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a) \(\frac{28\times7-45\times7+7\times18}{45\times14}\)
\(=\frac{7\left(28-45+7\right)}{45\times14}\)
\(=\frac{7\times\left(-10\right)}{45\times14}=\frac{-1}{9}\)
b) \(\frac{12.3-2.6}{4.5.6}\)
\(=\frac{2.6.3-2.6}{4.5.6}\)
\(=\frac{2.6\left(3-1\right)}{2.2.5.6}\)
\(=\frac{2.6.2}{2.2.5.6}\)\(=\frac{1}{5}\)
A = ( - a - b + c ) - ( - a - b - c )
= - a - b + c + a + b + c
= 2c
Vậy A = 2c
k mk nha
bài đầu mk làm nhầm nha
A = ( - a - b + c ) - ( - a - b - c )
A = - a - b + c + a + b + c
A = 0
Vậy A = 0
k mk nha
thank you very much
a)
\(\dfrac{6}{13}\cdot\dfrac{8}{7}\cdot\dfrac{-26}{3}\cdot\dfrac{-7}{8}\)
\(=\dfrac{6}{13}\cdot\dfrac{-26}{3}\cdot\dfrac{8}{7}\cdot\dfrac{-7}{8}\)
\(=-4\cdot\left(-1\right)\\ =4\)
b)
\(\dfrac{6}{11}+\dfrac{11}{3}\cdot\dfrac{3}{22}\)
\(=\dfrac{6}{11}+\dfrac{1}{2}\\ =\dfrac{12}{22}+\dfrac{11}{22}\\ =\dfrac{23}{22}\)
2(b-c)+3(c-a)-4(a-b)
=2b-2c+3c-3a-(4a-4b)
=2b-2c+3c-3a-4a+4b
=a(3-4)+b(2+4)+c(3-2)
=(-1).a+6b+c.1=-a+6b+c=6b+c-a
Nếu sai thì báo nhé!
\(A=1+\frac{2^2}{3^2}+\frac{2^2}{5^2}+\frac{2^2}{7^2}+...+\frac{2^2}{2009^2}\)
\(A=1+2^2\left(\frac{1}{3^2}+\frac{1}{5^2}+\frac{1}{7^2}+..+\frac{1}{2009^2}\right)\)
Ta có: \(\frac{1}{3^2}< \frac{1}{1.3};\frac{1}{5^2}< \frac{1}{3.5};\frac{1}{7^2}< \frac{1}{5.7};...;\frac{1}{2009^2}< \frac{1}{2007.2009}\)
\(\Rightarrow A< 1+4\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+..+\frac{1}{2007.2009}\right)\)
\(=1+4\cdot\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2007}-\frac{1}{2009}\right)\)
\(=1+2\left(1-\frac{1}{2009}\right)=3-\frac{2}{2009}< 3\)
\(\Rightarrow A< 3\)
\(A=19\frac{1}{4}+\frac{1}{2}\times2\frac{1}{3}+5,75-\frac{1}{6}+74\)
MK GHI ĐẦY ĐỦ RA RÙI, BẠN TỰ BẤM MÁY TÍNH LÀM NHA ( MÌNH LƯỜI )
\(A=19\frac{1}{4}+\frac{1}{2}\times2\frac{1}{3}+5,75-\frac{1}{6}+74\)
\(A=\frac{77}{4}+\frac{1}{2}\times\frac{7}{3}+\frac{23}{4}-\frac{1}{6}+74\)
\(A=\frac{77}{4}+\frac{7}{6}+\frac{23}{4}-\frac{1}{6}+74\)
\(A=(\frac{77}{4}+\frac{23}{4})+(\frac{7}{6}-\frac{1}{6})+74\)
\(A=25+1+74\)
\(A=26+74\)
\(A=100\)
a, A = \(\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}=\frac{a^2\left(a+1\right)+\left(a+1\right)\left(a-1\right)}{a^2\left(a+1\right)+a\left(a+1\right)+\left(a+1\right)}=\frac{\left(a+1\right)\left(a^2+a-1\right)}{\left(a+1\right)\left(a^2+a+1\right)}=\frac{a^2+a-1}{a^2+a+1}\)
b, Gọi UCLN(a2 + a - 1,a2 + a + 1) là d
Ta có: a2 + a - 1 \(⋮\)d
a2 + a + 1 \(⋮\)d
=> (a2 + a - 1) - (a2 + a + 1) \(⋮\)d
=> 2 \(⋮\)d => d = {1;-1;2;-2}
Mà a2 + a - 1 = a(a + 1) - 1 lẻ => d lẻ => d không thể bằng 2;-2 => d = {1;-1}
Vậy A tối giản
\(S=1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^n}\)
\(\Rightarrow3S=3+1+\frac{1}{3}+...+\frac{1}{3^{n-1}}\)
\(\Rightarrow3S-S=3-\frac{1}{3^n}\)
\(\Rightarrow2S=\frac{3^{n+1}-1}{3^n}\)
\(\Rightarrow S=\frac{3^{n+1}-1}{2\cdot3^n}\)
\(3A=3+3^2+3^3+...+3^7\)
\(3A-A=3+3^2+3^3+...+3^7-1-3-3^2-...-3^6\)
\(2A=3^7-1\)
\(A=\frac{3^7-1}{2}\)
Chúc em học tốt^^
\(A=1+3+3^2+...+3^6\)
\(3A=3+3^2+3^3+...+3^7\)
\(3A-A=\left(3+3^2+3^3+...+3^7\right)-\left(1+3+3^2+...+3^6\right)\)
\(2A=3^7-1=2186\)
\(A=1093\)