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\(a,2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(\Rightarrow x=23\)
\(b,2016-100\times\left(x+11\right)=128:8\)
\(2016-100\times\left(x+11\right)=16\)
\(100\times\left(x+11\right)=2016-16\)
\(100\times\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(\Rightarrow x=9\)
\(a,2448:\left[119-\left(x-6\right)\right]=24\\ 119-\left(x-6\right)=2448:24\\ 119-\left(x-6\right)=102\\ x-6=119-102\\ x-6=17\\ x=17+6\\ x=23\\ b,2016-100\times\left(x+11\right)=128:8\\ 2016-100\times\left(x+11\right)=16\\ 100\times\left(x+11\right)=2016-16\\ 100\times\left(x+11\right)=2000\\ x+11=2000:100\\ x+11=20\\ x=20-11\\ x=9\)
bài 2
a) 2448:[119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
a: x/3-1/6=1/5
=>x/3=11/30
hay x=11/90
b: =>1/2x=2
hay x=4
c: =>2/3:x=-7-1/3=-22/3
=>x=-1/11
\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(x=23\)( thỏa mãn \(x\in N\) )
vậy x = 23
\(2016-100\cdot\left(x+11\right)=2^7:2^3\)
\(2016-100\cdot\left(x+11\right)=128:8\)
\(2016-100\cdot\left(x+11\right)=16\)
\(100\cdot\left(x+11\right)=2016-16\)
\(100\cdot\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(x=9\)( thỏa mãn \(x\in N\))
vậy x = 9
Mình không chép lại đề nha
a)119-(x-6)=102
x-6 =17
x =23
b)(6x-39):7=3
6x-39 =21
6x =60
x =10
c, d bạn tự làm nha
a) (x+12)-20=0
x+12=20
x=8
b) 5.(x-7)=0
x-7=0
x=7
c) 12x-3x+1=937
12x-3x=936
9x=936
x=104
d) 2448 : [ 119 - ( x - 6 ) ] = 24
119-(x-6) = 102
x-6=17
x=23
a ) ( x + 12 ) - 20 = 0
x + 12 = 0 + 20
x +12 = 20
x = 20 - 12
x = 8
b ) 5 . ( x - 7 ) =0
x - 7 = 0 : 5
x - 7 = 0
x = 0 + 7
x = 7
a)
\(x+\left(x+2\right)+\left(x+4\right)+...+\left(x+98\right)=0\)
\(x+x+2+x+4+...+x+98=0\)
\(50x+\left(98+2\right).\left[\left(98-2\right):2+1\right]:2=0\)
\(50x+100.49:2=0\)
\(50x+49.50=0\)
\(50x=0-49.50\)
\(50x=-2450\)
\(x=-2450:50\)
\(x=-49\)
b)
\(\left(x-5\right)+\left(x-4\right)+\left(x-3\right)+...+\left(x+11\right)+\left(x+12\right)=99\)
\(x+x+x+...+x-5-4-3-...+11+12=99\)
\(18x+6+7\text{+ 8 + 9 + 10 + 11 + 12 = 99}\)
\(18x+63=99\)
\(18x=99-63\)
\(18x=36\)
\(x=36:18\)
\(x=2\)
Câu b,
= 50x + (1 + 3 + 5 + ..... + 99) = 2550
= 50x + 2500 = 2550
= 50x = 2550 - 2500
= 50x = 50
= x = 50 : 50
= x = 1
refer
A) 2448:[119-[x-6]]=24
<=> 199 - ( x-6 ) = 2448 : 24 = 102
<=> x - 6 = 199 - 102 = 97
<=> x = 97 +6 = 103
B) (x+1)+(x+3)+(x+5)+......+(x+99) = 2550
(x+x+x+....+x)+(1+3+5+....+99) = 2550
50x + 2500 = 2550
50x = 2550 - 2500
50x = 50
x = 50 : 50
x = 1