Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu 1 :
a) 8. ( \(-\frac{1}{2}\))2
= 8. \(\frac{1}{4}\)
= 2
b) 5,3 . 4,7 + (-1,7) . 5,3 - 5,9
= 5,3 . [4,7 + (-1,7)] - 5,9
= 5,3 . 3 - 5,9
= 15,9 - 5,9
= 10,9
c) \(\frac{2}{3} + (-\frac{1}{3}) + \frac{7}{15}\)
\(=\frac{1}{3} + \frac{7}{15}\)
\(= \frac{5}{15} + \frac{7}{15}\)
\(=\frac{12}{15}\)
d) 40 : {[11 + (26-33)]}
= 40 : {[11 + (26-27)]}
= 40 : {[11 + (-1)]}
= 40 : 10
= 4
\(=\dfrac{10}{15}+\dfrac{-5}{15}+\dfrac{7}{15}=\dfrac{12}{15}=\dfrac{4}{5}\)
a,(-5,3)+(-0,7)+5,3
=(-5,3+-0,7)+5,3
=-6+5,3
=-0,7
b, 5,3+(-10)+3,1+4,7
=(5,3+4,7)+(-10)+3,1
=10+(-)+3,1
=0+3,1
=3,1
c, (-4,1)+(-13,7)+(3,1)+(-5,9)+(-6,3)
=(-4,1+-5,9)+(-13,7+-6,3)+-3,1
=(-10). +(-20). +-3,1
=(-30). +-3,1
=33,1
\(a,\dfrac{15^3}{5^4}\)
\(=\dfrac{\left(3\cdot5\right)^3}{5^4}\)
\(=\dfrac{3^3\cdot5^3}{5^4}\)
\(=\dfrac{3^3}{5}\)
\(=\dfrac{27}{5}\)
\(---\)
\(b,\dfrac{21^3}{7^4}\)
\(=\dfrac{\left(3\cdot7\right)^3}{7^4}\)
\(=\dfrac{3^3\cdot7^3}{7^4}\)
\(=\dfrac{3^3}{7}\)
\(=\dfrac{27}{7}\)
\(---\)
\(c,\dfrac{6^6}{3^8}\)
\(=\dfrac{\left(2\cdot3\right)^6}{3^8}\)
\(=\dfrac{2^6\cdot3^6}{3^8}\)
\(=\dfrac{2^6}{3^2}\)
\(=\dfrac{64}{9}\)
#\(Toru\)
\(a.\dfrac{-42}{12}+\dfrac{9}{12}-\dfrac{17}{12}=-\dfrac{25}{6}\)
\(b.-\dfrac{1}{12}-\dfrac{5}{4}+\dfrac{1}{3}=-\dfrac{1}{12}-\dfrac{15}{12}+\dfrac{4}{12}=-1\)
a) \(\dfrac{-7}{2}+\dfrac{3}{4}-\dfrac{17}{12}=\dfrac{-42}{12}+\dfrac{9}{12}-\dfrac{17}{12}=\dfrac{-42+9-17}{12}=-\dfrac{50}{12}=-\dfrac{25}{6}\)
b)\(-\dfrac{1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)=-\dfrac{1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)=-\dfrac{2}{24}-\left(\dfrac{63}{24}-\dfrac{8}{24}\right)\)
\(=-\dfrac{2}{24}-\dfrac{63}{24}+\dfrac{8}{24}=-\dfrac{57}{24}=-\dfrac{19}{8}\)
a) 9/18 - (-7/12) + 13/32
= 13/12 + 13/32
= 143/96
b) (5/-8) + 14/25 - 6/10
= (-13/200) - 6/10
= -133/200
Chúc bạn học tốt!! ^^
a: \(\dfrac{9}{18}-\dfrac{-7}{12}+\dfrac{13}{32}\)
\(=\dfrac{1}{2}+\dfrac{7}{12}+\dfrac{13}{32}\)
\(=\dfrac{48}{96}+\dfrac{56}{96}+\dfrac{39}{96}\)
\(=\dfrac{143}{96}\)
b: \(\dfrac{-5}{8}+\dfrac{14}{25}-\dfrac{6}{10}\)
\(=\dfrac{-125}{200}+\dfrac{112}{200}-\dfrac{120}{200}\)
\(=\dfrac{-133}{200}\)
\(a.5,3.4,7+\left(-17\right).5,3-5,9\)
\(=5,3.\left[4,7+\left(-17\right)\right]-5,9\)
\(=5,3.\left(-12,3\right)-5,9\)
\(=-65,19-5,9=-71,09\)
\(b.\dfrac{2}{3}+\dfrac{-1}{3}+\dfrac{7}{15}=\dfrac{10}{15}+\dfrac{-5}{15}+\dfrac{7}{15}=\dfrac{12}{15}=\dfrac{4}{5}\)
a) 5,3.4,7+(−1,7).5,3−5,95,3.4,7+(−1,7).5,3−5,9
=5,3.(4,7−1,7)−5,9=5,3.(4,7−1,7)−5,9
=5,3.3−5,9=5,3.3−5,9
=15,9−5,9=10=15,9−5,9=10
b) 23+−13+71532+3−1+157
=2+(−1)3+715=32+(−1)+157
=5+715=1215=45=155+7=1512=54.