2x3x4x6/2x3x4x8=?
giúp mình với nhé!nhanh lên ,mình đang vội.
Kamado Nezuko
K
Khách
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KY
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refer
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ảnh này bn lên mạng nha!!!
13 tháng 7 2021
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CR
14
19 tháng 4 2017
x+y+xy=40
x.(y+1)+y=40
x.(y+1)+y+1=41
(x+1).(y+1)=41
Vì 41 là số nguyên tố, x,y nguyên
Xảy ra 4 trường hợp:
TH1; x+1=41,y+1=1
=>x=40,y=0(chọn)
TH2: x+1=1,y+1=41
=>x=0,y=40(chọn)
TH3: x+1=-1,y+1=-41
=>x=-2,y=-42(chọn)
TH4:x+1=-41,y+1=-1
=>x=-41,y=-2
19 tháng 4 2017
x+y+xy=40=>x(1+y)+(y+1)=41=>(y+1)(x+1)=41
do x,y là số nguyên=>y+1 và x+1 cũng là số nguyên =>y+1;x+1 thuộc Ư(41)
sau đó bạn tự chia trường hợp nhé
Có 4 trường hợp
kết quả là (40;0) (0;40)(-42;-2)(-2;-42)
nhớ mình nha
CP
12 tháng 3 2017
ta thấy số nhỏ nhất chia hết 15 và 18 là 270 mà ta thấy số cần tìm cộng 7 chia hết 15 và 18 vậy số đó là 270 - 7 = 263
12 tháng 3 2017
chia số đó thành 15 và 18 phần =nhau.ta có giá trị 1 phần là:
9+8=17
số đó là:17x15+8=263
đs:263
BA
1
HN
1
S
19 tháng 2 2023
Ta có:
\(\dfrac{1}{4^2}< \dfrac{1}{3.4}\)
\(\dfrac{1}{5^2}< \dfrac{1}{4.5}\)
\(\dfrac{1}{6^2}< \dfrac{1}{5.6}\)
\(...\)
\(\dfrac{1}{100^2}< \dfrac{1}{99.100}\) \(\left(1\right)\)
\(\Rightarrow\dfrac{1}{4^2}+\dfrac{1}{5^2}+\dfrac{1}{6^2}+...+\dfrac{1}{100^2}< \dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+...+\dfrac{1}{99.100}\)
Đặt \(A=\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+...+\dfrac{1}{99.100}\)
\(=\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{99}-\dfrac{1}{100}\)
\(=\dfrac{1}{3}-\dfrac{1}{100}\)\(< \dfrac{1}{3}\) \(\left(2\right)\)
Từ \(\left(1\right)\) và \(\left(2\right)\)
\(\Rightarrow\dfrac{1}{4^2}+\dfrac{1}{5^2}+\dfrac{1}{6^2}+...+\dfrac{1}{100^2}< \dfrac{1}{3}\)
8 tháng 11 2016
211. cho a=45: b=204 :c=126 a) tim UCLN (a,b,c) b) tim BCNN(a,b )
8 tháng 11 2016
do la
211cho a =45;b=204;c=126
a)tim UCLN(a,b,c)
b)tim BCNN(a,b)
viet duoc the thoi
LP
12 tháng 1 2022
The children went jogging with their parents at the zoo.
12 tháng 1 2022
The children went jogging with their parents at the zoo
PM
3
\(\dfrac{2\times3\times4\times6}{2\times3\times4\times8}=\dfrac{2}{2}\times\dfrac{3}{3}\times\dfrac{4}{4}\times\dfrac{6}{8}\)
\(=1\times1\times1\times\dfrac{3}{4}=\dfrac{3}{4}\)
\(\dfrac{2\times3\times4\times6}{2\times3\times4\times8}=\dfrac{6}{8}=\dfrac{3}{4}\)