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2=0$

$\Rightarrow x-\dfrac{2}{3}=0\Rightarrow x=\dfrac{2}{3}$

#$Urushi\text{☕}$

Đúng(3)

QN

quan nguyen hoang

13 tháng 2 2022

#Toán lớp 6

1

DD

Đinh Đức Anh

13 tháng 2 2022

A -$\dfrac{24}{25}$

B -$\dfrac{5}{21}$

C -$\dfrac{24}{47}$

D -$\dfrac{19}{42}$

tick cho mk

Đúng(2)

I

ILoveMath

13 tháng 2 2022

trả lời hẳn ra sao bạn cứ chỉ ghi kết quả thế

Đúng(1)

TD

Thầy Đức Anh

Giáo viên VIP

27 tháng 4 2022

Tìm $x$, biết :
a) $\left(\dfrac{1}{2}+1,5\right) \cdot x=\dfrac{1}{5}$
b) $\left(-1 \dfrac{3}{5}+x\right): \dfrac{12}{13}=2 \dfrac{1}{6}$
c) $\left(x: 2 \dfrac{1}{3}\right) \cdot \dfrac{1}{7}=\dfrac{-3}{8}$
d) $\dfrac{-4}{7} \cdot x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1 \dfrac{2}{3}\right)$

13

YN

Yen Nhi

21 tháng 6 2022

$a)\left(\dfrac{1}{2}+1,5\right)x=\dfrac{1}{5}$

$\Rightarrow2x=\dfrac{1}{5}$

$\Rightarrow x=\dfrac{1}{10}$

$b)\left(-1\dfrac{3}{5}+x\right):\dfrac{12}{13}=2\dfrac{1}{6}$

$\Leftrightarrow-\dfrac{8}{5}+x=\dfrac{13}{6}.\dfrac{12}{13}$

$\Leftrightarrow-\dfrac{8}{5}+x=2$

$\Leftrightarrow x=\dfrac{18}{5}$

$c)\left(x:2\dfrac{1}{3}\right).\dfrac{1}{7}=-\dfrac{3}{8}$

$\Leftrightarrow x:\dfrac{7}{3}=-\dfrac{3}{8}:\dfrac{1}{7}$

$\Leftrightarrow x=-\dfrac{21}{8}.\dfrac{7}{3}$

$\Leftrightarrow x=-\dfrac{49}{8}$

$d)-\dfrac{4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1\dfrac{2}{3}\right)$

$\Leftrightarrow-\dfrac{4}{7}x+\dfrac{7}{5}=-\dfrac{3}{40}$

$\Leftrightarrow-\dfrac{4}{7}x=-\dfrac{59}{40}$

$\Leftrightarrow x=\dfrac{413}{160}$

T

TINH

13 tháng 7 2022

a) $\left(\dfrac{1}{2}+1,5\right) \cdot x=\dfrac{1}{5}$

$\cdot x=\dfrac{1}{5}$

$x=\dfrac{1}{5}: 2$

$x=\dfrac{1}{10}$
b) $\left(-1 \dfrac{3}{5}+x\right): \dfrac{12}{13}=2 \dfrac{1}{6}$

$\dfrac{3}{5}+x=\dfrac{13}{6} \cdot \dfrac{12}{13}$
$\dfrac{3}{5}$

$\dfrac{3}{5}$
c) $\left(x: 2 \dfrac{1}{3}\right) \cdot \dfrac{1}{7}=\dfrac{-3}{8}$

$\cdot \dfrac{3}{7} \cdot \dfrac{1}{7}=\dfrac{-3}{8}$

$x=\dfrac{-3}{8}: \dfrac{3}{49}$
$x=\dfrac{-49}{8}=-6 \dfrac{1}{8}$
d) $\dfrac{-4}{7} \cdot x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1 \dfrac{2}{3}\right)$

$\dfrac{-4}{7} x+\dfrac{7}{5}=\dfrac{1}{8} \cdot \dfrac{-3}{5}$
$-\dfrac{4}{7} x=\dfrac{-3}{40}-\dfrac{7}{5} \\ x=\dfrac{-59}{40}: \dfrac{-4}{7}=\dfrac{413}{160}=2 \dfrac{93}{160}$

1. tìm xa, 2x - $\dfrac{1}{2}$ : $\dfrac{3}{4}$ = $\dfrac{12}{9}$b, x$^2$ - 2 = 02. Cho A = $\dfrac{1,11+0,19-13.2}{2,06+0,54}$ - $\left(\dfrac{1}{2}+\dfrac{1}{4}\right)$ : 2B = $\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right)$ : $2\dfrac{23}{26}$a, Rút gọn A, Bb, Tìm x ϵ Z để A < x <...

HG

Hoàng Giang

25 tháng 12 2023

2

TD

Trần Đức Hải Phong

25 tháng 12 2023

a)
=$2x-\dfrac{1}{2}=\dfrac{12}{9}\cdot\dfrac{3}{4}=1$
=$2x=1+\dfrac{1}{2}=1.5$
=$x=1.5:2=0.75$
b)
=$x^2=0+2=2$
TH1:$x=2$
TH2:$x=-2$

NL

Nguyễn Lê Phước Thịnh

31 tháng 12 2023

Bài 1:

a: $2x-\dfrac{1}{2}:\dfrac{3}{4}=\dfrac{12}{9}$

=>$2x-\dfrac{1}{2}\cdot\dfrac{4}{3}=\dfrac{4}{3}$

=>$2x=\dfrac{4}{3}+\dfrac{2}{3}=\dfrac{6}{3}=2$

=>x=2/2=1

b: $x^2-2=0$

=>$x^2=2$

=>$\left[{}\begin{matrix}x=\sqrt{2}\\x=-\sqrt{2}\end{matrix}\right.$

Bài 2:

a: $A=\dfrac{1,11+0,19-13\cdot2}{2,06+0,54}-\left(\dfrac{1}{2}+\dfrac{1}{4}\right):2$

$=\dfrac{1,3-26}{2,6}-\dfrac{3}{4}:2$

$=-9,5-\dfrac{3}{8}=-\dfrac{79}{8}$

$B=\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right):\left(2\dfrac{23}{26}\right)$

$=\left(5+\dfrac{7}{8}-2-\dfrac{1}{4}-\dfrac{1}{2}\right):\dfrac{75}{26}$

$=\left(3+\dfrac{1}{8}\right)\cdot\dfrac{26}{75}=\dfrac{25}{8}\cdot\dfrac{26}{75}=\dfrac{13}{12}$

b: A<x<B

=>$-\dfrac{79}{8}< x< \dfrac{13}{12}$

mà $x\in Z$

nên $x\in\left\{-9;-8;...;0;1\right\}$

Câu 1: Tinh $A=\left(\dfrac{3}{5}\right)^2.5^2-\left(2\dfrac{1}{4}\right)^3:\left(\dfrac{3}{4}\right)^3+\dfrac{1}{2}$ $B=\left[\dfrac{4}{11}.\left(\dfrac{1}{25}\right)^0+\dfrac{7}{22}.2\right]^{2010}-\left(\dfrac{1}{2^2}:\dfrac{8^2}{4^4}\right)^{2009}$ $\dfrac{7}{8}.\left(\dfrac{2}{12}+\dfrac{4}{10}\right)$ $\dfrac{3}{2}-\dfrac{5}{6}:\left(\dfrac{1}{2}\right)^2+\sqrt{4}$ Câu 2: Tim...

NC

Nguyễn Châu Mỹ Linh

8 tháng 11 2018

2

RT

Rimuru tempest

8 tháng 11 2018

câu 1 $A=\dfrac{3^2}{5^2}.5^2-\dfrac{9^3}{4^3}:\dfrac{3^3}{4^3}+\dfrac{1}{2}$

$A=\dfrac{3^2}{5^2}.5^2-\dfrac{\left(3^2\right)^3}{4^3}.\dfrac{4^3}{3^3}+\dfrac{1}{2}$

$A=\dfrac{3^2}{5^2}.5^2-\dfrac{3^6}{4^3}.\dfrac{4^3}{3^3}+\dfrac{1}{2}=3^2-3^3+\dfrac{1}{2}=-18+\dfrac{1}{2}=-\dfrac{35}{2}$

$B=\left[\dfrac{4}{11}+\dfrac{7}{22}.2\right]^{2010}-\left(\dfrac{1}{2^2}.\dfrac{4^4}{8^2}\right)^{2009}$

$B=\left[\dfrac{4}{11}+\dfrac{7}{11}\right]^{2010}-\left(\dfrac{1}{2^2}.\dfrac{\left(2^2\right)^4}{\left(2^3\right)^2}\right)^{2009}$

$B=1^{2010}-\left(\dfrac{1}{2^2}.\dfrac{2^8}{2^6}\right)^{2009}$

$B=1^{2010}-\left(\dfrac{2^8}{2^8}\right)^{2009}$

$B=1^{2010}-1^{2009}=1-1=0$

RT

Rimuru tempest

8 tháng 11 2018

câu 2

a) $2x-\dfrac{5}{4}=\dfrac{20}{15}$

$\Leftrightarrow2x=\dfrac{4}{3}+\dfrac{5}{4}$

$\Leftrightarrow2x=\dfrac{31}{12}$

$\Leftrightarrow x=\dfrac{31}{24}$

b) $\left(x+\dfrac{1}{3}\right)^3=\left(-\dfrac{1}{2}\right)^3$

$\Leftrightarrow x+\dfrac{1}{3}=-\dfrac{1}{2}$

$\Leftrightarrow x=-\dfrac{1}{2}-\dfrac{1}{3}$

$\Leftrightarrow x=-\dfrac{5}{6}$