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(13x7+13x8):(29/3-y)=39
=>[13x(7+8)]:(29/3-y)=39
=>(13x15):(29/3-y)=39
=>195:(29/3-y)=39
=>29/3-y=195:39=5
=>y=29/3-5
=>y=29/3-15/3
=>y=13/3
(13 x 7 + 13 x 8) : (29/3 - y) = 39
=> [13 x (7 + 8)] : (29/3 - y) = 39
=> (13 x 15) : (29/3 - y) = 39
=>195 : (29/3 - y) = 39
=> 29/3 - y = 195 : 39 = 5
=> y = 29/3 - 5
=> y = 29/3 - 15/3
=> y = 13/3
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a, \(\dfrac{7}{8}\) \(\times\) \(\dfrac{3}{13}\) + \(\dfrac{4}{9}\) \(\times\) \(\dfrac{4}{13}\)
= \(\dfrac{1}{13}\) \(\times\)( \(\dfrac{21}{8}\) + \(\dfrac{16}{9}\))
= \(\dfrac{1}{13}\) \(\times\)( \(\dfrac{189}{72}\) + \(\dfrac{128}{72}\))
= \(\dfrac{1}{13}\) \(\times\) \(\dfrac{317}{73}\)
= \(\dfrac{317}{949}\)
b, \(\dfrac{6}{5}\) + \(\dfrac{7}{3}\) + \(\dfrac{8}{9}\)
= \(\dfrac{54}{45}\) + \(\dfrac{105}{45}\) + \(\dfrac{40}{45}\)
= \(\dfrac{199}{45}\)
c, 23 : \(\dfrac{5}{14}\) + \(\dfrac{6}{7}\) + \(\dfrac{4}{9}\)
= \(\dfrac{322}{5}\) + \(\dfrac{6}{7}\) + \(\dfrac{4}{9}\)
= \(\dfrac{20286}{315}\) + \(\dfrac{270}{315}\) + \(\dfrac{140}{315}\)
= \(\dfrac{20696}{315}\)
d, 4\(\dfrac{1}{4}\) + 7\(\dfrac{3}{7}\) - 2\(\dfrac{4}{17}\)
= 4 + \(\dfrac{1}{4}\) + 7 + \(\dfrac{3}{7}\) - 2 - \(\dfrac{4}{17}\)
= (4+7-2) + (\(\dfrac{1}{4}\) + \(\dfrac{3}{7}\) - \(\dfrac{4}{17}\))
= 9 + \(\dfrac{119}{476}\) + \(\dfrac{204}{476}\) - \(\dfrac{112}{476}\)
= 9\(\dfrac{211}{476}\) = \(\dfrac{4495}{476}\)
e, 8 - (9\(\dfrac{2}{11}\) + \(\dfrac{8}{33}\))
= 8 - 9 - \(\dfrac{2}{11}\) - \(\dfrac{8}{33}\)
= -1 - \(\dfrac{2}{11}\) - \(\dfrac{8}{33}\)
= \(\dfrac{-33}{33}\) - \(\dfrac{-6}{33}\) - \(\dfrac{8}{33}\)
= - \(\dfrac{47}{33}\)
Dấu \(.\)là dấu nhân
\(\left(7.13+8.13\right):\left(9\frac{2}{3}-y\right)=39\)
\(\Rightarrow13.\left(7+8\right):\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow13.15:\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow195:\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow\frac{29}{3}-y=195:39\)
\(\Rightarrow\frac{29}{3}-y=5\)
\(\Rightarrow y=\frac{29}{3}-5\)
\(\Rightarrow y=\frac{29}{3}-\frac{15}{3}\)
\(\Rightarrow y=\frac{14}{3}\)
Vậy \(y=\frac{14}{3}\)
~ Ủng hộ nhé .
P/s : Đúng nha