11) $\dfrac{1}{3}$x $\dfrac{1}{5}$ - $\dfrac{1}{2}$x = 1$\dfrac{1}{4}$ 12) $\dfrac{3}{2}$( x $\dfrac{1}{2}$) - $\dfrac{1}{8}$x = $\dfrac{1}{4}$ 13) $\dfrac{3}{5}$( x \(\dfrac...

1

HH

Hắc Hường

18 tháng 6 2018

Giải:

a) $\dfrac{1}{3}x+\dfrac{1}{5}-\dfrac{1}{2}x=1\dfrac{1}{4}$

$\Leftrightarrow\dfrac{1}{5}-\dfrac{1}{6}x=\dfrac{5}{4}$

$\Leftrightarrow\dfrac{1}{6}x=\dfrac{-21}{20}$

$\Leftrightarrow x=\dfrac{-63}{10}$

Vậy ...

b) $\dfrac{3}{2}\left(x+\dfrac{1}{2}\right)-\dfrac{1}{8}x=\dfrac{1}{4}$

$\Leftrightarrow\dfrac{3}{2}x+\dfrac{3}{4}-\dfrac{1}{8}x=\dfrac{1}{4}$

$\Leftrightarrow\dfrac{11}{8}x=\dfrac{-1}{2}$

$\Leftrightarrow x=\dfrac{-4}{11}$

Vậy ...

Các câu sau làm tương tự câu b)

$\dfrac{1}{5}+\dfrac{2}{11} \dfrac{x}{55} \dfrac{2}{5}+\dfrac{1}{5}$ $\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6} x\le\dfrac{13}{4}+\dfrac{14}{8}$ $\dfrac{1}{4}+\dfrac{5}{12}+\dfrac{-1}{13} x \dfrac{7}{5}+\dfrac{2}{10}+\dfrac{1}{2}$ \(\dfrac{79}{15}+\dfrac{7}{5}+\dfrac{-8}{3}\le...

VM

Vương Minh Phong

25 tháng 3 2022

#Toán lớp 6

3

HG

Hương Giang Vũ

25 tháng 3 2022

$\dfrac{1}{5}+\dfrac{2}{11}< \dfrac{x}{55}< \dfrac{2}{5}+\dfrac{1}{5}$

$\dfrac{11+10}{55}< \dfrac{x}{55}< \dfrac{3}{5}$

$\dfrac{21}{55}< \dfrac{x}{55}< \dfrac{33}{55}$

Vậy $x\in\left\{22;23;24;...\right\}$

VM

Vương Minh Phong

25 tháng 3 2022

$\dfrac{????????}{????????????}$

TT

Trần Thị Đào

5 tháng 7 2017

5. $3-1\dfrac{1}{2}-x+\dfrac{5}{4}=2-\left|1\dfrac{1}{8}-\dfrac{5}{12}\right|$ 6. $3\dfrac{1}{14}-5\dfrac{1}{3}-\dfrac{4}{7}+\dfrac{11}{21}=x-\dfrac{1}{2}$ 7. $\dfrac{11}{-40}+\dfrac{4}{5}-\left|\dfrac{3}{4}-1\dfrac{5}{12}\right|=\dfrac{3}{20}-x$

2

NH

Nguyễn Hải Dương

5 tháng 7 2017

chắc h có mấy thành cay r nên ko làm bn lên mạng tải phẩn mêm có cánh iair đó :D

NK

Như Khương Nguyễn

5 tháng 7 2017

@Đoàn Đức Hiếu

LH

Lưu huỳnh ngọc

11 tháng 8 2021

1/ $\dfrac{5x+1}{8}-\dfrac{x-2}{4}=\dfrac{1}{2}$

2/ $\dfrac{x+3}{4}+\dfrac{1-3x}{3}=\dfrac{-x+1}{18}$

3/ $\dfrac{x+2}{4}-\dfrac{5x}{6}=\dfrac{1-x}{3}$

4/ $\dfrac{x-3}{2}-\dfrac{x+1}{10}=\dfrac{x-2}{5}$

5/ $\dfrac{4x+1}{4}-\dfrac{9x-5}{12}+\dfrac{x-2}{3}=0$

#Toán lớp 8

2

NL

Nguyễn Lê Phước Thịnh

11 tháng 8 2021

1: Ta có: $\dfrac{5x+1}{8}-\dfrac{x-2}{4}=\dfrac{1}{2}$

$\Leftrightarrow5x+1-2\left(x-2\right)=4$

$\Leftrightarrow5x+1-2x+4=4$

$\Leftrightarrow3x=-1$

hay $x=-\dfrac{1}{3}$

2: Ta có: $\dfrac{x+3}{4}+\dfrac{1-3x}{3}=\dfrac{-x+1}{18}$

$\Leftrightarrow9x+27+12-36x=-2x+2$

$\Leftrightarrow-27x+2x=2-39$

hay $x=\dfrac{37}{25}$

3: Ta có: $\dfrac{x+2}{4}-\dfrac{5x}{6}=\dfrac{1-x}{3}$

$\Leftrightarrow3x+6-10x=4-4x$

$\Leftrightarrow-7x+4x=4-6=-2$

hay $x=\dfrac{2}{3}$

NL

Nguyễn Lê Phước Thịnh

11 tháng 8 2021

4: Ta có: $\dfrac{x-3}{2}-\dfrac{x+1}{10}=\dfrac{x-2}{5}$

$\Leftrightarrow5x-15-x-1=2x-4$

$\Leftrightarrow4x-2x=-4+16=12$

hay x=6

5: Ta có: $\dfrac{4x+1}{4}-\dfrac{9x-5}{12}+\dfrac{x-2}{3}=0$

$\Leftrightarrow12x+3-9x+5+4x-8=0$

$\Leftrightarrow7x=0$

hay x=0

HL

Hao Le Tuan

4 tháng 5 2022

$\dfrac{3}{2}X-0,2=\dfrac{3}{5}$

$\dfrac{1}{3}+x=\dfrac{3}{4}$

$1\dfrac{1}{2}x-\dfrac{2}{5}=\dfrac{1}{4}$

$\dfrac{11}{8}-\dfrac{3}{8}.x=\dfrac{1}{8}$

giúp với

#Toán lớp 6

1

O

★彡✿ทợท彡★

4 tháng 5 2022

$\dfrac{3}{2}x-0,2=\dfrac{3}{5}$

$\dfrac{3}{2}x-\dfrac{1}{5}=\dfrac{3}{5}$

$\dfrac{3}{2}x=\dfrac{3}{5}+\dfrac{1}{5}$

$\dfrac{3}{2}x=\dfrac{4}{5}$

$x=\dfrac{4}{5}:\dfrac{3}{2}$

$x=\dfrac{4}{5}\cdot\dfrac{2}{3}$

$x=\dfrac{8}{15}$

$\dfrac{1}{3}+x=\dfrac{3}{4}$

$x=\dfrac{3}{4}-\dfrac{1}{3}$

$x=\dfrac{9}{12}-\dfrac{4}{12}$

$x=\dfrac{5}{12}$

$1\dfrac{1}{2}x-\dfrac{2}{5}=\dfrac{1}{4}$

$\dfrac{3}{2}x-\dfrac{2}{5}=\dfrac{1}{4}$

$\dfrac{3}{2}x=\dfrac{1}{4}+\dfrac{2}{5}$

$\dfrac{3}{2}x=\dfrac{13}{20}$

$x=\dfrac{13}{20}:\dfrac{3}{2}$

$x=\dfrac{13}{20}\cdot\dfrac{2}{3}$

$x=\dfrac{13}{30}$

$\dfrac{11}{8}-\dfrac{3}{8}\cdot x=\dfrac{1}{8}$

$\dfrac{3}{8}\cdot x=\dfrac{11}{8}-\dfrac{1}{8}$

$\dfrac{3}{8}\cdot x=\dfrac{5}{4}$

$x=\dfrac{5}{4}:\dfrac{3}{8}$

$x=\dfrac{5}{4}\cdot\dfrac{8}{3}$

$x=\dfrac{10}{3}$

Tìm x:$\dfrac{3}{5}$ : x = $\dfrac{1}{3}+\dfrac{1}{2}$ x : $\dfrac{7}{12}$ = 2 x - $\dfrac{3}{2}$ = $\dfrac{11}{4}-\dfrac{5}{4}$ x...

NL

Nguyễn Linh

5 tháng 2 2022

Giải các phương trình sau:

$e.\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}$

$f.\dfrac{6x+1}{x^2-7x+10}+\dfrac{5}{x-2}=\dfrac{3}{x-5}$

$g.\dfrac{2}{x+2}-\dfrac{2x^2+16}{x^3+8}=\dfrac{5}{x^2-2x+4}$

$h.\dfrac{8}{x-8}+\dfrac{11}{x-11}=\dfrac{9}{x-9}+\dfrac{10}{x-10}$

#Toán lớp 8

1

DT

Đào Tùng Dương

5 tháng 2 2022

e) ĐK : $\left\{{}\begin{matrix}1+3x\ne0\\1-3x\ne0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3x\ne-1\\3x\ne1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ne\dfrac{-1}{3}\\x\ne\dfrac{1}{3}\end{matrix}\right.$

$\Leftrightarrow\dfrac{12}{\left(1-3x\right)\left(1+3x\right)}=\dfrac{\left(1-3x\right)^2-\left(1+3x\right)^2}{\left(1+3x\right)\left(1-3x\right)}$

$\Leftrightarrow12\left(1+3x\right)\left(1-3x\right)=\left(1-3x\right)\left(1+3x\right)\left(1-3x-1-3x\right)\left(1-3x+1+3x\right)$

$\Leftrightarrow12=\left(-6x\right).2\Leftrightarrow6=-6x$

$\Leftrightarrow x=-1\left(TM\right)$

Đúng(1)

MC

Minh Châu Trần

16 tháng 10 2023

#Toán lớp 5

1

H

⭐Hannie⭐

16 tháng 10 2023

`3/5 : x =1/3 +1/2`

` 3/5 : x= 2/6 +3/6`

` 3/5 : x= 5/6`

` x= 3/5 : 5/6`

` x= 3/5 xx 6/5`

` x= 18/25`

__

`x: 7/15 =2`

` x= 2xx 7/15`

` x= 14/15`

__

`x-3/2=11/4-5/4`

`x-3/2= 6/4`

`x= 3/2 +3/2`

`x= 6/2`

`x=3`

__

`x+5/4 = 3/2+7/12`

`x+5/4 = 18/12+7/12`

`x+5/4 = 25/12`

`x= 25/12-5/4`

`x= 25/12- 15/12`

`x= 10/12`

`x= 5/6`

Đúng(2)

TT

Trần Thị Đào

5 tháng 7 2017

5. $3-1\dfrac{1}{2}-x+\dfrac{5}{4}=2-\left|1\dfrac{1}{8}-\dfrac{5}{12}\right|$ 6. $3\dfrac{1}{14}-5\dfrac{1}{3}-\dfrac{4}{7}+\dfrac{11}{21}=-\dfrac{1}{2}$ 7. $\dfrac{11}{-40}+\dfrac{4}{5}-\left|\dfrac{3}{4}-1\dfrac{5}{12}\right|=\dfrac{3}{20}-X$

Giải các phương trình sau: (TM ĐK) 1) $\dfrac{11}{x}=\dfrac{9}{x+1}+\dfrac{2}{x-4}$ 2) $\dfrac{14}{3x-12}-\dfrac{2+x}{x-4}=\dfrac{3}{8-2x}-\dfrac{5}{6}$ 3) $\dfrac{x+5}{x^2-5x}-\dfrac{x+25}{2x^2-50}=\dfrac{x-5}{2x^2+10}$ 4) $\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{16}{x^2-1}$ 5) $\left(1-\dfrac{x-1}{x+1}\right)\left(x+2\right)=\dfrac{x+1}{x-1}+\dfrac{x-1}{x+1}$ mng giúp mk bài này nha. Cảm ơn bạn...

0

TA

Tuyet Anh Lai

17 tháng 1 2023

#Toán lớp 8

1

Y

YangSu

17 tháng 1 2023

$1,\left(dk:x\ne0,-1,4\right)$

$\Leftrightarrow\dfrac{9}{x+1}+\dfrac{2}{x-4}-\dfrac{11}{x}=0$

$\Leftrightarrow\dfrac{9x\left(x-4\right)+2x\left(x+1\right)-11\left(x+1\right)\left(x-4\right)}{x\left(x+1\right)\left(x-4\right)}=0$

$\Leftrightarrow9x^2-36x+2x^2+2x-11x^2+44x-11x+44=0$

$\Leftrightarrow-x=-44$

$\Leftrightarrow x=44\left(tm\right)$

$2,\left(đk:x\ne4\right)$

$\Leftrightarrow\dfrac{14}{3\left(x-4\right)}-\dfrac{2+x}{x-4}-\dfrac{3}{2\left(x-4\right)}+\dfrac{5}{6}=0$

$\Leftrightarrow\dfrac{14.2-6\left(2+x\right)-3.3+5\left(x-4\right)}{6\left(x-4\right)}=0$

$\Leftrightarrow28-12-6x-9+5x-20=0$

$\Leftrightarrow-x=13$

$\Leftrightarrow x=-13\left(tm\right)$

Đúng(2)

TA

Tuyet Anh Lai

17 tháng 1 2023

bn ơi ktra lại câu 2 giúp mk đc ko

TD

Thầy Đức Anh

Giáo viên VIP

27 tháng 4 2022

Tìm $x$, biết :
a) $\left(\dfrac{1}{2}+1,5\right) \cdot x=\dfrac{1}{5}$
b) $\left(-1 \dfrac{3}{5}+x\right): \dfrac{12}{13}=2 \dfrac{1}{6}$
c) $\left(x: 2 \dfrac{1}{3}\right) \cdot \dfrac{1}{7}=\dfrac{-3}{8}$
d) $\dfrac{-4}{7} \cdot x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1 \dfrac{2}{3}\right)$

13

YN

Yen Nhi

21 tháng 6 2022

$a)\left(\dfrac{1}{2}+1,5\right)x=\dfrac{1}{5}$

$\Rightarrow2x=\dfrac{1}{5}$

$\Rightarrow x=\dfrac{1}{10}$

$b)\left(-1\dfrac{3}{5}+x\right):\dfrac{12}{13}=2\dfrac{1}{6}$

$\Leftrightarrow-\dfrac{8}{5}+x=\dfrac{13}{6}.\dfrac{12}{13}$

$\Leftrightarrow-\dfrac{8}{5}+x=2$

$\Leftrightarrow x=\dfrac{18}{5}$

$c)\left(x:2\dfrac{1}{3}\right).\dfrac{1}{7}=-\dfrac{3}{8}$

$\Leftrightarrow x:\dfrac{7}{3}=-\dfrac{3}{8}:\dfrac{1}{7}$

$\Leftrightarrow x=-\dfrac{21}{8}.\dfrac{7}{3}$

$\Leftrightarrow x=-\dfrac{49}{8}$

$d)-\dfrac{4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1\dfrac{2}{3}\right)$

$\Leftrightarrow-\dfrac{4}{7}x+\dfrac{7}{5}=-\dfrac{3}{40}$

$\Leftrightarrow-\dfrac{4}{7}x=-\dfrac{59}{40}$

$\Leftrightarrow x=\dfrac{413}{160}$

T

TINH

13 tháng 7 2022

a) $\left(\dfrac{1}{2}+1,5\right) \cdot x=\dfrac{1}{5}$

$\cdot x=\dfrac{1}{5}$

$x=\dfrac{1}{5}: 2$

$x=\dfrac{1}{10}$
b) $\left(-1 \dfrac{3}{5}+x\right): \dfrac{12}{13}=2 \dfrac{1}{6}$

$\dfrac{3}{5}+x=\dfrac{13}{6} \cdot \dfrac{12}{13}$
$\dfrac{3}{5}$

$\dfrac{3}{5}$
c) $\left(x: 2 \dfrac{1}{3}\right) \cdot \dfrac{1}{7}=\dfrac{-3}{8}$

$\cdot \dfrac{3}{7} \cdot \dfrac{1}{7}=\dfrac{-3}{8}$

$x=\dfrac{-3}{8}: \dfrac{3}{49}$
$x=\dfrac{-49}{8}=-6 \dfrac{1}{8}$
d) $\dfrac{-4}{7} \cdot x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1 \dfrac{2}{3}\right)$

$\dfrac{-4}{7} x+\dfrac{7}{5}=\dfrac{1}{8} \cdot \dfrac{-3}{5}$
$-\dfrac{4}{7} x=\dfrac{-3}{40}-\dfrac{7}{5} \\ x=\dfrac{-59}{40}: \dfrac{-4}{7}=\dfrac{413}{160}=2 \dfrac{93}{160}$

Tìm x: a) $\dfrac{11}{12}$ - ($\dfrac{2}{5}$ + $\dfrac{3}{4}$x) $\dfrac{2}{3}$ b) $\dfrac{-2}{5}$ + $\dfrac{5}{3}$ . ($\dfrac{3}{2}$ - $\dfrac{4}{15}$x) = $\dfrac{-7}{6}$ c) $\dfrac{1}{2}$ + $\dfrac{3}{4}$x...

LP

Lê Phương Linh

29 tháng 9 2023

2

KT

『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』

29 tháng 9 2023

`#3107`

a)

$\dfrac{11}{12}-\left(\dfrac{2}{5}+\dfrac{3}{4}x\right)=\dfrac{2}{3}?\\ \Rightarrow\dfrac{2}{5}+\dfrac{3}{4}x=\dfrac{11}{12}-\dfrac{2}{3}\\ \Rightarrow\dfrac{2}{5}+\dfrac{3}{4}x=\dfrac{1}{4}\\ \Rightarrow\dfrac{3}{4}x=\dfrac{1}{4}-\dfrac{2}{5}\\ \Rightarrow\dfrac{3}{4}x=-\dfrac{3}{20}\\ \Rightarrow x=-\dfrac{3}{20}\div\dfrac{3}{4}\\ \Rightarrow x=-\dfrac{1}{5}$

Vậy, $x=-\dfrac{1}{5}$

b)

$\dfrac{-2}{5}+\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=\dfrac{-7}{6}\\ \Rightarrow\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=\dfrac{-7}{6}-\dfrac{-2}{5}\\ \Rightarrow\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=-\dfrac{23}{30}\\ \Rightarrow\dfrac{3}{2}-\dfrac{4}{15}x=-\dfrac{23}{30}\div\dfrac{5}{3}\\ \Rightarrow\dfrac{3}{2}-\dfrac{4}{15}x=-\dfrac{23}{50}\\ \Rightarrow\dfrac{4}{15}x=\dfrac{3}{2}-\left(-\dfrac{23}{50}\right)\\ \Rightarrow\dfrac{4}{15}x=\dfrac{49}{25}\\ \Rightarrow x=\dfrac{147}{20}$

Vậy, $x=\dfrac{147}{20}$

c)

$\dfrac{1}{2}+\dfrac{3}{4}x=\dfrac{1}{4}\\ \Rightarrow\dfrac{3}{4}x=\dfrac{1}{4}-\dfrac{1}{2}\\ \Rightarrow\dfrac{3}{4}x=-\dfrac{1}{4}\\ \Rightarrow x=-\dfrac{1}{4}\div\dfrac{3}{4}\\ \Rightarrow x=-\dfrac{1}{3}$

Vậy, $x=-\dfrac{1}{3}.$

$#Emyeu1aithatroi...$

Đúng(1)

TM

Trịnh Minh Trí

29 tháng 9 2023

(2/5 + 3/4 . x)= 11/12 -2/3

(2/5 +3/4 . x)= 1/4

3/4 . x = 1/4 - 2/5

3/4 . x = -3/20

x = -3/20 : 3/4

x = -1/5

Vậy .....