Question

[Hạ Hy]

viết phương trình biểu diễn sự chuyển hóa sau

Fe\(_2\)O\(_3\) \(\rightarrow\) \(_{\left(1\right)}\)FeCl\(_3\) \(\rightarrow\)\(_{\left(2\right)}\) Fe( NO\(_3\) )\(_3\) \(\rightarrow\)\(_{\left(3\right)}\) Fe(OH)\(_3\) \(\rightarrow\) \(_{\left(4\right)}\)Fe(SO\(_4\))\(_3\) \(\rightarrow\)\(_{\left(5\right)}\) BaSO\(_4\)

Answer 1

[Lê Thu Dương]

Fe2O3+6HCl--->2FeCl3+3H2O

FeCl3+3HNO3---->Fe(NO3)3+3HCl

Fe(NO3)3+ 3NaOH--->Fe(OH)3+3NaNO3

2Fe(OH)3+ 3H2SO4---->Fe2(SO4)3+6H2O

Fe2(SO4)3+3 BaCl2----->2FeCl3+3BaSO4

Answer 2

[B.Thị Anh Thơ]

\(1.\text{Fe2O3 + 6HCl → 3H2O + 2FeCl3}\)

\(2.\text{3AgNO3 + FeCl3 → 3AgCl + Fe(NO3)3}\)

\(3.\text{ 3Ba(OH)2 + 2Fe(NO3)3 → 3Ba(NO3)2 + 2Fe(OH)3 (kt) }\)

\(4.\text{3H2SO4 + 2Fe(OH)3 → Fe2(SO4)3 + 6H2O}\)

\(5.\text{3BaCl2 + Fe2(SO4)3 → 2FeCl3 + 3BaSO4}\)